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Ratio, Proportion & Percentage

Ratio, Proportion & Percentage is a frequently tested area in CUET General Test. Work through these free NTA-style sample questions with full answers and explanations, then attempt all 40 in a timed practice test to build exam-day speed.

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Snapshot

Part 1 — The core idea: everything is a fraction of a base

Written and reviewed by Devendra Dubey, Mathematics & Commerce faculty at UniDrill (M.Sc. Mathematics, Osmania University · 10 years teaching). Prepared for the CUET UG General Test.

Percent means "per hundred", so 25% is just the fraction 1/4 wearing different clothes. Once you see percentages as fractions, most of the arithmetic disappears: 25% of 880 is a quarter of 880, which is 220, with no long multiplication.

Why the base matters

A percentage is meaningless until you say "of what". A rise from 80 to 100 is a rise of 20, and 20 out of the old value 80 is 25%. If you divide by the new value you get 20%, and CUET always puts that wrong answer among the options. The rule never changes: percentage change is measured on the starting value.

This single fact also explains the "flip" that surprises students. If A is 25% more than B, then A = 1.25 B, so B is A divided by 1.25, which is 0.8 A, a 20% fall. The gap (0.25 B) is the same in both statements but the base is different (B in one, A in the other).

Ratio is a count of equal units

A ratio 2 : 3 : 4 does not tell you any amount. It tells you the whole is cut into 2 + 3 + 4 = 9 equal units. Find what one unit is worth and every share is a single multiplication. This one move solves sharing, ages, mixtures and partnerships.

Proportion is a rule about what stays fixed

In direct proportion the ratio of the two quantities stays fixed (twice the workers, twice the output). In inverse proportion the product stays fixed (twice the workers, half the days). Decide which one before you write anything.

A mixture is a balance

When two things at different values are blended, the result lies between them, closer to the one you used more of. Alligation is simply the balance rule: the distances from the mean to each ingredient are in the inverse ratio of the quantities.

Pause and predict: a shopkeeper raises a price by 20% and then lowers the new price by 20%. Is the final price higher, lower, or the same as the original?

Check your answer: lower. The 20% fall is taken on the larger, raised price, so it removes more rupees than the rise added. Net change is $20 - 20 - \dfrac{20 \times 20}{100} = -4$, a 4% fall.

Fraction and percentage pairs to memorise

Fraction % Fraction % Fraction %
1/2 50 1/6 16.67 1/12 8.33
1/3 33.33 1/7 14.28 1/15 6.67
1/4 25 1/8 12.5 1/16 6.25
1/5 20 1/9 11.11 3/8 37.5
2/5 40 1/10 10 5/8 62.5

Part 2 — Formula sheet

Percentage and change:

$$\text{Percentage change} = \dfrac{\text{New} - \text{Old}}{\text{Old}} \times 100$$

$$\text{Two successive changes of } a\% \text{ and } b\% = \left(a + b + \dfrac{ab}{100}\right)\% \quad (\text{use a minus sign for a fall})$$

$$\text{Final value} = \text{Original} \times \left(1 \pm \dfrac{r_1}{100}\right)\left(1 \pm \dfrac{r_2}{100}\right)\cdots$$

Ratio and proportion:

$$a : b = c : d \iff ad = bc \qquad \text{Mean proportional of } a, c = \sqrt{ac}$$

Partnership and alligation:

$$\text{Profit share} \propto \text{Capital} \times \text{Time} \qquad \dfrac{\text{Quantity of cheaper}}{\text{Quantity of dearer}} = \dfrac{\text{Dearer} - \text{Mean}}{\text{Mean} - \text{Cheaper}}$$

$$\text{Pure quantity left after } n \text{ replacements} = V\left(1 - \dfrac{x}{V}\right)^n$$

