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CUET 2025 Biology Question Paper with Answers & Solutions

50 questions with answer key & explanations

Q1.
Which one of the following guides the entry of the pollen tube into the embryo sac?
A. Antipodal Cells
B. Filiform apparatus
C. Micropyle
D. Synergids
Show answer & explanation

Correct answer: B

The filiform apparatus is a special cellular thickening at the micropylar tip of the synergids. It guides the entry of the pollen tube into the synergid (and thus into the embryo sac) by producing chemical guidance cues.

Q2.
Antibody molecule has:
A. Two peptide chain
B. Three peptide chain
C. Four peptide chain
D. One polypeptide chain
Show answer & explanation

Correct answer: C

An antibody (immunoglobulin) has the structure H2L2: two identical heavy (H) chains and two identical light (L) chains, i.e., four peptide chains in total.

Q3.
Choose the correct equation from the following options to show correct relationship between Gross Primary Productivity (GPP), Respirational Losses (R) and Net Primary Productivity (NPP).
A. GPP = R / (NPP)$^2$
B. GPP = 2NPP+R
C. GPP= NPP-R
D. GPP-R = NPP
Show answer & explanation

Correct answer: D

NPP = GPP - R, which rearranges to $GPP - R = NPP$. NPP is the biomass available after subtracting respiratory losses from gross primary productivity.

Q4.
Match List-I with List-II List-I (Disease): (A) Malaria, (B) Filariasis, (C) Ringworms, (D) Amoebiasis List-II (Characteristic symptoms): (I) Inflammation of lower limb, (II) Cycles of fever, (III) Blood clots and excess mucus in stools, (IV) Scaly lesions on nails Choose the correct answer from the options given below:
A. (A) - (IV), (B) - (II), (C) - (III), (D) - (I)
B. (A) - (I), (B) - (III), (C) - (II), (D) - (IV)
C. (A) - (II), (B) - (I), (C) - (IV), (D) - (III)
D. (A) - (III), (B) - (IV), (C) - (I), (D) - (II)
Show answer & explanation

Correct answer: C

Malaria - cycles of fever (II); Filariasis - inflammation/swelling of lower limbs (I); Ringworm - scaly lesions on skin/nails (IV); Amoebiasis - blood clots and mucus in stools (III). Matches option C.

Q5.
Match List-I to List-II List-I (Producer): (A) Clostridium butylicum, (B) Aspergillus niger, (C) Acetobacter aceti, (D) Lactobacillus List-II (Acid): (I) Lactic acid, (II) Butyric acid, (III) Citric acid, (IV) Acetic acid Choose the correct options
A. (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
B. (A) - (II), (B) - (III), (C) - (IV), (D) - (I)
C. (A) - (III), (B) - (II), (C) - (IV), (D) - (I)
D. (A) - (III), (B) - (IV), (C) - (I), (D) - (II)
Show answer & explanation

Correct answer: B

Clostridium butylicum - butyric acid (II); Aspergillus niger - citric acid (III); Acetobacter aceti - acetic acid (IV); Lactobacillus - lactic acid (I). Matches option B.

Q6.
Which one of the following is opposite part of micropylar end of ovule.
A. Hilum
B. Chalaza
C. Funicle
D. Nucellus
Show answer & explanation

Correct answer: B

The chalaza is the basal part of the ovule located opposite the micropylar end, where the integuments and nucellus join the funicle.

Q7.
Match List I with List II List I (Technique / term): (A) Amniocentesis, (B) Maternal mortality rate, (C) Vasectomy, (D) Tubectomy List II (Features): (I) Ligation of fallopian tube, (II) Ligation of vas deferens, (III) Death rate, (IV) Testing of sex Choose the correct options:
A. (A) - (I), (B) - (II), (C) - (III), (D) - (IV)
B. (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
C. (A) - (III), (B) - (IV), (C) - (II), (D) - (I)
D. (A) - (II), (B) - (I), (C) - (III), (D) - (IV)
Show answer & explanation

Correct answer: B

Amniocentesis - testing of sex/foetal disorders (IV); Maternal mortality rate - death rate (III); Vasectomy - ligation of vas deferens (II); Tubectomy - ligation of fallopian tube (I). Matches option B.

