📌 Snapshot
- Amines are derivatives of ammonia obtained by replacing one, two or three H atoms by alkyl/aryl groups; nitrogen is sp³ hybridised, giving a pyramidal geometry.
- Covers classification (1°, 2°, 3°), nomenclature (common + IUPAC), six preparation routes, basicity in gas vs aqueous phase, distinguishing tests (carbylamine, Hinsberg, HNO₂), and electrophilic substitution of arylamines.
- Diazonium salts derived from aniline are introduced as versatile synthetic intermediates allowing replacement of –N₂⁺ by –Cl, –Br, –I, –F, –CN, –OH, –NO₂, –H, and azo-coupling to give dyes.
- CUET regularly tests product prediction (Hofmann bromamide, Sandmeyer, Gabriel), basicity ordering with pKb logic, and identification of amines using the Hinsberg/carbylamine tests.
📖 Detailed Notes
2.1 Core concepts
- Amines are formed by replacing one, two or three H atoms of NH₃ with alkyl/aryl groups; biologically they occur in proteins, vitamins, alkaloids and hormones; commercially used in medicines, dyes and polymers (NCERT Introduction, p. 259).
- Nitrogen in amines is sp³ hybridised with one unshared lone pair; geometry is pyramidal and the C–N–E angle is less than 109.5° (108° in trimethylamine, Fig. 9.1) (NCERT §9.1, p. 259-260). The lone pair occupies the fourth sp³ orbital and is responsible for both the basicity and nucleophilicity of amines.
- Classification: 1° (R–NH₂), 2° (R–NHR′), 3° (R₃N) depending on number of H atoms of NH₃ replaced; "simple" if all alkyl/aryl groups are identical, "mixed" if different (NCERT §9.2, p. 260). Aromatic amines may carry –NH₂ on the ring (aniline) or on a side chain (benzylamine, C₆H₅CH₂NH₂ — still aliphatic in nature).
- Nomenclature: common system uses alkylamine (one word); IUPAC names primary amines as alkanamines (replace "e" of alkane by "amine"); secondary/tertiary use locant N (e.g., CH₃NHCH₂CH₃ = N-methylethanamine); C₆H₅NH₂ = aniline = benzenamine (NCERT §9.3, Table 9.1, p. 260-261).
- Preparation routes: (1) Reduction of nitro compounds with H₂/Ni, Pd or Pt or with Fe/HCl (FeCl₂ hydrolyses to regenerate HCl, so only catalytic HCl needed); active metals + acidic medium (Sn/HCl, Fe/HCl) reduce ArNO₂ → ArNH₂; selective reduction with H₂S, polysulphide or Fe/HCl leaves another reducible group untouched (NCERT §9.4(1), p. 262).
- (2) Ammonolysis of alkyl halides with ethanolic NH₃ in a sealed tube at 373 K — gives a mixture of 1°, 2°, 3° amines and quaternary ammonium salt (Hofmann's exhaustive alkylation); reactivity RI > RBr > RCl; large excess NH₃ favours primary amine while excess alkyl halide favours quaternary salt (NCERT §9.4(2), p. 262-263).
- (3) Reduction of nitriles with LiAlH₄ or catalytic H₂/Ni, Pd, Pt gives 1° amines with one more carbon — used for "ascent of amine series" (Mendius reduction); (4) Reduction of amides with LiAlH₄ gives amines (NCERT §9.4(3-4), p. 263).
- (5) Gabriel phthalimide synthesis: phthalimide + ethanolic KOH → potassium phthalimide → alkyl halide (SN2) → alkaline hydrolysis (or hydrazinolysis) → primary amine + phthalhydrazide; works ONLY for aliphatic 1° amines, since aryl halides do not undergo nucleophilic substitution with the phthalimide anion (NCERT §9.4(5), p. 264).
- (6) Hofmann bromamide degradation: R/Ar–CONH₂ + Br₂ + 4 NaOH → R/Ar–NH₂ + Na₂CO₃ + 2 NaBr + 2 H₂O — gives a primary amine with one carbon less than the amide; involves migration of the alkyl/aryl group from carbonyl C to N through an isocyanate intermediate (NCERT §9.4(6), p. 264). Benzamide → aniline; acetamide → methanamine.
