Time-Speed-Distance & Time-Work
Time-Speed-Distance & Time-Work is a frequently tested area in CUET General Test. Work through these free NTA-style sample questions with full answers and explanations, then attempt all 40 in a timed practice test to build exam-day speed.
Snapshot
- Time-Speed-Distance (TSD) and Time & Work are two faces of the same idea: a rate acting over time produces an output (distance, or work done). Master the rate idea and trains, boats, pipes and "A and B together" all become one method.
- TSD's core is the triangle Distance = Speed × Time; Work's core is Work = Rate × Time, where one person's rate is 1 ÷ (days they take alone).
- This guide covers unit conversion, average and relative speed, trains, boats & streams, and time–work including pipes & cisterns — with worked examples for each.
- Exam reality: +5 / −1. Set the rate, watch the units, and these are quick marks.
Part 1 — Speed, Distance, Time
Distance = Speed × Time. Rearrange as needed: Speed = D ÷ T, Time = D ÷ S. The one conversion you must own:
km/h → m/s: multiply by 5/18. m/s → km/h: multiply by 18/5. (72 km/h = 72 × 5/18 = 20 m/s.)
When distance is constant, time and speed are inversely proportional — double the speed, halve the time. So "if speed increases by 25%, time falls by 20%" (the base-flip from the percentage guide).
Part 2 — Average & Relative Speed
Average speed = total distance ÷ total time — never the simple average of the speeds. For a journey covering equal distances at speeds a and b, average speed is the harmonic mean 2ab ÷ (a + b).
Relative speed is how fast one object closes on another:
Moving toward each other, speeds add; moving in the same direction, speeds subtract. Time to meet = (gap between them) ÷ (relative speed).
Part 3 — Trains, Boats & Streams
Trains. A train crossing a pole travels its own length; crossing a platform travels (length of train + length of platform). Two trains crossing each other travel the sum of their lengths at their relative speed.
Boats & streams. With stream speed s and boat speed b in still water: downstream speed = b + s, upstream speed = b − s. Reverse-engineering: b = ½(downstream + upstream), s = ½(downstream − upstream).
Part 4 — Time & Work
One worker who finishes a job in a days has a rate of 1/a per day. Working together, rates add: A (1/a) and B (1/b) together do 1/a + 1/b per day, finishing in ab ÷ (a + b) days.
Pipes & cisterns is the same idea — a filling pipe has a positive rate, a leak/outlet a negative one; add them. Men–days–hours: for two situations doing the same kind of work, M₁ D₁ H₁ ÷ W₁ = M₂ D₂ H₂ ÷ W₂ (the compound-proportion formula).
Part 5 — Speed techniques
- Convert with 5/18 (or 18/5) on sight — most train/speed sums hide a unit change.
- Use inverse proportion for constant distance — set up speed₁ × time₁ = speed₂ × time₂.
- For "together", add rates, not days — the classic error is averaging the days.
- Take total work as the LCM of the days to avoid fractions (job = LCM(a, b) units).
- Average speed for equal distances is harmonic — 2ab/(a+b), never (a+b)/2.
- For a leak, subtract its rate — a tank "filled in x but leak empties in y" fills in xy/(y−x).
Part 6 — Worked examples
1. Conversion. A train at 90 km/h crosses a 200 m pole-to-platform... first, 90 km/h = 25 m/s.
2. Average speed. Goes at 40, returns at 60 (equal distance). Average = 2×40×60/(100) = 48 km/h.
3. Relative (opposite). Two trains 120 m and 130 m long run toward each other at 40 and 50 km/h. Time to cross? rel speed = 90 km/h = 25 m/s; total length 250 m; time = 250 ÷ 25 = 10 s.
4. Train + platform. A 150 m train at 20 m/s crosses a 250 m platform in (150+250)/20 = 20 s.
5. Boats. A boat does 16 km downstream and 8 km upstream, each in 2 h. Speeds: down 8, up 4 → boat = 6 km/h, stream = 2 km/h.
6. Work together. A does a job in 12 days, B in 18. Together? 12×18/(12+18) = 216/30 = 7.2 days.
7. Work with LCM. A (10 days) and B (15 days): job = LCM 30 units; A = 3/day, B = 2/day; together 5/day → 6 days.
8. Pipes. Pipe fills a tank in 6 h, leak empties in 9 h. Net fill = 6×9/(9−6) = 54/3 = 18 h.
Part 7 — Common traps
- Unit mismatch — convert km/h ↔ m/s before using a length in metres.