Q8.
Which type of innate Immunity is exhibited by interferons secreted by virus infected cells to protect non infected cells?
A. Physical barriers
B. Cytokine barriers
C. Physiological barriers
D. Cellular barriers
Show answer & explanation

Correct answer: B

Interferons are cytokines secreted by virus-infected cells that protect surrounding non-infected cells; this represents the cytokine barrier of innate immunity (NCERT).

Q9.
The process of copying genetic information from one strand of DNA into RNA is termed as -
A. Replication
B. Translation
C. Transcription
D. Regulation
Show answer & explanation

Correct answer: C

Transcription is the process of copying genetic information from the template strand of DNA into RNA.

Q10.
Arrange the following events in the correct order pertaining to fertilization in the human reproductive system. (A) The blastocyst becomes embedded in the endometrium. (B) Finger-like projections appear on the trophoblast called chorionic villi. (C) The blastomeres are arranged into trophoblast and the inner cell mass. (D) The zygote divides miotically and transforms into an embryo with 8-16 blastomeres, called a morula. Choose the correct answer from the options given below.
A. (D), (C), (A), (B)
B. (A), (C), (B), (D)
C. (B), (A), (D), (C)
D. (C), (B), (D), (A)
Show answer & explanation

Correct answer: A

Order: morula forms (D), then blastomeres arrange into trophoblast and inner cell mass forming blastocyst (C), blastocyst implants in endometrium (A), then chorionic villi appear (B). Sequence D, C, A, B = option A.

Q11.
Which of the following are not involved in intra uterine devices? (A) Lippes Loop (B) LNG-20 (C) Saheli (D) Implants Choose the correct answer from the options given below:
A. (A), (B) and (D) only
B. (C) and (D) only
C. (A), (B), (C) and (D)
D. (B), (C) and (D) only
Show answer & explanation

Correct answer: B

IUDs include Lippes Loop and hormone-releasing LNG-20. Saheli is an oral contraceptive pill and Implants are subdermal hormone implants, so (C) and (D) are NOT IUDs. Option B.

Q12.
Match the List-I with List-II List-I (Character): (A) Flower Colour, (B) Seed colour, (C) Pod colour, (D) Pod shape List-II (Recessive Trait): (I) Green, (II) Yellow, (III) Constricted, (IV) White Choose the correct answer from the options given below:
A. (A) - (II), (B) - (IV), (C) - (I), (D) - (III)
B. (A) - (I), (B) - (IV), (C) - (II), (D) - (III)
C. (A) - (I), (B) - (II), (C) - (IV), (D) - (III)
D. (A) - (IV), (B) - (I), (C) - (II), (D) - (III)
Show answer & explanation

Correct answer: D

Recessive traits in Mendel's pea: Flower colour - white (IV); Seed colour - green (I); Pod colour - yellow (II); Pod shape - constricted (III). Matches option D.

Q13.
Which one of the following is not associated with the process of transcription in bacteria?
A. Rho factor
B. Methyl guanosine triphosphate
C. Sigma factor
D. DNA dependent RNA polymerase
Show answer & explanation

Correct answer: B

Methyl guanosine triphosphate is the 5' cap added during eukaryotic mRNA processing, not bacterial transcription. Rho factor (termination), sigma factor (initiation), and DNA-dependent RNA polymerase are all part of bacterial transcription.

Q14.
Which of the following disorders are the results of aneuploidy? (A) Haemophilia (B) Down's Syndrome (C) Thalassemia (D) Turner's Syndrome Choose the correct answer from the options given below:
A. (B) and (D) only
B. (A), (B) and (C) only
C. (A), (B), (C) and (D)
D. (A) and (C) only
Show answer & explanation

Correct answer: A

Aneuploidy is gain/loss of chromosomes. Down's syndrome (trisomy 21) and Turner's syndrome (XO, monosomy) are aneuploidies. Haemophilia and thalassemia are gene mutations, not aneuploidies. Option A.

Q15.
Which one of the following options will express intermediate skin colour in an individual?
A. AABBCC
B. aabbcc
C. AaBbCc
D. aaBbcc
Show answer & explanation

Correct answer: C

Skin colour is polygenic. AaBbCc has three dominant (dark) alleles out of six, giving an intermediate skin colour. AABBCC is darkest, aabbcc is lightest.

