📌 Snapshot
- Why dough rises and muscles burn: glycolysis, the Krebs cycle and the electron transport chain explained.
- Every step with its site, enzyme and ATP, NADH and FADH2 count, plus the 38 ATP balance sheet built from scratch.
- Fermentation versus aerobic respiration, the amphibolic pathway and respiratory quotient values for each substrate.
- Exam traps, a one minute revision table and practice MCQs on enzymes, ETS complexes and ATP arithmetic.
📖 Detailed Notes
Written and reviewed by Anjali Sharma, Biology faculty at UniDrill (M.Sc. Botany, Banaras Hindu University · 8 years teaching NCERT Biology). Based on NCERT Biology Class XI, Chapter 12.
Why not just burn the glucose?
Burn a spoonful of glucose and it gives out all its energy at once, mostly as heat. Do that inside a cell and the cell would be cooked. The cell does something smarter: it takes the same glucose apart in many small steps, each controlled by an enzyme, so that the energy comes out in portions small enough to be captured as ATP, the energy currency of the cell. That slow, controlled oxidation is respiration. It is the breaking of C–C bonds of complex compounds through oxidation inside the cell. The compounds oxidised are called respiratory substrates. Carbohydrates are used usually, but proteins, fats and even organic acids can serve under some conditions.
Photosynthesis stores energy in glucose, sucrose and starch. Respiration, which takes place in the cytoplasm and the mitochondria of eukaryotes, is how plants, and everything that eats them, get that energy back out.
How do plants breathe without lungs?
Plants have no special organs for gas exchange. They use stomata in leaves and lenticels in the bark of woody stems. Three reasons explain why this is enough.
| Reason | Meaning |
|---|---|
| Each part looks after itself | Roots, stems and leaves exchange their own gases with little transport between them |
| Low demand | Plants respire at far lower rates than animals do |
| Short distance | Most living cells lie close to the surface, and the loosely packed parenchyma has connected air spaces. In woody stems the living cells form thin layers under the bark |
The big picture before the details
Respiration of glucose is one story told in three acts, each in a different place. Knowing the sites is half of this chapter.
| Stage | Site | Oxygen needed? | Main output per glucose |
|---|---|---|---|
| Glycolysis | Cytoplasm | No | 2 pyruvate, net 2 ATP, 2 NADH |
| Link reaction | Mitochondrial matrix | Indirectly | 2 acetyl-CoA, 2 CO₂, 2 NADH |
| Krebs (TCA) cycle | Mitochondrial matrix | Indirectly | 4 CO₂, 6 NADH, 2 FADH₂, 2 ATP |
| ETS and oxidative phosphorylation | Inner mitochondrial membrane | Yes, as final acceptor | Most of the ATP; water |
The path in one line: glucose → glycolysis → pyruvate → link reaction → acetyl-CoA → Krebs cycle → NADH and FADH₂ → ETS → ATP and H₂O.
Glycolysis: the step every cell shares
The word comes from Greek glycos (sugar) and lysis (splitting). The scheme was worked out by Gustav Embden, Otto Meyerhof and J. Parnas, which is why it is called the EMP pathway. It takes place in the cytoplasm of all living organisms, and in anaerobes it is the only respiratory process. A glucose molecule is partly oxidised, through ten enzyme catalysed reactions, to two molecules of pyruvic acid.
In plants the glucose usually comes from sucrose, the end product of photosynthesis, which invertase splits into glucose and fructose. Both sugars are then phosphorylated by hexokinase and enter the pathway.
| Step | Event | Energy change |
|---|---|---|
| 1 | Glucose → glucose 6 phosphate (hexokinase) | Uses 1 ATP |
| 2 | Isomerisation to fructose 6 phosphate | None |
| 3 | Fructose 6 phosphate → fructose 1,6 bisphosphate (phosphofructokinase) | Uses 1 ATP |
| 4 | Splitting into 3C dihydroxyacetone phosphate (DHAP) and 3 phosphoglyceraldehyde (PGAL) | None; the two interconvert |
| 5 | PGAL → 1,3 bisphosphoglyceric acid (BPGA) | NADH formed (per PGAL) |
| 6 | BPGA → 3 phosphoglyceric acid (3 PGA) | ATP formed (per PGAL) by substrate level phosphorylation |
| 7 | 3 PGA → 2 PGA → phosphoenolpyruvate (PEP), with loss of water | None |
| 8 | PEP → pyruvate | ATP formed (per PGAL) |
The arithmetic. Steps 5 to 8 happen twice for each glucose, because one fructose bisphosphate gives two PGAL. So 4 ATP are made and 2 are spent: the net gain is 2 ATP and 2 NADH. NTA asks "net", not "gross".