Situation Formula When to use
Percentage of a number $\dfrac{r}{100} \times N$ Direct "r% of N"
A is what % of B $\dfrac{A}{B} \times 100$ Base is the number after "of"
Reverse percentage $\dfrac{\text{Final}}{1 \pm r/100}$ Final value after a change is given
Price up r%, cut consumption by $\dfrac{r}{100 + r} \times 100$ % Expenditure kept constant
Price down r%, raise consumption by $\dfrac{r}{100 - r} \times 100$ % Expenditure kept constant
Direct proportion $\dfrac{x_1}{y_1} = \dfrac{x_2}{y_2}$ Both rise together
Inverse proportion $x_1 y_1 = x_2 y_2$ One rises, the other falls
Compound proportion $\dfrac{M_1 D_1 H_1}{W_1} = \dfrac{M_2 D_2 H_2}{W_2}$ Men, days, hours, work
Combining ratios Make the common term equal A : B and B : C to get A : B : C
Weighted mean of two groups $\dfrac{n_1 a_1 + n_2 a_2}{n_1 + n_2}$ Alligation in disguise

Part 3 — Shortcut methods and when they fail

Shortcut How it works When it fails
Convert to a fraction 37.5% of 800 is 3/8 of 800 = 300 Odd percentages such as 17.3%: just compute 10% + 7% + 0.3%
Flip the percentage x% of y equals y% of x, so 16% of 25 = 25% of 16 = 4 Only for "of" calculations, never for percentage change
10% and 1% anchors 23% of 350 = 70 + 10.5 = 80.5 Slower than the fraction method when the percentage is a friendly fraction
Successive formula $a + b + ab/100$ Two changes in one line It is for two changes only. For three or more, multiply the factors: 1.1 × 1.2 × 0.9
Percentage flip $r/(100 \pm r)$ Consumption or reverse change in one line Needs a constant product (expenditure, area, speed × time). It fails when the quantity is not a product
Unit value for ratios One unit = total ÷ sum of parts Ratios of ages or amounts after a change need an equation, not one unit
Alligation cross Ratio of distances from the mean Only when the quantity mixed is linear in the property (price per kg, acid per litre). It fails for averages of rates such as speed over equal distances
Product constant for inverse $x_1 y_1 = x_2 y_2$ If some workers are added midway, split the job into stages instead

The multiplier habit. Turn each change into a multiplier: +12% is 1.12, −15% is 0.85, and then multiply. It never fails, and it handles three or four changes without a special formula. Use the $a + b + ab/100$ shortcut only when there are exactly two.

Direction check. After every answer ask whether it moved the right way. A price after a discount must be smaller; the original before a discount must be larger. This 3-second check catches the most common sign slips.

Part 4 — Worked examples: percentage

Worked example 1: successive change. A number is increased by 25% and then decreased by 20%. What is the net change?

Step What we do Result
1 Multipliers are 1.25 and 0.8 $1.25 \times 0.8$
2 Multiply $1.00$
3 Net change No change (0%)

Common wrong step: adding 25 and subtracting 20 to get +5%. Each change has a different base, so the rise and fall do not simply add.

Worked example 2: reverse percentage. After a 12% hike a salary is ₹28,000. What was it before?

The final value is 112% of the original, so original = $\dfrac{28000}{1.12} = 25000$, that is ₹25,000. Check: 12% of 25,000 is 3,000 and 25,000 + 3,000 = 28,000.

Common wrong step: subtracting 12% of 28,000 (₹3,360) to get ₹24,640. The 12% was taken on the old salary, not the new one.

Worked example 3: two years of growth. A town has 40,000 people. Its population grows 10% in the first year and 20% in the second. What is it after two years?

Use multipliers: $40000 \times 1.1 \times 1.2 = 40000 \times 1.32 = 52{,}800$. The overall rise is 32%, which is $10 + 20 + \dfrac{10 \times 20}{100}$.

Worked example 4: the flip. A's salary is 20% less than B's. By what percentage is B's salary more than A's?