- Average speed is harmonic for equal distances — not the mean of the speeds.
- "Together" adds rates, not days.
- Pole vs platform — a pole adds only the train's length; a platform adds both lengths.
- Upstream is b − s, not s − b — the boat must beat the current.
Part 8 — How to use this page
Lock the 5/18 conversion, the harmonic-mean rule, and "add rates for together", re-solve the eight examples closed-book, then attempt the practice set and the timed test.
One-line revision: D = S × T, convert with 5/18, average speed for equal distances is 2ab/(a+b), relative speed adds when opposite and subtracts when same-way, and for work add rates (or use the LCM of the days).
Practice questions
Now test yourself. 8 free sample questions with explanations. 32 more in the timed practice test.
Q1. A and B can complete a work in $30$ days. They work together for $20$ days and then A leaves. B completes the remaining work in $20$ more days. In how many days can B alone complete the whole work?
▸ Show answer & explanation
Answer: A
In $20$ days together they finish $\frac{20}{30}=\frac{2}{3}$. B finishes remaining $\frac{1}{3}$ in $20$ days, so B's full work $=20\times3=60$ days.
Q2. Pipe A can fill a tank in $20$ minutes and pipe B in $30$ minutes. Both are opened together, but after some time pipe A is closed and the tank gets completely filled in $18$ minutes in total. After how many minutes from the start was A closed?
▸ Show answer & explanation
Answer: A
B runs for the full $18$ minutes: $\frac{18}{30}=\frac{3}{5}$ of the tank. A must supply the remaining $\frac{2}{5}$ at rate $\frac{1}{20}$, taking $\frac{2}{5}\times20=8$ minutes, so A was closed after $8$ minutes.
Q3. Two trains running in opposite directions at $54$ km/h and $36$ km/h cross each other in $12$ seconds. If one train is $120$ m long, what is the length of the other train?
▸ Show answer & explanation
Answer: A
Relative speed $=54+36=90$ km/h $=25$ m/s. Total length $=25\times12=300$ m. Other train $=300-120=180$ m.
Q4. A man covers half of his journey at $30$ km/h and the other half at $20$ km/h. What is his average speed for the entire journey?
▸ Show answer & explanation
Answer: A
For equal distances, average speed $=\frac{2\times30\times20}{30+20}=\frac{1200}{50}=24$ km/h.
Q5. Three pipes can fill a tank in $10$, $15$ and $30$ hours respectively. If all three are opened together, in how many hours is the tank filled?
▸ Show answer & explanation
Answer: A
Combined rate $=\frac{1}{10}+\frac{1}{15}+\frac{1}{30}=\frac{3+2+1}{30}=\frac{6}{30}=\frac{1}{5}$ per hour, so $5$ hours.
Q6. A group of $8$ women can complete a work in $10$ days, while a group of $10$ children can complete the same work in $20$ days. In how many days will the $8$ women and $10$ children together complete the work?
▸ Show answer & explanation
Answer: A
The women's group rate $=\frac{1}{10}$ and the children's group rate $=\frac{1}{20}$. Together $=\frac{1}{10}+\frac{1}{20}=\frac{2+1}{20}=\frac{3}{20}$ per day, so the work takes $\frac{20}{3}$ days.
Q7. Two pipes A and B can fill a tank in $20$ minutes and $30$ minutes respectively. If both pipes are opened together, how long will it take to fill the tank?
▸ Show answer & explanation
Answer: A
Combined rate $=\frac{1}{20}+\frac{1}{30}=\frac{3+2}{60}=\frac{5}{60}=\frac{1}{12}$ per minute, so the tank fills in $12$ minutes.
Q8. A boat covers $8$ km upstream and $36$ km downstream in $5$ hours; it also covers $36$ km upstream and $12$ km downstream in $10$ hours. Find the speed of the boat in still water.
▸ Show answer & explanation
Answer: A
Let $x=\frac{1}{u}$ (upstream) and $y=\frac{1}{d}$ (downstream). Then $8x+36y=5$ and $36x+12y=10$. Solving gives $x=\frac{1}{4}$, $y=\frac{1}{12}$, so $u=4$, $d=12$. Still-water speed $=\frac{u+d}{2}=\frac{4+12}{2}=8$ km/h.
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