Substrate level phosphorylation means that a phosphate is moved directly from a substrate to ADP. It is different from the ETS route, where a proton gradient does the work.
Pause and predict: a cell gets fructose instead of glucose. Does it still make a net 2 ATP per sugar?
Check your answer: essentially yes. Fructose is also phosphorylated by hexokinase and joins the pathway at fructose 6 phosphate, so the ATP-using and ATP-making steps afterwards are the same.
Pyruvate has three possible fates
Glycolysis leaves a pyruvate at a fork. With no oxygen, the cell ferments it, either to lactic acid or to ethanol. With oxygen, it goes into the mitochondrion for complete oxidation. So there are three routes: lactic acid fermentation, alcoholic fermentation and aerobic respiration.
| Alcoholic fermentation | Lactic acid fermentation | |
|---|---|---|
| Where | Yeast and some other microbes | Some bacteria; animal muscle when oxygen is short |
| Change | Pyruvate → CO₂ + ethanol | Pyruvate → lactic acid |
| Enzymes | Pyruvic acid decarboxylase and alcohol dehydrogenase | Lactate dehydrogenase |
| Everyday example | Bread dough, wine and beer | Curd; the burn in muscles during a sprint |
| NADH | Reoxidised to NAD⁺ | Reoxidised to NAD⁺ |
Why fermentation wastes most of the energy. Less than 7 per cent of the energy in glucose is released, and not all of it ends up in ATP. The product (alcohol or acid) is also harmful. Yeast poisons itself when ethanol reaches about 13 per cent, which is why naturally fermented drinks stop at about that strength and anything stronger must be distilled.
Beyond the textbook. For the exam: fermentation is partial breakdown of glucose to ethanol or lactic acid under anaerobic conditions, with a net gain of 2 ATP. In reality: the real job of the last step is not to make the product, but to turn NADH back into NAD⁺. Glycolysis needs a supply of NAD⁺ at step 5, and with no oxygen to reoxidise NADH, ethanol or lactate formation is the only way to keep glycolysis going. Why it matters: it explains why both fermentations share the "NADH becomes NAD⁺" line, a favourite statement in assertion-reason questions.
Aerobic respiration: entering the mitochondrion
In eukaryotes, pyruvate is carried into the mitochondrion. Two crucial events follow. First, pyruvate is oxidised completely by removing every hydrogen, leaving three CO₂. This takes place in the matrix. Second, the electrons removed with the hydrogen are passed to molecular oxygen, with ATP being made as they go. This takes place on the inner membrane.
The link reaction. In the matrix, the pyruvate dehydrogenase complex carries out the oxidative decarboxylation of pyruvate:
Pyruvic acid + CoA + NAD⁺ → acetyl-CoA + CO₂ + NADH + H⁺
Coenzyme A and Mg²⁺ are among the cofactors needed. One glucose gives two pyruvates, so this step yields 2 NADH and 2 CO₂ per glucose.
The Krebs (TCA) cycle
Named after Hans Krebs, this cycle turns the acetyl group into CO₂. It begins when acetyl-CoA condenses with oxaloacetic acid (OAA) and water to give citric acid (6C), catalysed by citrate synthase. The cycle regenerates OAA at the end, which is why it is a cycle and why OAA must always be replenished.
| Reaction | What is released |
|---|---|
| Acetyl-CoA + OAA → citric acid (6C) | CoA released |
| Citric acid → isocitric acid | Isomerisation only |
| Isocitric acid → α-ketoglutaric acid (5C) | CO₂ + NADH |
| α-Ketoglutaric acid → succinyl-CoA (4C) | CO₂ + NADH |
| Succinyl-CoA → succinic acid | GTP, which gives ATP: substrate level phosphorylation |
| Succinic acid → fumaric acid | FADH₂ |
| Fumaric acid → malic acid → OAA | NADH at the last step |
So one turn of the cycle gives 3 NADH, 1 FADH₂, 1 ATP (via GTP) and 2 CO₂. Taking the link reaction and the cycle together, the summary for one pyruvate is pyruvic acid + 4 NAD⁺ + FAD⁺ + 2 H₂O + ADP + Pi → 3 CO₂ + 4 NADH + 4 H⁺ + FADH₂ + ATP. Doubling it for one glucose gives 6 CO₂, 8 NADH, 2 FADH₂ and 2 ATP, which accounts for all the carbon of glucose. Notice that only 2 ATP are made directly. The rest of the energy is waiting in the NADH and FADH₂.