- Physical properties: lower aliphatic amines are gases with fishy odour; higher ones smell like fish; aniline and arylamines are colourless but darken on storage due to atmospheric oxidation; lower amines are water-soluble via N–H···O hydrogen bonding, solubility falls with increasing alkyl mass; alcohols are more polar than amines (O is more electronegative than N) and form stronger H-bonds (NCERT §9.5, p. 265).
- Boiling point order of isomeric amines: 1° > 2° > 3° because 1° has two N–H bonds available for intermolecular H-bonding while 3° has none; Table 9.2 shows n-C₄H₉NH₂ (350.8 K) > (C₂H₅)₂NH (329.3 K) > C₂H₅N(CH₃)₂ (310.5 K) > (C₂H₅)(CH₃)₂N (310 K) and n-C₄H₉OH (390.3 K) > n-C₄H₉NH₂ (NCERT §9.5, Table 9.2, p. 266).
- Basicity: amines react with acids to form salts; aliphatic amines are stronger bases than NH₃ (+I effect of alkyl groups, pKb 3–4.22); aromatic amines are weaker than NH₃ (lone pair in conjugation with ring; aniline pKb = 9.38) (NCERT §9.6, Table 9.3, p. 266-267). Smaller pKb means stronger base; Kb = [R-NH₃⁺][OH⁻]/[R-NH₂].
- Gas-phase basicity order: 3° > 2° > 1° > NH₃ (governed only by the +I effect of alkyl groups); aqueous-phase order is irregular due to interplay of (a) +I electron release, (b) solvation/H-bonding stabilisation of the alkyl-substituted ammonium cation, and (c) steric hindrance to solvation. NCERT gives the ethyl series as (C₂H₅)₂NH > (C₂H₅)₃N > C₂H₅NH₂ > NH₃ and the methyl series as (CH₃)₂NH > CH₃NH₂ > (CH₃)₃N > NH₃ (NCERT §9.6.1, p. 268-269).
- Aniline is less basic than NH₃ because aniline has five resonance structures (lone pair delocalised into the benzene ring) but anilinium ion has only two — so the free amine is more stabilised than its conjugate acid; electron-releasing groups (–OCH₃, –CH₃) at p-position increase basicity, while electron-withdrawing groups (–NO₂, –SO₃H, –COOH, –X) decrease it. Order: p-toluidine > aniline > p-nitroaniline (NCERT §9.6.1(b), p. 269).
- Alkylation: amines react with alkyl halides giving 2°, 3° amines and quaternary salts (Hofmann's exhaustive alkylation); acylation: 1° and 2° amines react with acid chlorides, anhydrides or esters in presence of a base (pyridine, removing HCl) to give N-substituted amides; benzoyl chloride gives benzoylated derivatives (Schotten-Baumann benzoylation) (NCERT §9.6.2-9.6.3, p. 270).
- Carbylamine reaction: 1° aliphatic and aromatic amines + CHCl₃ + alcoholic KOH (Δ) → foul-smelling isocyanides (carbylamines) R–NC; 2° and 3° amines give no such reaction — diagnostic test for 1° amines: R–NH₂ + CHCl₃ + 3KOH → R–NC + 3KCl + 3H₂O (NCERT §9.6.4, p. 271).
- Reaction with HNO₂ (nitrous acid generated in situ from NaNO₂ + dil. HCl): 1° aliphatic amines → unstable aliphatic diazonium salts which liberate N₂ quantitatively and form alcohols (Van Slyke method for amino-acid estimation); 1° aromatic amines at 273-278 K → stable aromatic diazonium salts (diazotisation); 2° amines give yellow oily N-nitrosoamines (R₂N–NO); 3° amines react differently (form a soluble salt with HCl, then react with HNO₂ to give an N-nitroso ammonium compound) (NCERT §9.6.5, p. 271).
- Hinsberg test with benzenesulphonyl chloride (C₆H₅SO₂Cl): 1° amine → N-alkylbenzenesulphonamide bearing an N–H that is acidic (SO₂ group withdraws e⁻), hence soluble in alkali; 2° amine → N,N-dialkylbenzenesulphonamide (no acidic N–H), insoluble in alkali; 3° amine → no reaction (no N–H to react); p-toluenesulphonyl chloride is now preferred (NCERT §9.6.6, p. 271-272).
