📌 Snapshot
- Studies physical properties of liquids and gases (collectively "fluids") that flow and offer almost no resistance to shear stress, distinguishing them from solids.
- Builds the hydrostatics block: pressure as a scalar normal-force-per-area, variation with depth, Pascal's law, hydraulic machines, atmospheric pressure, barometers and manometers.
- Develops fluid dynamics for ideal fluids: streamline vs turbulent flow, equation of continuity (Av = constant), and Bernoulli's principle with its applications — Torricelli's law of efflux and dynamic lift (Magnus effect, aerofoil).
- Introduces viscosity (Newton's law of viscous flow, coefficient eta), Stokes' law and terminal velocity of a sphere falling through a viscous medium.
- Ends with surface tension as surface energy per unit area, angle of contact, excess pressure inside drops and bubbles, and capillary rise.
📖 Detailed Notes
2.1 Core concepts
- Fluids (liquids + gases) flow because they offer negligible resistance to shear stress — about a million times smaller than that of solids — but liquids are largely incompressible while gases are highly compressible (NCERT §9.1, p. 180).
- Pressure at a point in a fluid is defined in the limiting sense P = lim (Delta F / Delta A) as Delta A tends to 0; only the component of force normal to the area enters the numerator. Pressure is a scalar with dimensions [M L^-1 T^-2] and SI unit pascal (Pa = N m^-2); 1 atm = 1.013 x 10^5 Pa (NCERT §9.2, p. 181).
- Density rho = m/V is a positive scalar with SI unit kg m^-3; relative density is the dimensionless ratio of a substance's density to that of water at 4 deg C (1.0 x 10^3 kg m^-3) (NCERT §9.2, p. 181).
- Considering a right-angled prismatic element of fluid at rest, equilibrium together with geometry gives Pa = Pb = Pc — pressure exerted is the same in all directions at a point, confirming pressure is not a vector (NCERT §9.2.1, p. 182).
- For two points 1 and 2 separated vertically by height h in a fluid at rest, balancing the weight of the cylindrical element gives (P2 - P1) = rho g h; taking point 1 at the open surface yields the absolute pressure P = Pa + rho g h, while P - Pa is the gauge pressure (NCERT §9.2.2, pp. 182–183).
- The hydrostatic paradox: vessels A, B and C of different shapes connected at the base fill to the same level on filling with water because the bottom pressure depends only on height of the fluid column, not on shape or base area (NCERT §9.2.2, p. 183).
- The atmospheric pressure at sea level equals the weight of an air column of unit area extending to the top of the atmosphere and is 1.013 x 10^5 Pa (1 atm). Torricelli's mercury barometer gives Pa = rho g h; the mercury column at sea level is about 76 cm, so 1 mm of Hg = 1 torr = 133 Pa and 1 bar = 10^5 Pa (NCERT §9.2.3, pp. 183–184).
- An open-tube manometer is a U-tube containing a suitable liquid (oil for small, mercury for large pressure differences); it measures the gauge pressure P - Pa proportional to the difference of liquid heights (NCERT §9.2.3, p. 184).
- Pascal's law for transmission of fluid pressure: a change in pressure applied to an enclosed fluid is transmitted undiminished and equally in all directions to every point of the fluid and the walls. In a hydraulic lift the small piston of area A1 exerts force F1 producing pressure P = F1/A1; the larger piston of area A2 then experiences force F2 = (A2/A1) F1, giving mechanical advantage A2/A1. The same principle is used in hydraulic brakes (NCERT §9.2.4, pp. 185–186).
- Steady (streamline) flow: at every fixed point, the velocity of each passing fluid particle is constant in time; the streamline is a curve whose tangent at any point gives the fluid velocity, and no two streamlines can cross (NCERT §9.3, pp. 186–187).
- Equation of continuity follows from conservation of mass: rho_P A_P v_P = rho_R A_R v_R = rho_Q A_Q v_Q; for an incompressible fluid this reduces to A v = constant, so velocity rises where the cross-section narrows (NCERT §9.3, p. 187).
- Beyond a critical speed, streamline flow loses steadiness and becomes turbulent — eddies and whirlpool-like white-water regions form (NCERT §9.3, p. 187).
- Bernoulli's principle: along a streamline of an ideal (non-viscous, incompressible, steady) flow, P + (1/2) rho v^2 + rho g h = constant. The derivation uses the work–energy theorem on an element pushed between two cross-sections at different heights (NCERT §9.4, pp. 187–188).
- Bernoulli's equation does NOT hold for viscous fluids, compressible fluids or non-steady/turbulent flows; for fluids at rest it reduces to P1 + rho g h1 = P2 + rho g h2, the hydrostatic relation (NCERT §9.4, p. 188).