Pause and predict: one pyruvate is oxidised completely to three CO₂. Which steps release them?
Check your answer: one in the link reaction, and two in the cycle (at isocitrate → α-ketoglutarate and α-ketoglutarate → succinyl-CoA).
The electron transport system: where the real harvest happens
The ETS sits in the inner mitochondrial membrane. NADH and FADH₂ hand over their electrons, which pass along a chain of carriers, ending at oxygen. The energy released is used to pump protons across the membrane and then to make ATP.
| Complex | Name | Role |
|---|---|---|
| I | NADH dehydrogenase | Takes electrons from NADH made in the matrix and passes them to ubiquinone (UQ) |
| II | Succinate dehydrogenase | Passes electrons from FADH₂ (made at succinate → fumarate) to ubiquinone |
| III | Cytochrome bc₁ complex | Passes electrons from reduced ubiquinone (ubiquinol) to cytochrome c |
| IV | Cytochrome c oxidase (cytochromes a and a₃, two copper centres) | Passes electrons to O₂, forming water |
| V | ATP synthase | Makes ATP from ADP + Pi using the proton gradient |
Cytochrome c is a small, mobile protein attached to the outer surface of the inner membrane that shuttles electrons between Complexes III and IV. Ubiquinone is the mobile carrier between I, II and III.
Why oxygen is essential even though it works only at the end. Oxygen is the final acceptor of the electrons. Without it, Complex IV cannot unload its electrons, the whole chain backs up, NADH cannot become NAD⁺ again, and the Krebs cycle stops. Oxygen removes hydrogen from the system and so keeps the whole process moving.
Making ATP: oxidative phosphorylation. Electron flow through Complexes I, III and IV pumps protons from the matrix into the space between the membranes, building a proton gradient. (Complex II does not pump, which is why FADH₂ yields less ATP than NADH.) ATP synthase has an F₀ part, an integral channel in the membrane, and an F₁ part, the headpiece that projects into the matrix and makes ATP. Protons flow back through F₀, and 4 H⁺ pass through F₀ for each ATP made. The energy comes from oxidation and reduction, not from light, hence the name oxidative phosphorylation. For exam calculations, one NADH gives 3 ATP and one FADH₂ gives 2 ATP.
The balance sheet: where 38 ATP comes from
| Stage | Direct ATP | NADH (x 3 ATP) | FADH₂ (x 2 ATP) | Total ATP |
|---|---|---|---|---|
| Glycolysis | 2 | 2 (6) | None | 8 |
| Link reaction | None | 2 (6) | None | 6 |
| Krebs cycle | 2 | 6 (18) | 2 (4) | 24 |
| Whole glucose | 38 |
This is an idealised figure. It assumes that the pathways run one after another in an orderly way, that NADH from glycolysis enters the mitochondrion and is oxidised there, that no intermediate is drawn off to make other compounds, and that glucose is the only substrate.
Beyond the textbook. For the exam: aerobic respiration of one glucose gives a net 38 ATP, with 3 ATP per NADH and 2 per FADH₂. In reality: a living cell does not reach this. Moving glycolytic NADH into the mitochondrion and moving ATP and Pi across the membrane both cost energy, and the generally accepted values are about 2.5 ATP per NADH and 1.5 per FADH₂, giving roughly 30 to 32 ATP per glucose. Why it matters: if a CUET option says 30 to 32 ATP and the others say 38, pick the one that matches the values the question gives (3 and 2 ATP means 38).
Fermentation versus aerobic respiration. Fermentation is partial breakdown, aerobic respiration is complete breakdown to CO₂ and H₂O. Fermentation nets 2 ATP per glucose, aerobic respiration far more. NADH is oxidised slowly in fermentation and very vigorously in aerobic respiration.
The amphibolic pathway: a crossroads, not a one way street
Glucose is the favourite substrate, but other food molecules also enter the same pathway at different points.
| Substrate | Breakdown | Enters at |
|---|---|---|
| Carbohydrates | Converted to glucose first | Glycolysis |
| Fats | Glycerol and fatty acids | Fatty acids → acetyl-CoA; glycerol → PGAL |
| Proteins | Proteases give amino acids; deamination | Pyruvate, acetyl-CoA or Krebs cycle intermediates |
Because intermediates are also drawn off to build fatty acids and amino acids, the respiratory pathway works in both catabolism and anabolism. That is why it is called an amphibolic pathway rather than just a catabolic one.
Pause and predict: a starving seedling burns its stored fats. At which compound do the fatty acids enter the pathway?