- Electrophilic substitution on aniline: –NH₂ is a powerful o/p-directing activating group; bromination with bromine water at room temperature gives white 2,4,6-tribromoaniline (over-reaction); to obtain monosubstituted products, –NH₂ is protected by acetylation (acetic anhydride → acetanilide), substitution performed, then hydrolysed back to the amine — gives mainly p-bromoaniline (NCERT §9.6.7(a), p. 272-273).
- Nitration of aniline directly gives tarry oxidation products and significant m-nitroaniline (anilinium ion in strong acid is meta-directing; ratio o : m : p ≈ 19 : 47 : 51); after acetylation, nitration gives p-nitroacetanilide as major product, hydrolysed to p-nitroaniline (NCERT §9.6.7(b), p. 273).
- Sulphonation of aniline with conc. H₂SO₄ → anilinium hydrogensulphate → on heating at 453-473 K → p-aminobenzenesulphonic acid (sulphanilic acid, exists as a zwitterion); aniline does not undergo Friedel-Crafts reaction (alkylation or acylation) because it forms a salt with AlCl₃, making N positively charged (strong deactivator) (NCERT §9.6.7(c), p. 273).
- Diazonium salts have formula R–N₂⁺X⁻ where R is aryl and X⁻ is Cl⁻, Br⁻, HSO₄⁻, BF₄⁻; named by attaching "diazonium" to the parent hydrocarbon name followed by anion name; arenediazonium ion is stabilised by resonance over the ring carbons (NCERT §II, p. 274).
- Diazotisation: aniline + NaNO₂ + 2HCl at 273-278 K → C₆H₅N₂⁺Cl⁻ + NaCl + 2H₂O; diazonium salts are unstable in the dry state (explosive) and must be used immediately in solution (NCERT §9.7, p. 274).
- Properties: benzenediazonium chloride is a colourless crystalline solid, water-soluble, stable in cold but reacts with warm water; benzenediazonium fluoroborate is water-insoluble and stable at room temperature (NCERT §9.8, p. 275).
- Replacement reactions (loss of N₂): Sandmeyer with Cu₂Cl₂/Cu₂Br₂/CuCN gives Ar–Cl, Ar–Br, Ar–CN; Gatterman uses Cu powder + HX; KI gives Ar–I directly (no Cu needed); HBF₄ then heat (Balz-Schiemann) gives Ar–F; mild reducing agents (H₃PO₂ or ethanol) give Ar–H; warming in water (283 K) gives phenol; NaNO₂/Cu with diazonium fluoroborate gives Ar–NO₂ (NCERT §9.9 A, p. 275-276).
- Coupling reactions (retention of diazo group): benzenediazonium chloride + phenol (in mildly alkaline medium) → p-hydroxyazobenzene (orange dye); + aniline (in mildly acidic medium) → p-aminoazobenzene (yellow); the resulting azo compounds (–N=N–) are coloured and used as dyes (NCERT §9.9 B, p. 276).
- Importance: diazonium salts enable introduction of –F, –Cl, –Br, –I, –CN, –OH, –NO₂ into aromatic rings — aryl fluorides and iodides cannot be made by direct halogenation, and –CN cannot be introduced by direct nucleophilic substitution of chlorobenzene (NCERT §9.10, p. 276-277).
