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Ratio, Proportion & Percentage

Ratio, Proportion & Percentage is a frequently tested area in CUET General Test. Work through these free NTA-style sample questions with full answers and explanations, then attempt all 40 in a timed practice test to build exam-day speed.

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Snapshot

Part 1 — Percentage

"Percent" means "per hundred". What percent is A of B = (A ÷ B) × 100. X percent of N = (X ÷ 100) × N. Memorise these pairs so you never long-divide:

Fraction % Fraction % Fraction %
1/2 50 1/6 16.67 1/12 8.33
1/3 33.33 1/7 14.28 3/4 75
1/4 25 1/8 12.5 2/5 40
1/5 20 1/9 11.11 5/8 62.5

Percentage change = (new − old) ÷ OLD × 100 — always divide by the old value. Rise from 80 to 100 is 20 ÷ 80 = 25%, not 20%.

Successive change. Two changes of a% and b% combine to a + b + (ab ÷ 100) (use minus signs for decreases). A 20% rise then a 20% fall = 20 − 20 − 4 = a net 4% fall — never zero.

Reverse percentage. If a price after a 20% discount is ₹240, the original was 240 ÷ 0.8 = ₹300. If A is 25% more than B, then B is 20% less than A (not 25%) — because the base changes.

Percentage point vs percent. A share rising from 20% to 25% is 5 percentage points, but a 25% relative increase (5 ÷ 20). CUET offers both as options on purpose.

Part 2 — Ratio & Proportion

A ratio A : B compares two amounts, reduced to lowest terms. To divide a quantity in a ratio, add the parts to get total units, find one unit, then scale — the single most common ratio question:

Dividing ₹3,600 in the ratio 2 : 3 : 422%33%45%Ravi — ₹800 (2 parts)Sita — ₹1200 (3 parts)Mohan — ₹1600 (4 parts)

Split ₹3,600 in 2 : 3 : 4: total = 9 units, one unit = 3,600 ÷ 9 = ₹400 → shares ₹800, ₹1,200, ₹1,600.

A proportion says two ratios are equal: a : b = c : d means a × d = b × c (cross-multiply). In a continued proportion a : b = b : c, the middle term is the mean proportional, b = √(a × c) — mean proportional of 4 and 9 is √36 = 6.

Direct proportion: more of one ⇒ more of the other (workers ↔ output); the ratio stays constant. Inverse proportion: more of one ⇒ less of the other (workers ↔ time); the product stays constant. Compound proportion chains several together (men, days and hours in the classic "work" formula M₁D₁H₁ ÷ W₁ = M₂D₂H₂ ÷ W₂).

Partnership. Profit is shared in the ratio of (capital × time) for each partner. If A invests ₹x for 12 months and B invests ₹y for 6 months, their profit ratio is 12x : 6y.

Part 3 — Mixtures & Alligation

When two ingredients at different "prices" (or strengths) are mixed, the rule of alligation gives the mixing ratio in one line:

(quantity of cheaper) : (quantity of dearer) = (dearer − mean) : (mean − cheaper).

Alligation: mix ₹60 milk with ₹0 water to get ₹40 milk60dearer (milk)0cheaper (water)40mean price40 − 0 = 4060 − 40 = 20milk : water = 40 : 20 = 2 : 1

So to get ₹40 "milk" by mixing ₹60 milk with free water, milk : water = (40 − 0) : (60 − 40) = 2 : 1. Alligation also answers "what fraction is water" and "replacement" sums (the repeated replacement result: after removing and replacing x from a vessel of V, n times, the pure quantity left = V(1 − x/V)ⁿ).

Part 4 — Speed techniques

  1. Convert every percentage to a fraction before multiplying: 37.5% of 800 = 3/8 × 800 = 300.
  2. Flip the percentage when one number is friendly: 16% of 25 = 25% of 16 = 4.
  3. Anchor to 10% and 1%: 23% of 350 = (10% × 2) + (1% × 3) = 70 + 10.5 = 80.5.
  4. Use unit value for ratios — find one part, then every share is one multiplication.
  5. Use complements: if 35% is spent, compute the 65% that remains if it is friendlier.
  6. For "x% more / less", remember the base flips — +25% one way is −20% the other.
  7. Sanity-check direction — an increase answer must exceed the original; a discount answer must be smaller.