Check your answer: at acetyl-CoA, which then enters the Krebs cycle.
Respiratory quotient (RQ)
RQ = volume of CO₂ evolved ÷ volume of O₂ consumed. It tells you which substrate a tissue is burning, because the ratio depends on how much oxygen the substrate already contains.
| Substrate | Example | RQ |
|---|---|---|
| Carbohydrate | C₆H₁₂O₆ + 6O₂ → 6CO₂ + 6H₂O | 1.0 |
| Fat | Tripalmitin: 2C₅₁H₉₈O₆ + 145O₂ → 102CO₂ + 98H₂O, so 102 ÷ 145 | About 0.7 |
| Protein | Mixed amino acids | About 0.9 |
Fats have much less oxygen in the molecule than carbohydrates, so they need extra O₂ from outside and the ratio falls below 1. In real cells substrates are mixed, and pure proteins or fats are never the only fuel.
Beyond the textbook. For the exam: learn 1.0, 0.7 and 0.9. In reality: organic acids, which are already rich in oxygen, give an RQ above 1, and so does respiration in which some oxygen is unavailable. Why it matters: a measured RQ somewhere between the standard values means the tissue is burning a mixture.
Exam traps
| The trap | Why it's tempting | The truth |
|---|---|---|
| "Glycolysis gives 4 ATP." | Four are made | Net 2, because two are used at the start |
| "Glycolysis occurs only in anaerobes." | It needs no oxygen | It occurs in all living organisms, and in anaerobes it is the only respiratory process |
| "The Krebs cycle produces 38 ATP." | It is the famous cycle | It gives only 2 ATP directly per glucose. Most ATP is from the ETS |
| "The Krebs cycle directly makes only ATP." | Textbooks keep saying ATP | The direct product is GTP at succinyl-CoA → succinate, which is then converted to ATP |
| "Use 2.5 ATP per NADH for CUET." | Modern textbooks say so | The exam standard is 3 ATP per NADH, 2 per FADH₂ |
| "Complex II pumps protons." | It is part of the chain | Only I, III and IV pump |
| "Cytochrome c is a fixed part of Complex IV." | It sits close to it | It is a mobile carrier between III and IV |
| "Pyruvate has two fates." | Fermentation and respiration | Three: lactic acid fermentation, alcoholic fermentation and aerobic respiration |
60-second revision
| Topic | Lock this in |
|---|---|
| Glycolysis | Cytoplasm · EMP · glucose → 2 pyruvate · net 2 ATP + 2 NADH · hexokinase, PFK use ATP |
| Fermentation | Alcoholic: decarboxylase + alcohol dehydrogenase; lactic: lactate dehydrogenase · under 7 per cent energy · yeast dies at about 13 per cent ethanol |
| Link reaction | Matrix · pyruvate dehydrogenase · 2 NADH + 2 CO₂ per glucose |
| Krebs | Citrate synthase · per turn 3 NADH, 1 FADH₂, 1 GTP/ATP, 2 CO₂ |
| ETS | I NADH dehydrogenase · II succinate dehydrogenase · III bc₁ · IV cytochrome c oxidase · V ATP synthase |
| ATP | NADH 3, FADH₂ 2 · 4 H⁺ per ATP · net 38 (idealised) |
| Amphibolic | Catabolism and anabolism; fats via acetyl-CoA, glycerol via PGAL |
| RQ | Carbohydrate 1.0 · fat 0.7 · protein 0.9 |
Where this chapter connects
- Previous: Photosynthesis in Higher Plants makes the glucose that is burned here, and uses chemiosmosis too.
- Next: Plant Growth and Development uses this ATP to power growth, and shows ethylene raising respiration during fruit ripening.
- Class XII link: Microbes in Human Welfare applies fermentation by yeast and lactic acid bacteria in bread, curd and alcohol.
🎯 Practice MCQs
First 3 questions free · create a free account to unlock the rest — answers & explanations included, no payment needed
Q1. Match List I with List II. List I: (i) Hexokinase (ii) Invertase (iii) Citrate synthase (iv) Pyruvate dehydrogenase. List II: (p) Splits sucrose into glucose and fructose (q) Phosphorylates glucose to glucose 6 phosphate (r) Joins acetyl-CoA and oxaloacetic acid to form citric acid (s) Converts pyruvate to acetyl-CoA
▸ Show answer & explanation
Answer: A
Hexokinase starts glycolysis by phosphorylating glucose, invertase splits sucrose before glycolysis, citrate synthase begins the Krebs cycle and pyruvate dehydrogenase carries out the link reaction. Options B, C and D each swap the roles of at least one pair of enzymes.