2.2 Definitions to memorise
| Term | Definition | Page |
|---|---|---|
| Primary amine (1°) | R–NH₂ — one H of NH₃ replaced by alkyl/aryl group | 260 |
| Secondary amine (2°) | R–NHR′ — two H atoms of NH₃ replaced | 260 |
| Tertiary amine (3°) | R₃N — all three H atoms of NH₃ replaced | 260 |
| Simple vs mixed amine | All alkyl/aryl groups same = simple; different = mixed | 260 |
| Quaternary ammonium salt | R₄N⁺X⁻ formed by exhaustive alkylation of amine | 263 |
| Ammonolysis | Cleavage of C–X bond by NH₃ giving amine + HX (sealed tube, 373 K) | 262 |
| Hofmann bromamide degradation | Amide + Br₂ + NaOH → 1° amine with one C less | 264 |
| Gabriel phthalimide synthesis | Phthalimide → K-phthalimide → alkyl halide → hydrolysis to give 1° aliphatic amine | 264 |
| Mendius reduction | Reduction of nitrile R–CN with Na/C₂H₅OH or H₂/Ni → 1° amine with one C more | 263 |
| Diazotisation | Conversion of 1° aromatic amine to arenediazonium salt with NaNO₂/HCl at 273-278 K | 274 |
| Carbylamine reaction | 1° amine + CHCl₃ + alc. KOH → R–NC (isocyanide); diagnostic for 1° amines | 271 |
| Hinsberg test | C₆H₅SO₂Cl distinguishes 1°/2°/3° amines by alkali-solubility of the sulphonamide | 271 |
| Sandmeyer reaction | Ar–N₂⁺X⁻ + Cu₂X₂ → Ar–X (X = Cl, Br, CN) | 275 |
| Gatterman reaction | Ar–N₂⁺X⁻ + Cu/HX → Ar–X (less efficient than Sandmeyer) | 275 |
| Balz-Schiemann reaction | Ar–N₂⁺BF₄⁻ Δ→ Ar–F + N₂ + BF₃ | 275 |
| Coupling reaction | Ar–N₂⁺ + ArOH or ArNH₂ → Ar–N=N–Ar′ (azo dye) | 276 |
| Schotten-Baumann reaction | Benzoylation of 1°/2° amine with C₆H₅COCl in presence of NaOH | 270 |
| Acetanilide | C₆H₅NHCOCH₃ — N-protected aniline used to moderate ring substitution | 272 |
| pKb | –log Kb; smaller pKb = stronger base | 267 |
| Aniline | C₆H₅NH₂ = benzenamine; weakest of common amines (pKb 9.38) | 269 |
| Isocyanide | R–N≡C (carbylamine); foul-smelling; obtained from 1° amine + CHCl₃ + KOH | 271 |
| N-Nitrosoamine | R₂N–NO; yellow oil formed from 2° amine + HNO₂ | 271 |
| Invert/azo dye | Coloured –N=N– compound from diazonium salt + activated arene | 276 |
2.3 Diagrams / processes to remember
- Fig. 9.1, p. 260 — pyramidal shape of trimethylamine, three C–N bonds with the lone pair occupying the fourth tetrahedral position; C–N–C angle = 108°, slightly less than tetrahedral 109.5° due to lone-pair compression.
- Fig. 9.2, p. 266 — intermolecular hydrogen bonding in primary amines: N–H···N chains explain why 1° amines boil higher than 2° (one N–H per N) and 3° amines (no N–H); diagram contrasts the H-bonded network in CH₃CH₂NH₂ with the absence of such bonding in (CH₃)₃N.
- Table 9.1, p. 261 — common vs IUPAC names of alkylamines and arylamines (methylamine = methanamine; ethylamine = ethanamine; aniline = benzenamine; N,N-dimethylmethanamine for trimethylamine).
- Table 9.2, p. 266 — boiling points of amines, alcohols, alkanes of similar molar mass showing 1° > 2° > 3° amine order (n-butylamine 350.8 K > diethylamine 329.3 K > N,N-dimethylethylamine 310 K) and alcohol > amine (n-butanol 390.3 K).
- Table 9.3, p. 267 — pKb values: methanamine 3.38, dimethylamine 3.27, trimethylamine 4.22, ethanamine 3.29, aniline 9.38, N-methylaniline 9.30, N,N-dimethylaniline 8.92 — useful for ordering basicity.
- Resonance structures of aniline (five) vs anilinium ion (two), p. 269 — diagram of how the lone pair on N is donated into the ring in three Kekulé-equivalent canonical forms plus two ortho/para charge-separated forms, lowering the energy of the free amine more than the protonated ion → reduced basicity.
- Sandmeyer / Gatterman reaction equations, p. 275 — Cu(I) catalysed replacements of –N₂⁺ by –Cl, –Br, –CN; mechanism involves radical-pair intermediate with Cu(II)X species; arrows showing C₆H₅N₂⁺ + CuCl → C₆H₅Cl + N₂ + Cu⁺.