Part 5 — Worked examples

1. Successive change. A number is increased 25% then decreased 20%. Net? 25 − 20 − (25×20÷100) = 0% — no change.

2. Reverse percentage. After a 12% rise, a salary is ₹28,000. Original? 28,000 ÷ 1.12 = ₹25,000.

3. Divide in a ratio. Split ₹6,300 among A, B, C in 2 : 3 : 4. 9 units = 6,300 → unit = 700 → ₹1,400, ₹2,100, ₹2,800.

4. Inverse proportion. 15 workers finish a job in 8 days; how long for 20 workers? 15×8 = 20×t → t = 6 days.

5. Mean proportional. Mean proportional of 8 and 32 = √(8×32) = √256 = 16.

6. Partnership. A puts ₹12,000 for 8 months, B ₹9,000 for 12 months. Profit ratio? (12000×8) : (9000×12) = 96 : 108 = 8 : 9.

7. Alligation. In what ratio mix rice at ₹30/kg and ₹40/kg to sell the mix at ₹36/kg? cheaper : dearer = (40−36):(36−30) = 4 : 6 = 2 : 3.

8. Replacement. From 40 L of pure milk, 4 L is removed and replaced with water, twice. Milk left? 40(1 − 4/40)² = 40 × (0.9)² = 32.4 L.

Part 6 — Common traps

Part 7 — How to use this page

Memorise the fraction–percent table and the alligation rule, re-solve the eight examples with the page hidden, then attempt the practice set below — for each miss, name the rule that caught you — and finish with the timed test.

One-line revision: convert percentages to fractions, divide percentage change by the old value, split a quantity by finding one unit first, keep the product constant for inverse proportion, and reach for the alligation cross whenever two things are mixed.

Practice questions

Now test yourself. 8 free sample questions with explanations. 32 more in the timed practice test.

Q1. The ratio of two numbers is $4:7$ and their LCM is $84$. What is the smaller number?

▸ Show answer & explanation

Answer: A

Let numbers be $4x$ and $7x$. Since $4$ and $7$ are coprime, LCM $=28x=84$, so $x=3$. Smaller number $=4\times3=12$.

Q2. Two numbers are in the ratio $5:7$. If $8$ is added to each, the ratio becomes $7:9$. What is the smaller of the two numbers?

▸ Show answer & explanation

Answer: B

Let the numbers be $5x$ and $7x$. Then $\frac{5x+8}{7x+8}=\frac{7}{9}$, so $9(5x+8)=7(7x+8)$, giving $45x+72=49x+56$, so $4x=16$ and $x=4$. The smaller number is $5\times4=20$.

Q3. The monthly incomes of A and B are in the ratio $5:4$ and their expenditures are in the ratio $3:2$. If each saves ₹6000 per month, what is A's monthly income?

▸ Show answer & explanation

Answer: A

Let incomes be $5x,4x$ and expenditures $3y,2y$. Then $5x-3y=6000$ and $4x-2y=6000$. From the second, $2x-y=3000$, so $y=2x-3000$. Substituting: $5x-3(2x-3000)=6000$, i.e. $5x-6x+9000=6000$, so $-x=-3000$, $x=3000$. A's income $=5\times3000=$ ₹15000.

Q4. A's income is $20\%$ more than B's, and B's income is $25\%$ more than C's. By what percentage is A's income more than C's?

▸ Show answer & explanation

Answer: A

Let C $=100$. Then B $=125$ and A $=1.20\times125=150$. So A exceeds C by $50\%$.

Q5. The sum of two numbers is $80$ and their ratio is $3:5$. What is the larger number?

▸ Show answer & explanation

Answer: A

Total parts $=3+5=8$ correspond to $80$, so one part $=10$. The larger number $=5\times10=50$.

Q6. In a mixture of $60$ litres, the ratio of milk to water is $2:1$. How much water must be added to make the ratio $1:2$?

▸ Show answer & explanation

Answer: A

Milk $=\frac{2}{3}\times60=40$ litres, water $=20$ litres. For ratio $1:2$ with milk fixed at $40$, water must be $80$ litres, so add $80-20=60$ litres.

Q7. Two-fifths of a number is $30$ more than one-fourth of the same number. What is the number?

▸ Show answer & explanation

Answer: B

Let the number be $x$. Then $\frac{2}{5}x-\frac{1}{4}x=30$, i.e. $\frac{8x-5x}{20}=30$, so $\frac{3x}{20}=30$, giving $3x=600$ and $x=200$.

Q8. A number when increased by $25\%$ gives $150$. What is the number?

▸ Show answer & explanation

Answer: A

Let the number be $x$. Then $1.25x=150$, so $x=\frac{150}{1.25}=120$.

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