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Direction Sense

Direction Sense is a frequently tested area in CUET General Test. Work through these free NTA-style sample questions with full answers and explanations, then attempt all 35 in a timed practice test to build exam-day speed.

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Snapshot

Part 1 — The compass and the turning rule

Written and reviewed by Devendra Dubey, Mathematics & Commerce faculty at UniDrill (M.Sc. Mathematics, Osmania University · 10 years teaching). Prepared for the CUET UG General Test.

Every direction question lives on one picture: North at the top of your page, East on the right, South at the bottom, West on the left, and the four diagonals (NE, SE, SW, NW) halfway between. Draw it before you read the question twice.

Compass and the turning ruleNSEWNESESWNWRight turn = clockwiseN → E → S → W → NLeft turn = anticlockwiseN → W → S → E → NStart the rotation from your current heading

The only rule you must never break: a turn is measured from the direction you are facing at that moment. If you are walking South and turn left, you go East, because East is on the left-hand side of someone facing South. It is not West and it is not "left of North". The table below fixes all sixteen cases.

Facing now Turn left (90°) Turn right (90°) Turn back (180°)
North West East South
East North South West
South East West North
West South North East

For turns that are not 90°, give each direction a bearing in degrees measured clockwise from North: $N = 0^\circ$, $NE = 45^\circ$, $E = 90^\circ$, $SE = 135^\circ$, $S = 180^\circ$, $SW = 225^\circ$, $W = 270^\circ$, $NW = 315^\circ$. A right turn of $\theta$ adds $\theta$, a left turn subtracts $\theta$, and you subtract or add $360^\circ$ whenever the answer leaves the range $0^\circ$ to $360^\circ$. This turns every angle question into one line of arithmetic.

Part 2 — The method, step by step

Use the same routine on every question and your speed will come from habit, not luck.

  1. Draw the compass cross (a plus sign) with N at the top, and mark the start with a dot.
  2. Write the facing direction at the start. If the question does not say, the first leg tells you.
  3. Draw each leg as an arrow in its true direction with its length written on it.
  4. Update the facing after every turn using the table or the bearing trick, and write it next to the corner.
  5. Add the legs on each axis separately. East is positive and West negative on the horizontal axis. North is positive and South negative on the vertical axis.
  6. Read the answer from the two net numbers: their signs give the direction (net 6 East and 8 North means North-East), and the straight-line distance is $\sqrt{h^2 + v^2}$.
  7. Re-read the question to see whether it wants the direction faced, the direction of the position, the distance, or the total distance walked. These are four different answers to the same path.

Part 3 — The full menu of question types

Type What is asked Tool
Direction faced "Which direction is he facing now?" Turn table or bearing arithmetic
Direction of position "In which direction is he from the starting point?" Signs of the net East-West and North-South totals
Shortest distance "How far is he from the start?" $\sqrt{h^2+v^2}$ and Pythagorean triples
Total distance walked "How far did he walk in all?" Add every leg, including a return trip
Angle turns "Turns 135° clockwise" or "45° anticlockwise" Bearings
Landmark chains "A is north of B, C is east of B…" Place B at the centre, add one point at a time
Two walkers Two people leave one point in different directions Right triangle between them
Shadow and sun Morning or evening shadow falls to a person's left or right Sunrise East, shadow West; sunset West, shadow East
Clock and compass "12 on the dial faces North, where does the hand point?" Hour hand moves $30^\circ$ per hour; minute hand $6^\circ$ per minute

Part 4 — Distance, Pythagoras and the triples

After step 5 of the method you hold two numbers: the net horizontal movement $h$ and the net vertical movement $v$. The straight-line distance from the start is the hypotenuse of a right triangle with those two sides.

$$d = \sqrt{h^2 + v^2}$$

The examiner almost always picks numbers that make the square root a whole number. Learn these triples by heart, along with their multiples, and you will skip the calculation.