- Coupling reaction scheme, p. 276 — formation of p-hydroxyazobenzene (from phenol, mildly alkaline pH 9-10) and p-aminoazobenzene (from aniline, mildly acidic pH 4-5); electrophile is the arenediazonium ion; coupling para to the activating –OH or –NH₂ group.
- Acetanilide protection scheme, p. 272-273 — flowchart: aniline → (Ac₂O / pyridine) → acetanilide → (Br₂ / CH₃COOH) → p-bromoacetanilide → (H₃O⁺) → p-bromoaniline; shows how moderation prevents tribromination.
- Carbylamine test arrow-pushing, p. 271 — formation of dichlorocarbene from CHCl₃ + OH⁻, attack on R–NH₂, elimination of 2 HCl to give R–NC; only 1° amines have two replaceable N–H atoms.
2.4 Common confusions / NTA trap points
- Gas-phase basicity follows pure +I logic (3° > 2° > 1° > NH₃), but aqueous phase order is irregular due to solvation + steric hindrance; do NOT generalise either way — NCERT specifies methyl series as (CH₃)₂NH > CH₃NH₂ > (CH₃)₃N > NH₃ (Table 9.3, p. 267-268).
- Hofmann bromamide gives amine with one C less; reduction of nitriles gives amine with one C more — these two routes are commonly swapped in distractors (p. 263-264). Acetamide (C-2) → methanamine (C-1); methyl cyanide (C-2) → ethylamine (C-2).
- Gabriel phthalimide synthesis works only for primary aliphatic amines; aromatic primary amines cannot be made because aryl halides do not undergo nucleophilic substitution with phthalimide anion (p. 264).
- Hinsberg test: 1° gives sulphonamide soluble in alkali (acidic N–H); 2° gives sulphonamide insoluble in alkali (no N–H); 3° does not react at all — students often reverse 1° and 2° solubility (p. 271-272).
- Carbylamine test is positive only for 1° amines (aliphatic and aromatic); 2° and 3° amines give negative result (p. 271).
- Aniline does NOT undergo Friedel-Crafts alkylation/acylation because aniline + AlCl₃ forms a salt putting positive charge on N, deactivating the ring (p. 273); the salt is C₆H₅NH₂·AlCl₃.
- Direct nitration of aniline gives substantial m-nitroaniline because in strong acid aniline is protonated to anilinium ion which is meta-directing — this contradicts the "amino is o/p-directing" rule and is a favourite trap (p. 273).
- HNO₂ + 1° aliphatic amine → alcohol + N₂↑ (unstable RN₂⁺ decomposes); but HNO₂ + 1° aromatic amine → stable ArN₂⁺ at 273-278 K — students often confuse the two outcomes (p. 271).
- HNO₂ + 2° amine → N-nitrosoamine (yellow oil, R₂N–NO); 3° aliphatic amine → quaternary ammonium nitrite (water-soluble); 3° aromatic amine (N,N-dimethylaniline) → p-nitroso derivative (ring attack). All three outcomes are different — memorise each (p. 271).
- Diazonium coupling needs activated arenes (phenol, aniline, N,N-dimethylaniline); benzene itself does NOT couple. Students sometimes write coupling with toluene — wrong.
- Bromination of aniline with Br₂/H₂O gives the 2,4,6-tribromo product (not the mono); to get the mono-Br product, the amine must first be acetylated (p. 272-273).
- Reduction of ArNO₂ in acidic medium (Sn/HCl, Fe/HCl) gives ArNH₂; in neutral/alkaline medium gives intermediate products like ArN=NAr (azobenzene) or ArNHNHAr (hydrazobenzene) — easy to confuse with diazonium chemistry.
🎯 Practice MCQs
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Q1. The C–N–C bond angle in trimethylamine is 108°. Which of the following best explains this value being less than the ideal tetrahedral angle of 109.5°?
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Answer: B
Nitrogen is sp³ hybridised with one orbital holding the unshared lone pair; the lone pair–bond pair repulsion compresses the C–N–C angle to 108°, slightly less than 109.5°.