- Torricelli's law of efflux: for a tank open to the atmosphere with a small hole at height y1 below the free surface (depth h = y2 - y1), Bernoulli's equation gives speed of efflux v1 = sqrt(2 g h), the same as that of a freely falling body; if a high pressure P drives the tank, v1 = sqrt(2 g h + 2(P - Pa)/rho), relevant to rocket propulsion (NCERT §9.4.1, pp. 188–189).
- Dynamic lift on a spinning ball (Magnus effect): a ball spinning while moving drags air with it, crowding streamlines on one side and rarifying them on the other; the resulting pressure difference deflects the ball from a parabolic path (NCERT §9.4.2, pp. 189–190).
- Aerofoil lift on aircraft wings: the wing shape and orientation makes air flow faster above than below; the pressure difference Delta P = (rho/2)(v2^2 - v1^2) provides upward dynamic lift balancing the weight (NCERT §9.4.2, p. 190; Example 9.7).
- Viscosity is the internal friction between adjacent layers of a fluid in relative motion; experimentally the shear stress depends on rate of strain (v/l), and the coefficient of viscosity eta = shear stress / strain rate. SI unit is the poiseuille (Pl) = N s m^-2 = Pa s; dimensions [M L^-1 T^-1]. Viscosity of liquids decreases while that of gases increases with temperature (NCERT §9.5, pp. 190–191).
- Stokes' law: a sphere of radius a moving with velocity v through a fluid of viscosity eta experiences a viscous drag F = 6 pi eta a v (NCERT §9.5.1, p. 192).
- A small sphere falling through a viscous fluid attains terminal velocity when (viscous drag + buoyant force) equals gravity; balancing gives 6 pi eta a vt = (4 pi/3) a^3 (rho - sigma) g, so vt = 2 a^2 (rho - sigma) g / (9 eta). Terminal velocity is proportional to square of radius and inversely to viscosity (NCERT §9.5.1, p. 192).
- Surface tension arises because molecules on the free surface have less negative potential energy than those in the bulk (about half), so increasing surface area requires work; consequently a liquid tends to minimise its free surface area (NCERT §9.6.1, p. 193).
- Stretching a film by distance d on parallel guides of length l increases area by 2 d l (two surfaces); the work F d done equals the surface energy S (2 d l), giving S = F / (2 l). Surface tension is therefore both surface energy per unit area and force per unit length acting in the plane of the interface (NCERT §9.6.2, p. 194).
- Angle of contact theta is measured between the tangent to the liquid surface at the line of contact and the solid surface, taken inside the liquid; equilibrium of interfacial tensions gives S_la cos theta + S_sl = S_sa. theta is acute when S_sl < S_la (water on glass — wets), obtuse when S_sl > S_la (water on lotus leaf, mercury on glass — does not wet) (NCERT §9.6.3, pp. 195–196).
- Wetting agents (soaps, detergents) lower the angle of contact so liquids penetrate better; water-proofing agents raise it (NCERT §9.6.3, p. 196).
- Free drops and bubbles tend to be spherical because a sphere has the least surface area for given volume. Excess pressure inside a spherical liquid drop or cavity is (Pi - Po) = 2 S_la / r; for a soap bubble, with two interfaces, the excess pressure is (Pi - Po) = 4 S_la / r (NCERT §9.6.4, pp. 196–197).
- Capillary rise: in a narrow tube of radius a with acute contact angle theta, the concave meniscus produces an excess pressure 2 S cos theta / a. Equating the hydrostatic head: h rho g = 2 S cos theta / a, so h = 2 S cos theta / (rho g a). For mercury (theta obtuse) cos theta is negative and the liquid is depressed in the capillary (NCERT §9.6.5, pp. 196–197).