Triple Common multiples
3, 4, 5 6, 8, 10 and 9, 12, 15 and 12, 16, 20 and 15, 20, 25
5, 12, 13 10, 24, 26 and 15, 36, 39
8, 15, 17 16, 30, 34
7, 24, 25 14, 48, 50
20, 21, 29 none usually asked

If the legs are equal, say 12 and 12, the distance is $12\sqrt{2} \approx 17$. Distance is always positive and never larger than the total walked, because a straight line is the shortest path between two points. If the net horizontal or vertical movement is zero, the person is on a straight line from the start and no Pythagoras is needed.

Part 5 — Shadows and the sun

The sun rises in the East and sets in the West, and a shadow always falls away from the sun.

Time Sun is in Shadow falls towards A person facing the sun has the shadow
Sunrise or early morning East West behind them
Sunset or evening West East behind them
Noon overhead almost no shadow no direction can be fixed

Method for shadow questions: first write which way the shadow falls (West in the morning, East in the evening). Then match that direction with the person's left, right, front or back. For example, "the shadow falls to his right in the morning" means his right-hand side is West, so he is facing South, because West is on the right of someone facing South. Whenever two people stand back to back, their facing directions are exactly opposite.

Part 6 — Worked examples

Example 1. Distance and direction. A man walks 6 km North, turns right and walks 8 km. How far is he from the start and in which direction?

North 6, then right of North is East, so East 8. Net: 8 East, 6 North, so he is North-East of the start. Distance $=\sqrt{8^2+6^2}=\sqrt{100}=$ 10 km, North-East.

Example 2. Successive 90° turns. A person faces West, turns left, then right, then right. Which direction does he face?

West, turn left gives South. South, turn right gives West. West, turn right gives North. He faces North. With bearings: $270^\circ - 90^\circ + 90^\circ + 90^\circ = 360^\circ = 0^\circ$, which is North.

Example 3. An angle turn. Facing North, a girl turns $90^\circ$ clockwise and then $135^\circ$ anticlockwise. Which direction does she face?

Bearing: $0^\circ + 90^\circ - 135^\circ = -45^\circ$, and adding $360^\circ$ gives $315^\circ$. That is North-West.

Example 4. Mixed angles. A boy faces South-East, turns $90^\circ$ anticlockwise and then $45^\circ$ clockwise. Which direction does he face?

South-East is $135^\circ$. Then $135^\circ - 90^\circ + 45^\circ = 90^\circ$, which is East.

Example 5. A three-leg path with a triple. A girl walks 20 m North, turns right and walks 5 m, then turns right again and walks 8 m. How far is she from the start?

20 m N, 5 m E, 8 m Sstart20 m N5 m E8 m SNet: 5 m East and 12 m NorthDistance = 13 m, North-EastN

Facing North, a right turn gives East (5 m), and another right turn gives South (8 m). Net East $=5$ m. Net North $=20-8=12$ m. Distance $=\sqrt{5^2+12^2}=$ 13 m, North-East (the 5, 12, 13 triple).

Example 6. Left, left, right. A man walks 10 km West, turns left and walks 5 km, turns left and walks 10 km, then turns right and walks 5 km. Where is he relative to the start?

West 10 puts him at 10 West of the start. Turning left from West gives South, so he walks 5 South. Turning left from South gives East, so he walks 10 East, which brings him back to the start's North-South line, 5 South of it. Turning right from East gives South, so he walks 5 more South. Final position: 10 km due South of the start, facing South. The total he walked is $10+5+10+5=30$ km, a different answer to a different question.

Example 7. Legs that cancel. From home Ravi walks 10 km East, 6 km North, 4 km West and 6 km South. Where is he now?

East-West: $+10-4=+6$ (East). North-South: $+6-6=0$. He is 6 km East of home, and no square root is needed.

Example 8. Total distance with a return trip. A runner goes 4 km North, 3 km East, and then returns to the start by the shortest route. What is the total distance run?