Q16.
Match List-I with List-II List-I (Name of the gene): (A) 'i', (B) 'z', (C) 'y', (D) 'a' List-II (Encodes): (I) Permease, (II) Repressor, (III) Transacetylase, (IV) β- Galactosidase Choose the correct answer from the options given below:
A. (A) - (IV), (B) - (II), (C) - (III), (D) - (I)
B. (A) - (I), (B) - (III), (C) - (II), (D) - (IV)
C. (A) - (II), (B) - (IV), (C) - (I), (D) - (III)
D. (A) - (III), (B) - (IV), (C) - (I), (D) - (II)
Show answer & explanation

Correct answer: C

In the lac operon: i gene - repressor (II); z gene - beta-galactosidase (IV); y gene - permease (I); a gene - transacetylase (III). Matches option C.

Q17.
Which of the following is incorrect with reference to drug abuse?
A. Cannabinoids affect cardiovascular system of the body.
B. Heroin is extracted from the latex of Papaver somniferum.
C. Nicotine is a very effective sedative and pain killer.
D. Excessive dosage of coca alkaloid causes hallucinations.
Show answer & explanation

Correct answer: C

Nicotine stimulates the adrenal gland to release adrenaline and noradrenaline; it is a stimulant, not a sedative/pain killer (those are opioids like morphine). So statement C is incorrect.

Q18.
Arrange the given steps involved in gel electrophoresis used for separation of DNA fragments ? (A) Exposure to UV light (B) Staining with ethidium bromide (C) Moving of DNA fragments towards anode (D) Elution Choose the correct options given below
A. (A), (B), (C), (D)
B. (B), (A), (D), (C)
C. (A), (D), (B), (C)
D. (C), (B), (A), (D)
Show answer & explanation

Correct answer: D

DNA fragments move towards anode (C), gel is stained with ethidium bromide (B), exposed to UV light to visualise bands (A), and the desired fragments are cut out and eluted (D). Sequence C, B, A, D = option D.

Q19.
Match List-I with List-II List-I (Product): (A) Citric Acid, (B) Ethanol, (C) Statins, (D) Cyclosporin A List-II (Producer): (I) Trichoderma polysporum, (II) Monascus purpureus, (III) Sachharomyces cerevisiae, (IV) Aspergillus niger Choose the correct answer from the options given below:
A. (A) - (IV), (B) - (III), (C) - (II), (D) - (I)
B. (A) - (I), (B) - (III), (C) - (II), (D) - (IV)
C. (A) - (I), (B) - (II), (C) - (IV), (D) - (III)
D. (A) - (III), (B) - (IV), (C) - (I), (D) - (II)
Show answer & explanation

Correct answer: A

Citric acid - Aspergillus niger (IV); Ethanol - Saccharomyces cerevisiae (III); Statins - Monascus purpureus (II); Cyclosporin A - Trichoderma polysporum (I). Matches option A.

Q20.
EcoRI, a significant tool in rDNA technology is -
A. Bacteria
B. Plasmid
C. Enzyme
D. Purine
Show answer & explanation

Correct answer: C

EcoRI is a restriction endonuclease, i.e., an enzyme used to cut DNA at specific recognition sequences in recombinant DNA technology.

Q21.
Arrange the following geological periods in their occurrence from latest to oldest order. (A) Triassic (B) Carboniferous (C) Tertiary (D) Jurassic Choose the correct answer from the options given below:
A. (D), (B), (C), (A)
B. (A), (B), (D),(C)
C. (B), (A), (D), (C)
D. (C), (D), (A), (B)
Show answer & explanation

Correct answer: D

From latest (most recent) to oldest: Tertiary (most recent), Jurassic, Triassic, Carboniferous (oldest). Sequence C, D, A, B = option D.

Q22.
Which of the following steps are related to polymerase chain reaction (PCR)? (A) Extension (B) Annealing (C) Propagation (D) Denaturation Choose the correct answer from the options given below:
A. (A), (B) and (D) only
B. (A), (B) and (C) only
C. (A), (B), (C) and (D)
D. (B), (C) and (D) only
Show answer & explanation

Correct answer: A

The three steps of PCR are denaturation, annealing (primer binding), and extension. Propagation is not a PCR step. So (A), (B) and (D) only = option A.