2.2 Definitions to memorise
| Term | Definition | Page |
|---|---|---|
| Pressure (P) | Normal component of force per unit area on a surface in a fluid; scalar; SI unit Pa = N m^-2 | 181 |
| Pascal (Pa) | SI unit of pressure equal to 1 N m^-2; 1 atm = 1.013 x 10^5 Pa | 181 |
| Density (rho) | Mass per unit volume; SI unit kg m^-3; positive scalar | 181 |
| Relative density | Ratio of density of substance to density of water at 4 deg C; dimensionless | 181 |
| Gauge pressure | Excess of absolute pressure over atmospheric pressure, Pg = P - Pa = rho g h | 183 |
| Pascal's law | Pressure applied to an enclosed fluid is transmitted undiminished and equally in all directions | 185 |
| Streamline | Curve whose tangent at every point is in the direction of fluid velocity at that point in steady flow | 186 |
| Equation of continuity | A v = constant for an incompressible fluid in steady flow (conservation of mass) | 187 |
| Bernoulli's equation | P + (1/2) rho v^2 + rho g h = constant along a streamline of an ideal fluid | 188 |
| Torricelli's law | Speed of efflux from a small open hole at depth h below the free surface, v1 = sqrt(2 g h) | 189 |
| Dynamic lift | Force on a body (wing, spinning ball) due to motion through a fluid; explained by Bernoulli | 189 |
| Magnus effect | Dynamic lift on a spinning body due to streamline asymmetry caused by rotation | 189 |
| Coefficient of viscosity (eta) | Ratio of shear stress to strain rate; SI unit poiseuille (Pl) = Pa s; dimensions [M L^-1 T^-1] | 191 |
| Stokes' law | Viscous drag on a sphere of radius a moving with velocity v through a fluid: F = 6 pi eta a v | 192 |
| Terminal velocity | Constant velocity attained when net force is zero: vt = 2 a^2 (rho - sigma) g / (9 eta) | 192 |
| Surface tension (S) | Force per unit length in the plane of interface (or surface energy per unit area); units N m^-1 | 194 |
| Angle of contact (theta) | Angle between tangent to liquid surface at the contact line and the solid surface, measured inside the liquid | 195 |
| Excess pressure (drop) | (Pi - Po) = 2 S / r for a spherical liquid drop or cavity | 197 |
| Excess pressure (soap bubble) | (Pi - Po) = 4 S / r — two interfaces | 197 |
| Capillary rise (h) | h = 2 S cos theta / (rho g a) for a narrow tube of radius a | 197 |
2.3 Diagrams / processes to remember
- Fig. 9.1 — beaker with submerged object: fluid force is normal to every surface; idealised piston-spring pressure gauge (p. 181).
- Fig. 9.2 — right-angled prismatic fluid element used to prove that pressure at a point is the same in all directions (p. 182).
- Fig. 9.3 — vertical cylindrical column for deriving P2 - P1 = rho g h (p. 183).
- Fig. 9.4 — three differently shaped vessels A, B, C filled to the same level — hydrostatic paradox (p. 183).
- Fig. 9.5 — (a) mercury barometer and (b) open-tube manometer (p. 184).
- Fig. 9.6 — (a) external pressure applied to a fluid is transmitted equally to all vertical tubes; (b) schematic of a hydraulic lift (pp. 185–186).
- Fig. 9.7 — streamlines: (a) trajectory of one fluid particle; (b) region of streamline flow showing planes P, R, Q (p. 186).
- Fig. 9.8 — (a) laminar streamlines; (b) jet on a flat plate showing turbulent flow (p. 187).
- Fig. 9.9 — flow of an ideal fluid in a pipe of varying cross-section for Bernoulli derivation (p. 188).
- Fig. 9.10 — Torricelli's law: tank with hole, v1 = sqrt(2 g h) (p. 189).
- Fig. 9.11 — (a) non-spinning sphere (symmetric streamlines, zero lift); (b) spinning sphere — Magnus effect; (c) aerofoil (p. 190).
- Fig. 9.12 — (a) liquid sandwiched between glass plates with top plate moving; (b) parabolic velocity profile in a tube (p. 191).
- Fig. 9.13 — block-and-pulley setup to measure coefficient of viscosity (p. 191).
- Fig. 9.14 — molecules in the bulk, at the surface, and balance of attractive/repulsive forces (p. 193).
- Fig. 9.15 — soap film on a sliding bar — derivation S = F/(2l) (p. 194).
- Fig. 9.16 — vertical glass plate balance for measuring surface tension (p. 195).
- Fig. 9.17 — water drop on lotus leaf (obtuse contact angle) vs spreading on clean plastic (acute) (p. 195).
- Fig. 9.18 — drop, cavity and bubble of radius r — excess pressure formulae (p. 196).
- Fig. 9.19 — capillary rise schematic with enlarged meniscus (p. 196).
2.4 Common confusions / NTA trap points
- Pressure is a scalar, even though it is "force per area" — only the normal component of force enters; vector-pressure options are NTA's favourite distractor.
- For a soap bubble use 4 S / r (two interfaces), but for a liquid drop or an air cavity in a liquid use 2 S / r — many students apply the wrong formula in numerical MCQs.
- Bernoulli's principle assumes incompressible, non-viscous, steady (streamline) flow. It does NOT apply to turbulent flow, compressible flow, or flow with significant viscous losses (e.g. rapids in a river).
- For a sphere falling through a viscous fluid, the terminal velocity is proportional to a^2 (not a) and inversely to eta — questions deliberately swap the dependence.
- Viscosity behaves oppositely with temperature: liquids' viscosity decreases, gases' increases — a classic Assertion-Reason trap.