The return leg is the hypotenuse $\sqrt{4^2+3^2}=5$ km. Total $=4+3+5=$ 12 km.

Example 9. A landmark chain. A is to the north of B. C is to the east of B. D is to the south of C. In which direction is D from A?

Put B at the centre. A is above B. C is to the right of B. D is directly below C, so D is on the right and below the line through B. A is above that line. So D is South-East of A.

Example 10. A morning shadow. One morning, Vikram and Shailesh stand back to back on a lawn. Vikram's shadow falls exactly to his left. Which way is Shailesh facing?

Morning shadows fall West, so Vikram's left is West. A person whose left is West faces North (facing North, left is West). Shailesh stands back to back with him, so he faces South.

Example 11. An evening shadow. At sunset, Meena's shadow falls on her right-hand side. Which way is she facing?

At sunset the shadow falls East, so her right is East. Facing North puts East on the right. She faces North.

Example 12. Clock and compass. A wall clock is placed so that the 12 mark points North. In which directions do the hour and minute hands point at 4:30?

The minute hand is at 30 minutes, which is $30\times 6^\circ = 180^\circ$, so it points South. The hour hand is at $4.5\times 30^\circ = 135^\circ$, so it points South-East.

Example 13. Two walkers. Two friends start from the same point. Asha walks 15 km South and Bela walks 8 km West. How far apart are they, and where is Bela relative to Asha?

Asha is 15 below the start and Bela is 8 to its left, so the legs of the triangle are 15 and 8. Distance $=\sqrt{15^2+8^2}=$ 17 km (the 8, 15, 17 triple). Bela is above and to the left of Asha, so Bela is North-West of Asha.

Part 7 — Common traps

Trap What goes wrong The fix
Turning from North "Facing South, turn left" answered as West Always rotate from the current heading
Left and right swap Mixing which hand is which when facing South or West Use the table in Part 1 or the bearing trick
Total versus straight-line Giving the path length when the question says "distance from the start" Read the question word: "walked" is total, "from the start" is straight line
Forgetting Pythagoras Adding 5 and 12 to get 17 Net East-West and North-South are the legs of a right triangle
Shadow direction Believing a morning shadow falls East Shadow points away from the sun: sunrise East, shadow West
Reversed relationship If A is North-East of B, saying B is North-East of A The reverse direction is the exact opposite: B is South-West of A
Not cancelling Adding 10 East and 4 West as 14 Opposite directions on one axis subtract
Angle sign error Subtracting for a right turn Right adds to the bearing, left subtracts

Part 8 — Rapid-fire practice with answers

Cover the answer column and solve each in under a minute.

No. Question Answer
1 Facing East, a man turns right, then right again. Which way does he face? West
2 Facing North-West, a girl turns $90^\circ$ clockwise. Which way does she face? North-East
3 A man walks 7 km West and then 24 km North. How far is he from the start? 25 km, North-West
4 Walk 6 km North, 6 km East, 6 km South, 6 km West. Where does the person end up? At the starting point
5 A boy walks 9 km South and then 12 km East. Shortest distance from the start? 15 km, South-East
6 Facing South, a woman turns left and then left again. Which way does she face? North
7 In the morning, a boy's shadow falls directly behind him. Which way does he face? East
8 At sunset, a boy's shadow falls directly in front of him. Which way does he face? East
9 P is South-West of Q. In which direction is Q from P? North-East
10 Facing North, a man turns $135^\circ$ right and then $45^\circ$ left. Which way does he face? East
11 A man walks 10 km West, 5 km North, 6 km East, 5 km South. Where is he from the start? 4 km West
12 Facing East, a person turns $90^\circ$ anticlockwise twice. Which way does he face? West
13 Facing North, a man turns right, right and then left. Which way does he face? East

Part 9 — A timed-practice routine

Direction questions reward repetition more than any other reasoning topic, because the method never changes. Follow this ladder over two weeks.