Q2. Which statement about glycolysis is correct?
▸ Show answer & explanation
Answer: C
Four ATP are made but two are used, so the net gain is 2 ATP, and 2 NADH are formed at the PGAL to BPGA step. Glycolysis occurs in the cytoplasm of all organisms and needs no oxygen, so A and D are wrong. Option B quotes the gross yield of ATP.
Q3. Consider the statements. I: Yeast converts pyruvic acid into ethanol and CO2 under anaerobic conditions. II: Lactate dehydrogenase reduces pyruvic acid to lactic acid. III: NADH is reoxidised to NAD+ in both alcoholic and lactic acid fermentation. IV: Fermentation releases more than half of the energy of glucose. Which statements are correct?
▸ Show answer & explanation
Answer: A
Statements I, II and III are correct. Statement IV is wrong because fermentation releases less than 7 per cent of the energy in glucose.
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Q4. The link reaction between glycolysis and the Krebs cycle
▸ Show answer & explanation
Answer: B
The pyruvate dehydrogenase complex acts in the matrix, forming acetyl-CoA, CO2 and NADH. Conversion of acetyl-CoA to citric acid is the first step of the Krebs cycle (D), and ATP synthase belongs to the inner membrane ETS (C).
Q5. Complete oxidation of one molecule of pyruvic acid through the link reaction and the Krebs cycle yields
▸ Show answer & explanation
Answer: B
The summary equation gives 3 CO2, 4 NADH, 1 FADH2 and 1 ATP. Option A counts only the Krebs cycle turn and leaves out the NADH and CO2 of the link reaction. Options C and D give wrong numbers of FADH2 or ATP.
Q6. Which enzyme takes part in the Krebs cycle and also forms Complex II of the electron transport system?
▸ Show answer & explanation
Answer: C
Succinate dehydrogenase converts succinate to fumarate in the cycle, producing FADH2, and the same enzyme passes these electrons to ubiquinone as Complex II. NADH dehydrogenase is Complex I, citrate synthase works only in the cycle and cytochrome c oxidase is Complex IV.
Q7. Which statement about the electron transport system is INCORRECT?
▸ Show answer & explanation
Answer: D
Complex II does not pump protons, and FADH2 yields less ATP than NADH since it enters the chain after Complex I. Statements A, B and C are correct.
Q8. Match List I with List II. List I: (i) Complex I (ii) Complex III (iii) Complex IV (iv) Complex V. List II: (p) Cytochrome c oxidase (q) ATP synthase (r) NADH dehydrogenase (s) Cytochrome bc1 complex
▸ Show answer & explanation
Answer: A
Complex I is NADH dehydrogenase, III is the bc1 complex, IV is cytochrome c oxidase with cytochromes a and a3 and copper, and V is ATP synthase. The other options mismatch at least two complexes.
Q9. Assertion (A): In the absence of oxygen, the Krebs cycle soon stops. Reason (R): Oxygen is the final electron acceptor, and without it NADH and FADH2 cannot be reoxidised to NAD+ and FAD.
▸ Show answer & explanation
Answer: A
Without oxygen the chain backs up, NAD+ and FAD are not regenerated, and the dehydrogenase steps of the cycle cannot continue. R is the direct reason for A.
Q10. Using the values of 3 ATP per NADH and 2 ATP per FADH2, how many ATP are formed by oxidative phosphorylation from the NADH and FADH2 produced by the link reaction and the Krebs cycle of one glucose molecule?
▸ Show answer & explanation
Answer: B
The link reaction and the Krebs cycle give 8 NADH and 2 FADH2, which yield 8 x 3 + 2 x 2 = 28 ATP. Option A leaves out the FADH2, and the glycolytic NADH and the ATP made directly are not part of this count.
Q11. The respiratory quotient of tripalmitin, using 2C51H98O6 + 145O2 → 102CO2 + 98H2O, and the RQ of glucose are respectively
▸ Show answer & explanation
Answer: A
102 CO2 divided by 145 O2 gives about 0.7 for fat, while glucose gives 6 CO2 per 6 O2, which is 1.0. Option B reverses them and option C uses the approximate RQ of proteins for fat.
Q12. Assertion (A): The respiratory pathway is described as amphibolic. Reason (R): Intermediates of the pathway receive the breakdown products of fats and proteins and are also withdrawn to synthesise fatty acids and amino acids.
▸ Show answer & explanation
Answer: A
The pathway serves both catabolism and anabolism, because the same intermediates are used for breakdown and for biosynthesis. R therefore explains A.
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