Let B = 100, so A = 80. B exceeds A by 20, and the base is now A = 80, so the rise is $\dfrac{20}{80} \times 100 = 25\%$. The shortcut: "20% less" means a fall of $\dfrac{1}{5}$, so the reverse rise is $\dfrac{1}{5-1} = \dfrac{1}{4} = 25\%$.

Worked example 5: election. In an election 10% of the 20,000 votes cast are invalid. Candidate A gets 55% of the valid votes and the only other candidate B gets the rest. By how many votes does A win?

Step What we do Result
1 Valid votes = 90% of 20,000 18,000
2 A gets 55% of 18,000 9,900
3 B gets 45% of 18,000 8,100
4 Margin $9900 - 8100 = 1{,}800$

Common wrong step: taking 55% of 20,000. The percentage is of valid votes, not of all votes cast.

Worked example 6: constant expenditure. The price of sugar rises by 25%. By what percentage must a family cut consumption so that its spending stays the same?

Use $\dfrac{r}{100 + r} \times 100 = \dfrac{25}{125} \times 100 = 20\%$. Check with numbers: 10 kg at ₹40 costs ₹400. At ₹50 the same ₹400 buys 8 kg, which is a cut of 2 kg out of 10, or 20%. The cut is not 25%: after the rise the same money buys $\dfrac{1}{1.25} = 80\%$ of the old quantity, so the fall is 20%.

Part 5 — Worked examples: ratio, proportion, partnership, mixtures

Worked example 7: ratio changes after an addition. Two numbers are in the ratio 3 : 5. When 10 is added to each, the ratio becomes 5 : 7. Find the numbers.

Step What we do Result
1 Write the numbers as 3x and 5x $3x$, $5x$
2 Form the new ratio $\dfrac{3x + 10}{5x + 10} = \dfrac{5}{7}$
3 Cross-multiply $21x + 70 = 25x + 50$
4 Solve $x = 5$
5 Numbers 15 and 25

Check: 25 : 35 reduces to 5 : 7.

Worked example 8: joining two ratios. A : B = 2 : 3 and B : C = 4 : 5. Find A : B : C, and the three shares of ₹700.

Make B the same in both: scale the first by 4 and the second by 3. Then A : B = 8 : 12 and B : C = 12 : 15, so A : B : C = 8 : 12 : 15. The total is 35 units, one unit is ₹20, so the shares are ₹160, ₹240, ₹300.

Worked example 9: inverse proportion. 15 workers finish a job in 8 days. How long will 20 workers take?

More workers means fewer days, so the product is fixed: $15 \times 8 = 20 \times t$, giving $t = 6$ days.

Common wrong step: setting $15/8 = 20/t$ as if it were direct proportion, which gives 10.67 days, an answer that is larger even though there are more workers.

Worked example 10: partnership with different times. A invests ₹12,000 for 8 months and B invests ₹9,000 for 12 months. They earn ₹5,100. How is it shared?

Capital × time: A is $12000 \times 8 = 96000$ and B is $9000 \times 12 = 108000$. The ratio is 96 : 108 = 8 : 9, which is 17 parts. One part is $5100 \div 17 = 300$, that is ₹300. So A gets ₹2,400 and B gets ₹2,700.

Worked example 11: a partner who joins late. A starts a business with ₹20,000. After 4 months B joins with ₹30,000. At the end of the year the profit is ₹7,000. What does each get?

A's capital works for 12 months: $20000 \times 12 = 240000$. B's works for 8 months: $30000 \times 8 = 240000$. The ratio is 1 : 1, so each gets ₹3,500.

Worked example 12: alligation on price. In what ratio should rice at ₹30 per kg be mixed with rice at ₹40 per kg so that the mixture can be sold at ₹36 per kg with no gain or loss?