Q23.
Baculoviruses are pathogens that attack :
A. Insects
B. Roundworms
C. Molluscs
D. Birds
Show answer & explanation

Correct answer: A

Baculoviruses (genus Nucleopolyhedrovirus) are pathogens that attack insects and other arthropods, used as biocontrol agents.

Q24.
The number of individuals in the reproductive age group is more than the number of individuals in the pre-reproductive age group, the shape of its age pyramid would reflect the growth status of the population as:
A. Expanding
B. Stable
C. Declining
D. Homeostasis
Show answer & explanation

Correct answer: C

When reproductive age individuals exceed pre-reproductive individuals (narrow base), the population has fewer young to replace, indicating a declining population age pyramid.

Q25.
Which of the following statements are true with reference to homology or homologous organs? (A) Homology indicates common ancestry. (B) Whale and Cheetah share similarities in the pattern of the bones of the forelimbs. (C) Vertebrate heart is an example of homologous organs. (D) Thorn of Bougainvillea and tendrils of cucurbita represent homology. Choose the correct answer from the options given below:
A. (A), (B) and (D) only
B. (A), (B) and (C) only
C. (A), (B), (C) and (D)
D. (B), (C) and (D) only
Show answer & explanation

Correct answer: C

All four are correct: homology indicates common ancestry; whale and cheetah forelimb bones share the same pattern; vertebrate heart/brain are homologous; Bougainvillea thorn and Cucurbita tendril are homologous (both stem modifications). Option C.

Q26.
Arrange the following groups of plants according to their appearance on earth. (A) Angiosperms (B) Seed ferns (C) Rhynia type plants (D) Psilophyton Choose the correct answer from the options given below:
A. (C), (D), (B), (A)
B. (A), (C), (B), (D)
C. (B), (A), (D), (C)
D. (C), (B), (D), (A)
Show answer & explanation

Correct answer: A

Order of appearance (earliest to latest): Rhynia type plants (early vascular), Psilophyton, Seed ferns, then Angiosperms (most recent). Sequence C, D, B, A = option A.

Q27.
If a man is eating fish as his food, which trophic level is occupied by him in the food chain?
A. First
B. Second
C. Third
D. Fourth
Show answer & explanation

Correct answer: D

Food chain: phytoplankton/plants (T1) -> zooplankton/herbivore (T2) -> small fish/carnivore (T3) -> man eating fish (T4). Man occupies the fourth trophic level.

Q28.
Thorn of Bougainvillea and tendril of Cucurbita are:
A. Homologous structures
B. Analogous structures
C. Vestigial structures
D. Developing structures
Show answer & explanation

Correct answer: A

Both the thorn of Bougainvillea and the tendril of Cucurbita are modifications of the stem (axillary bud), having a common origin but different functions; hence they are homologous structures.

Q29.
A small standing crop of phytoplankton supports a large standing crop of zooplankton. This can be correctly represented by:
A. Inverted pyramid of energy
B. Inverted pyramid of biomass
C. Upright pyramid of biomass
D. Sometimes upright and sometimes inverted pyramid of energy
Show answer & explanation

Correct answer: B

In aquatic ecosystems, a small biomass of phytoplankton supports a larger biomass of zooplankton, giving an inverted pyramid of biomass. The pyramid of energy is always upright.

Q30.
The first isolated restriction endonuclease was:
A. Hind II
B. EcoR I
C. BamH I
D. Pvu II
Show answer & explanation

Correct answer: A

Hind II was the first restriction endonuclease to be isolated and characterised; it always cuts DNA at a specific point within a particular sequence of six base pairs.

Q31.
Arrange the given products formed during sewage treatment in correct sequence ? (A) Biogas (B) Activated sludge (C) Flocs (D) Primary sludge Choose the correct options given below
A. (A), (B), (C), (D)
B. (D), (C), (B), (A)
C. (C), (D), (B), (A)
D. (B), (A), (D), (C)
Show answer & explanation

Correct answer: B

Sequence: primary treatment yields primary sludge (D); secondary treatment forms flocs (C) which settle as activated sludge (B); anaerobic digestion of sludge produces biogas (A). Sequence D, C, B, A = option B.