- For mercury in a capillary, cos theta is negative (theta obtuse), so the formula h = 2 S cos theta / (rho g a) gives a depression — students often forget the sign.
- Hydrostatic pressure depends only on the vertical height of the column, not on the shape or base area of the container (hydrostatic paradox).
🎯 Practice MCQs
First 3 questions free · create a free account to unlock the rest — answers & explanations included, no payment needed
Q1. Which of the following statements about pressure in a fluid at rest is correct?
▸ Show answer & explanation
Answer: B
The NCERT explicitly states that pressure is a scalar and uses the component of force normal to the area in the numerator; the prism-element proof on p. 182 also shows that pressure at a point is the same in all directions.
Q2. Three vessels A, B and C of different shapes are connected at the bottom by a horizontal pipe and filled with water to the same level. The pressure at the bottom of the three vessels is
▸ Show answer & explanation
Answer: C
The hydrostatic paradox shows pressure at the bottom depends only on the height of the fluid column (P = Pa + rho g h), not on shape or base area, so all three vessels show the same bottom pressure.
Q3. In a hydraulic lift the smaller piston has cross-sectional area A1 = pi (0.5 x 10^-2)^2 m^2 and the larger piston has A2 = pi (1.5 x 10^-2)^2 m^2. If a force of 10 N is applied on the smaller piston, the force on the larger piston is
▸ Show answer & explanation
Answer: C
By Pascal's law, F2 = (A2/A1) F1 = (1.5/0.5)^2 x 10 N = 9 x 10 N = 90 N, identical to the worked example.
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Q4. Bernoulli's equation P + (1/2) rho v^2 + rho g h = constant along a streamline is valid only when the fluid is
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Answer: C
NCERT specifies three assumptions: zero viscosity, incompressibility and steady (not turbulent) flow — only option C contains all three.
Q5. Water flows out of a small hole in the side of a large open tank at a depth of 5.0 m below the free surface. Taking g = 10 m s^-2, the speed of efflux is
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Answer: B
Torricelli's law gives v1 = sqrt(2 x 10 x 5) = sqrt(100) = 10 m s^-1.
Q6. A pipe of cross-sectional area 8.0 cm^2 carries a steady incompressible flow of liquid at 1.5 m s^-1. The pipe narrows to 2.0 cm^2. The speed in the narrow part is
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Answer: D
By the equation of continuity A1 v1 = A2 v2, so v2 = (8.0/2.0) x 1.5 = 6.0 m s^-1; at narrower sections the speed must be higher.
Q7. Match Column I (quantity) with Column II (SI unit / value) and choose the correct option. Column I — (i) Coefficient of viscosity eta ; (ii) Surface tension S ; (iii) 1 atm ; (iv) 1 torr Column II — (P) 1.013 x 10^5 Pa ; (Q) Pa s ; (R) 133 Pa ; (S) N m^-1
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Answer: A
SI unit of eta is Pa s (also poiseuille); of S is N m^-1; 1 atm = 1.013 x 10^5 Pa; 1 torr = 133 Pa — only (A) matches all four.
Q8. Assertion (A): The viscosity of a liquid decreases with rise in temperature, while that of a gas increases. Reason (R): With rising temperature the random molecular motion in a gas grows, whereas in a liquid the atoms become more mobile and slide past each other more easily.
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Answer: A
NCERT states that as temperature rises, atoms of a liquid become more mobile so eta falls, while in a gas the temperature rise increases the random motion of atoms and eta increases — R correctly explains A.
Q9. A small steel ball of radius 2.0 mm and density 8.9 x 10^3 kg m^-3 falls with terminal velocity through oil of density 1.5 x 10^3 kg m^-3 and viscosity 9.9 x 10^-1 Pa s. Taking g = 9.8 m s^-2, the terminal velocity is closest to
▸ Show answer & explanation
Answer: B
vt = 2 a^2 (rho - sigma) g / (9 eta) = 2 x (2 x 10^-3)^2 x (8.9 - 1.5) x 10^3 x 9.8 / (9 x 0.99) approximately 6.5 x 10^-2 m s^-1, matching NCERT Example 9.9.
Q10. The lower end of a capillary tube of internal radius 0.5 mm is dipped vertically in water. Taking surface tension of water S = 7.3 x 10^-2 N m^-1, angle of contact theta = 0 deg, rho = 10^3 kg m^-3 and g = 9.8 m s^-2, the height to which water rises in the capillary is approximately
▸ Show answer & explanation
Answer: C
h = 2 S cos theta / (rho g a) = (2 x 0.073) / (10^3 x 9.8 x 5 x 10^-4) approximately 2.98 x 10^-2 m approximately 3.0 cm — the worked example on p. 197 gives the same value.
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