Step What we do Result
1 Cheaper = 30, dearer = 40, mean = 36 Mean lies between them
2 Distance of dearer from mean $40 - 36 = 4$
3 Distance of cheaper from mean $36 - 30 = 6$
4 Cheaper : dearer = 4 : 6 2 : 3

Note the cross: the quantity of the cheaper goes with the distance of the dearer from the mean. As a sense check, 36 is closer to 40, so you need more of the dearer rice (3 parts versus 2).

Worked example 13: adding water. A 45 L mixture has milk and water in the ratio 4 : 1. How much water must be added to make the ratio 3 : 2?

Milk = $\dfrac{4}{5} \times 45 = 36$ L and water = 9 L. Milk does not change, so 36 L must be 3 parts of the new ratio, giving one part = 12 L and water = 24 L. Water to add: $24 - 9 = $ 15 L.

Worked example 14: repeated replacement. A vessel holds 40 L of pure milk. 4 L is removed and replaced with water, and the same is done once more. How much pure milk is left?

Each step keeps a fraction $1 - \dfrac{4}{40} = 0.9$ of the milk. After two steps: $40 \times 0.9 \times 0.9 = 32.4$ L.

Common wrong step: subtracting 4 L twice to get 32 L. In the second step the 4 L removed is a mixture that already contains some water, so it carries less than 4 L of milk.

Part 6 — Common traps

Trap Why it is tempting The truth
Dividing by the new value The new value is the number you see last Percentage change is always on the old value
+20% then −20% is zero Plus and minus feel like they cancel Net is −4%, because the fall is on a bigger base
A is 25% more than B, so B is 25% less than A The same number appears twice B is 20% less. The base switched from B to A
Percentage point versus percent Both are written with the % sign A move from 20% to 25% is 5 percentage points, and a 25% relative rise
Using $15/8 = 20/t$ for workers and days Both pairs are "numbers" Workers and days are inverse, so the product is fixed
Cheaper : dearer written as (mean − cheaper) : (dearer − mean) The labels look natural It is crossed: cheaper goes with (dearer − mean)
Ratio read as B : A The question lists B first Read the order of the words: "A to B" is A : B
Subtracting the replaced amount each time Removal sounds like plain subtraction Each removal takes a mixture, so use the factor $(1 - x/V)$ per step

Part 7 — Rapid-fire practice with answers

Do these without a calculator, with the page covered, and check yourself afterwards.

No. Question Answer
1 37.5% of 640 240
2 $16\tfrac{2}{3}\%$ of 960 160
3 45 is what percent of 60? 75%
4 Rise from 250 to 300 is what percent? 20%
5 Fall from 300 to 250 is what percent? 16.67%
6 Two successive discounts of 20% and 30% equal one discount of 44%
7 Population grows 10% a year for 2 years: total growth 21%
8 Divide ₹1,000 in the ratio 3 : 7 ₹300 and ₹700
9 x : y = 3 : 4 and y : z = 6 : 5. Find x : y : z 9 : 12 : 10
10 Mean proportional of 9 and 25 15
11 24 men do a job in 10 days. Days for 16 men 15 days
12 3 L of 10% solution is mixed with 2 L of 20% solution. Strength of the mixture 14%
13 Price of an item rises 25%. Cut in consumption to keep spending fixed 20%
14 20% of 20% of 500 20
15 A is 20% less than B. B is what percent more than A? 25%

Part 8 — A timed-practice routine

Run this routine for one week and the whole topic becomes mental maths.

Day Task Time
1 Memorise the fraction and percentage table, then drill 20 quick "x% of y" questions 15 min
2 Solve worked examples 1 to 6 closed book, then write one line on which base each percentage used 25 min
3 Solve worked examples 7 to 14 closed book 30 min
4 Attempt the rapid-fire table against a clock: 15 questions in 12 minutes 12 min
5 Mixed set of 10 questions at 60 seconds each. Mark each as solved, guessed or skipped 10 min
6 Redo every question you got wrong or guessed, and write the rule that rescued it 20 min
7 Timed test of 15 questions in 15 minutes, and aim for 80% accuracy before you add speed 15 min

Marking rule for the exam. With +5 and −1, a guess between four options has an expected value of 0.25 × 5 − 0.75 × 1 = +0.5, so a guess is positive in expectation, but a blind guess is a gamble. Eliminate at least one option with a direction check first. Skip a question that needs more than 90 seconds and come back to it.