Q32.
Wildlife safari parks are example of-
A. Ex situ Conservation
B. In situ conservation
C. Biodiversity hot spots
D. Sacred grooves
Show answer & explanation

Correct answer: A

Wildlife safari parks, like zoos and botanical gardens, conserve organisms outside their natural habitat, so they are examples of ex situ conservation.

Q33.
Humification leads to :
A. Soil erosion
B. Soil conservation
C. Accumulation of humus
D. Accumulation of salts
Show answer & explanation

Correct answer: C

Humification is the process during decomposition that leads to the formation and accumulation of humus, a dark amorphous substance resistant to microbial action.

Q34.
If a double-stranded DNA has 15% of adenine, find out the percent of cytosine in the DNA ?
A. 15%
B. 30%
C. 35%
D. 85%
Show answer & explanation

Correct answer: C

By Chargaff's rule, $A=T$ and $G=C$. If $A=15\%$ then $T=15\%$, so $A+T=30\%$. Remaining $G+C=70\%$, hence $C=70/2=35\%$.

Q35.
Transgenic animals are used to understand the contribution of genes in the development of diseases such as:
A. Cholera and typhoid
B. Elephantiasis and ringworm
C. Cancer and cystic fibrosis
D. Pneumonia and kala-azar
Show answer & explanation

Correct answer: C

NCERT: transgenic animals are used as models to study how genes contribute to diseases such as cancer, cystic fibrosis, rheumatoid arthritis and Alzheimer's.

Q36.
Genetically modified plants have been useful in:
A. Increasing post harvest losses
B. Decreasing crop yield
C. Making crops tolerant to stresses.
D. Decreasing efficiency of mineral usage by plants
Show answer & explanation

Correct answer: C

GM plants are useful in making crops more tolerant to abiotic stresses (cold, drought, salt, heat), reducing post-harvest losses, increasing yield and improving mineral use efficiency. Correct option is making crops tolerant to stresses.

Q37.
Which of the following is the primary female sex organ?
A. Mammary glands
B. Uterus
C. Ovaries
D. Cervix
Show answer & explanation

Correct answer: C

The ovaries are the primary female sex organs, producing the female gametes (ova) and hormones (estrogen, progesterone). The rest are accessory/secondary organs.

Q38.
Which one of the following structure is haploid (n) in relation to male reproductive system?
A. Secondary spermatocytes
B. Primary spermatocytes
C. Leydig cells
D. Sertoli cells
Show answer & explanation

Correct answer: A

Secondary spermatocytes are formed after meiosis I and are haploid (n). Primary spermatocytes, Leydig cells and Sertoli cells are all diploid (2n).

Q39.
Of the incident solar radiation, what is the percentage of photosynthetically active radiation (PAR)?
A. 100%
B. Less than 50%
C. 1-5%
D. 2-10%
Show answer & explanation

Correct answer: B

NCERT: of the incident solar radiation, less than 50% is photosynthetically active radiation (PAR); plants capture only 2-10% of PAR.

Q40.
ELISA is based on the principle of -
A. Antigen - antibody interaction
B. PCR
C. Radioactive molecule
D. Amount of DNA
Show answer & explanation

Correct answer: A

ELISA (Enzyme-Linked Immuno-Sorbent Assay) is based on the principle of antigen-antibody interaction, used to detect infections such as HIV.

Species diversity on earth is not uniformly distributed. It is generally highest in the tropics and decreases towards the poles. Earth's fossil history reveals the incidences of mass extinctions in the past. Earth's rich biodiversity is vital for the very survival of mankind. It is believed that communities with high diversity tend to be less variable and more productive. The reasons of conserving biodiversity are narrowly utilitarian, broadly utilitarian and ethical. Biodiversity conservation may be in situ as well as ex-situ.
Q41.
Which of the following is not included in in-situ conservation?
A. Zoological park
B. National park
C. Wild life sanctuary
D. Biosphere reserves
Show answer & explanation

Correct answer: A

National parks, wildlife sanctuaries and biosphere reserves are in situ conservation. A zoological park (zoo) conserves organisms outside their natural habitat, so it is ex situ, not in situ.