Stage What to do Target
Days 1 to 2 Redraw the compass and the turn table from memory ten times. Re-solve Examples 1 to 13 without looking Table recalled in 20 seconds
Days 3 to 4 Do only angle and bearing questions (Examples 3 and 4 style), ten at a time 20 seconds each
Days 5 to 7 Mixed path questions with distance. Write the two net totals before you take the square root 45 seconds each
Week 2 Timed sets of 10 mixed questions, including shadow and clock 8 minutes per set, at most one wrong

After each set, tick one cause for every wrong answer: wrong heading, wrong arithmetic, wrong question word. If the same cause appears twice, add a sentence about it to your notes. In the exam, give a direction question no more than 60 seconds. If the path has more than five legs and no triple in sight, finish the easier questions first and return.

Part 10 — Where this connects

Direction sense shares its habits with other General Test reasoning topics. The left-right discipline carries over to Ranking & Arrangement, where people face North, South or the centre of a table. The "draw it, then read it" habit is the same one used in Blood Relations. The right-triangle step and the triples are developed further in Mensuration & Basic Geometry, and the figure-rotation ideas appear again in Non-Verbal Reasoning.

One-line revision: draw with North up, rotate every turn from the current heading (right adds, left subtracts on a bearing), add each axis separately, use $\sqrt{h^2+v^2}$ for distance, and remember that shadows point away from the sun.

Practice questions

Now test yourself. 8 free sample questions with explanations. 27 more in the timed practice test.

Q1. Rohan goes $5$ km North, $5$ km East, $5$ km South, $5$ km West. Where is he with respect to the start?

▸ Show answer & explanation

Answer: A

North–South cancel ($5-5=0$) and East–West cancel ($5-5=0$). He returns exactly to the starting point.

Q2. Sita walks $7$ km East, $7$ km North, $7$ km West and $7$ km North. How far is she from the start?

▸ Show answer & explanation

Answer: B

Net East–West: $7-7=0$. Net North: $7+7=14$ km. She ends $14$ km due North of start, so the distance is $14$ km.

Q3. A man walks $5$ km towards North, then turns right and walks $3$ km, then turns right again and walks $5$ km. In which direction is he now facing?

▸ Show answer & explanation

Answer: B

Start facing North. First right turn makes him face East; second right turn makes him face South. After the last walk he is still facing South.

Q4. A man drives $5$ km North, then $12$ km East, then $9$ km North, then $12$ km West. How far is he from the starting point?

▸ Show answer & explanation

Answer: C

Net East–West: $12-12=0$. Net North: $5+9=14$ km. He ends $14$ km due North; distance $=14$ km.

Q5. A person walks $12$ km East, then turns right and walks $5$ km. What is his straight-line distance from the starting point?

▸ Show answer & explanation

Answer: A

Facing East, a right turn gives South. The legs are perpendicular: $\sqrt{12^2+5^2}=\sqrt{144+25}=\sqrt{169}=13$ km.

Q6. A man starts walking towards South. After walking $40$ m he turns to his left and walks $30$ m. Then he turns right and walks $20$ m. In which direction is he from the starting point?

▸ Show answer & explanation

Answer: C

South $40$; left→East $30$; right→South $20$. Net South $=40+20=60$ m, net East $=30$ m. Being South and East of start, the direction is South-East.

Q7. A man goes $10$ m North, $6$ m East, $2$ m South and $6$ m West. How far is he from the start?

▸ Show answer & explanation

Answer: A

Net North–South: $10-2=8$ m North. Net East–West: $6-6=0$ m. So he is exactly $8$ m North of start, a straight-line distance of $8$ m.

Q8. A man walks $8$ km East, turns left and walks $6$ km, turns left and walks $16$ km. What is the shortest distance from his starting point?

▸ Show answer & explanation

Answer: C

East $8$; left→North $6$; left→West $16$. Net E–W: $16-8=8$ km West. Net North: $6$ km. Distance $=\sqrt{8^2+6^2}=\sqrt{64+36}=\sqrt{100}=10$ km.

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