Q2. Which of the following is the correct IUPAC name of (CH₃CH₂)₃N?
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Answer: B
Treating one of the ethyl groups as the parent ethanamine and the other two as N-substituents gives N,N-diethylethanamine. "Triethylamine" is the common name, not IUPAC.
Q3. The Gabriel phthalimide synthesis is not suitable for the preparation of aromatic primary amines because:
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Answer: B
The phthalimide anion is a nucleophile and requires an SN2-active alkyl halide; aryl halides do not undergo this nucleophilic substitution, so aromatic primary amines cannot be made.
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Q4. Hofmann bromamide degradation of benzamide gives:
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Answer: B
Hofmann bromamide reduces the carbon count by one (migration of aryl group from C=O to N); benzamide (C₆H₅CONH₂, seven carbons) gives aniline (C₆H₅NH₂, six carbons).
Q5. The correct decreasing order of basic strength in aqueous solution is:
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Answer: B
In aqueous solution the basicity order is governed by an interplay of +I effect, solvation of the substituted ammonium cation, and steric hindrance; NCERT explicitly gives the ethyl series order as (C₂H₅)₂NH > (C₂H₅)₃N > C₂H₅NH₂ > NH₃.
Q6. Which of the following reacts with benzenesulphonyl chloride (Hinsberg's reagent) to give a product that is insoluble in alkali?
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Answer: C
Secondary amines (like N-methylaniline) give N,N-disubstituted benzenesulphonamides with no N–H, which are insoluble in alkali. Primary amines give an N–H sulphonamide that is soluble in alkali; tertiary amines do not react.
Q7. Match the reagent with the diazonium salt reaction product (X = C₆H₅N₂⁺Cl⁻): | Reagent | Product | |---|---| | P. CuCN | 1. C₆H₅Cl | | Q. KI | 2. C₆H₅I | | R. Cu₂Cl₂ | 3. C₆H₅CN | | S. H₃PO₂ / H₂O | 4. C₆H₆ |
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Answer: A
CuCN gives the nitrile (Sandmeyer), KI gives iodobenzene, Cu₂Cl₂ gives chlorobenzene (Sandmeyer), and H₃PO₂ reduces the diazonium salt to benzene with loss of N₂.
Q8. Assertion (A): Aniline does not undergo Friedel-Crafts alkylation. Reason (R): The –NH₂ group is a strong ortho/para-directing activator, but aniline forms a salt with AlCl₃ in which nitrogen acquires a positive charge, making the ring strongly deactivated.
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Answer: A
NCERT explicitly states that aniline + AlCl₃ forms a salt placing positive charge on N, which then strongly deactivates the ring towards further electrophilic substitution.
Q9. A primary aliphatic amine is heated with chloroform and ethanolic potassium hydroxide. The foul-smelling product formed is:
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Answer: B
This is the carbylamine (isocyanide) test for primary amines: R–NH₂ + CHCl₃ + 3KOH → R–NC + 3KCl + 3H₂O; secondary and tertiary amines do not give this reaction.
Q10. Aniline is treated with NaNO₂ + HCl at 273-278 K and the resulting solution is added to phenol in alkaline medium. The major organic product is:
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Answer: B
Aniline first undergoes diazotisation to form benzenediazonium chloride; coupling at the para position of phenol gives p-hydroxyazobenzene, an orange azo dye. Replacement of –N₂⁺ by Cl would need CuCl, not phenol.
Q11. The correct order of basicity of the following aromatic amines in aqueous solution is:
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Answer: A
Electron-releasing –CH₃ (p-toluidine) increases the electron density on N → stronger base; electron-withdrawing –NO₂ (p-nitroaniline) drains it → weaker base. Hence p-toluidine > aniline > p-nitroaniline.
Q12. Acetanilide is preferred as a starting material for the para-bromination of aniline because:
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Answer: B
Acetylation of –NH₂ to –NHCOCH₃ moderates the activating effect of the lone pair on N (which gets delocalised into the C=O of the acetyl group), giving controlled mono-bromination at the para position. Subsequent acid hydrolysis regenerates the amine as p-bromoaniline.
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