Q42.
Which one of the following does not exhibit narrowly utilitarian argument for conserving biodiversity?
A. Construction materials
B. Pollination
C. Industrial products
D. Medicines
Show answer & explanation

Correct answer: B

Narrowly utilitarian arguments are direct economic benefits like food, medicines, construction materials and industrial products. Pollination is an ecosystem service - a broadly utilitarian argument, not narrowly utilitarian.

Q43.
Which of the following might not account for the greater biological diversity in the tropic region?
A. Frequent glaciations in the past
B. More solar energy available
C. Less seasonal and more constant and predictable
D. Undisturbed for million of years
Show answer & explanation

Correct answer: A

Tropics had no frequent glaciations; they remained relatively undisturbed for millions of years, had more solar energy and constant climate. 'Frequent glaciations in the past' does NOT account for tropical diversity.

Q44.
How many episodes of mass extinction of species have occurred since the origin and diversification of life on earth?
A. Two
B. Three
C. Five
D. Seven
Show answer & explanation

Correct answer: C

NCERT states there have been five episodes of mass extinction of species in Earth's history (the sixth, current one being human-driven).

Q45.
Which of the following hot spots does not cover India's biodiversity regions?
A. Western Ghats-Sri Lanka
B. Amazon forests
C. Indo-Burma
D. Himalaya
Show answer & explanation

Correct answer: B

India's biodiversity hotspots are Western Ghats-Sri Lanka, Indo-Burma and Himalaya. The Amazon forests of South America are not an Indian hotspot.

Pollen pistil interaction involves all events from the landing of pollen grains on the stigma until the pollen tube enters the embryo sac (when the pollen is compatible). When a pollen tube grows through the style and enters into the ovules, it finally discharges two male gametes in one of the synergids. Syngamy and triple fusion are two fusion events occur in angiosperms. Thus, angiosperms exhibit double fertilization. The products of these fusions are the diploid zygote and triploid primary endosperm nucleus. Zygote develops into embryo and primary endosperm cell forms the endosperm tissue. The developing embryo passes through different stages before maturation.
Q46.
With reference to reproduction in flowering plants, which one of the following is incorrect ?
A. Endosperm develops into seed
B. Ovary develops into fruit
C. Ploidy of PEN is 3n
D. Syngamy is the fusion of male and female gamete
Show answer & explanation

Correct answer: A

The ovule (not the endosperm) develops into the seed; endosperm only provides nourishment. So statement A is incorrect. B, C and D are correct.

Q47.
Which of the following is not a stage of growing embryo in dicotyledon plants?
A. Heart-shaped
B. Globular
C. Proembryo
D. Epiblast
Show answer & explanation

Correct answer: D

Dicot embryo stages are proembryo, globular, heart-shaped and mature embryo. Epiblast is a vestigial structure in monocot (grass) embryos, not a stage of dicot embryo development.

Q48.
The coconut water from tender coconut, a good source of nutrition is nothing but:
A. Free-nuclear endosperm
B. Synergids
C. Antipodal cells
D. Scutellum
Show answer & explanation

Correct answer: A

Coconut water is the free-nuclear endosperm (liquid syncytial endosperm), while the surrounding white kernel is the cellular endosperm.

Q49.
Formation of diploid zygot is a result of :
A. Emasculation
B. Triple fusion
C. Syngamy
D. Bagging
Show answer & explanation

Correct answer: C

Syngamy is the fusion of one male gamete with the egg cell to form the diploid (2n) zygote. Triple fusion forms the triploid PEN.

Q50.
If there are 38 chromosomes in the zygote, how many chromosomes will be there in its haploid egg cell?
A. 38
B. 57
C. 19
D. 76
Show answer & explanation

Correct answer: C

Zygote is diploid (2n) = 38, so $n = 38/2 = 19$. The haploid egg cell has 19 chromosomes.

Original question paper source: National Testing Agency (NTA), CUET (UG) 2025. Reproduced for educational use. Answers & explanations by UniDrill.