Part 9 — Where this connects

Percentage is the base for Profit, Loss and Interest, where the cost price is the base and a discount works on the marked price. Weighted means and age equations on the Averages and Ages page are alligation in another form. Inverse proportion drives Time, Speed and Work, and nearly every chart question in Data Interpretation asks for a percentage change or a ratio. For the mathematics behind repeated growth and decay, see Sequences and Series, because compounding is a geometric progression.

One-line revision: turn percentages into fractions or multipliers, divide the change by the old value, cut a ratio into equal units, keep the product fixed for inverse proportion, and cross the distances in alligation.

Practice questions

Now test yourself. 8 free sample questions with explanations. 32 more in the timed practice test.

Q1. The ratio of two numbers is $4:7$ and their LCM is $84$. What is the smaller number?

▸ Show answer & explanation

Answer: A

Let numbers be $4x$ and $7x$. Since $4$ and $7$ are coprime, LCM $=28x=84$, so $x=3$. Smaller number $=4\times3=12$.

Q2. Two numbers are in the ratio $5:7$. If $8$ is added to each, the ratio becomes $7:9$. What is the smaller of the two numbers?

▸ Show answer & explanation

Answer: B

Let the numbers be $5x$ and $7x$. Then $\frac{5x+8}{7x+8}=\frac{7}{9}$, so $9(5x+8)=7(7x+8)$, giving $45x+72=49x+56$, so $4x=16$ and $x=4$. The smaller number is $5\times4=20$.

Q3. The monthly incomes of A and B are in the ratio $5:4$ and their expenditures are in the ratio $3:2$. If each saves ₹6000 per month, what is A's monthly income?

▸ Show answer & explanation

Answer: A

Let incomes be $5x,4x$ and expenditures $3y,2y$. Then $5x-3y=6000$ and $4x-2y=6000$. From the second, $2x-y=3000$, so $y=2x-3000$. Substituting: $5x-3(2x-3000)=6000$, i.e. $5x-6x+9000=6000$, so $-x=-3000$, $x=3000$. A's income $=5\times3000=$ ₹15000.

Q4. A's income is $20\%$ more than B's, and B's income is $25\%$ more than C's. By what percentage is A's income more than C's?

▸ Show answer & explanation

Answer: A

Let C $=100$. Then B $=125$ and A $=1.20\times125=150$. So A exceeds C by $50\%$.

Q5. The sum of two numbers is $80$ and their ratio is $3:5$. What is the larger number?

▸ Show answer & explanation

Answer: A

Total parts $=3+5=8$ correspond to $80$, so one part $=10$. The larger number $=5\times10=50$.

Q6. In a mixture of $60$ litres, the ratio of milk to water is $2:1$. How much water must be added to make the ratio $1:2$?

▸ Show answer & explanation

Answer: A

Milk $=\frac{2}{3}\times60=40$ litres, water $=20$ litres. For ratio $1:2$ with milk fixed at $40$, water must be $80$ litres, so add $80-20=60$ litres.

Q7. Two-fifths of a number is $30$ more than one-fourth of the same number. What is the number?

▸ Show answer & explanation

Answer: B

Let the number be $x$. Then $\frac{2}{5}x-\frac{1}{4}x=30$, i.e. $\frac{8x-5x}{20}=30$, so $\frac{3x}{20}=30$, giving $3x=600$ and $x=200$.

Q8. A number when increased by $25\%$ gives $150$. What is the number?

▸ Show answer & explanation

Answer: A

Let the number be $x$. Then $1.25x=150$, so $x=\frac{150}{1.25}=120$.

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