📌 Snapshot
- Establishes that a wave is a propagating disturbance that transports energy and information without bulk transfer of matter through the medium.
- Classifies mechanical waves into transverse and longitudinal, and develops the sinusoidal travelling-wave description y(x, t) = a sin(kx − ωt + φ).
- Derives the speeds of mechanical waves — on a stretched string v = √(T/µ), in solids v = √(Y/ρ), in fluids v = √(B/ρ), and Newton-Laplace v = √(γP/ρ) for a gas.
- Builds the principle of superposition, reflection at rigid and free boundaries, and the resulting standing waves on strings and in pipes (with normal modes/harmonics).
- Closes with beats — slow waxing and waning of intensity at frequency ν_beat = |ν₁ − ν₂| when two close-frequency sounds interfere. CUET tests all four: travelling-wave parameters, wave-speed calculation, harmonics of strings/pipes, and beats.
📖 Detailed Notes
2.1 Core concepts
- A wave is a pattern of disturbance that moves through a medium without actual physical transfer of matter as a whole; the medium oscillates while energy and information propagate (NCERT §14.1, p. 278).
- Mechanical waves (string, water, sound, seismic) need an elastic medium and arise from coupling between oscillating constituents; electromagnetic waves do not need a medium and travel at c = 299,792,458 m s⁻¹ in vacuum; matter waves are associated with electrons, protons, atoms, etc. (NCERT §14.1, p. 279).
- In a transverse wave the constituents oscillate perpendicular to the direction of propagation (e.g. a wave on a stretched string); in a longitudinal wave they oscillate along the direction of propagation (e.g. sound in a long air-filled pipe with a piston) (NCERT §14.2, pp. 280–281).
- Transverse waves require shear elasticity, so they can propagate only in solids and on the surface of liquids; longitudinal waves need only bulk/compressional elasticity and so propagate in solids, liquids and gases. In steel both can propagate; in air only longitudinal (NCERT §14.2, p. 281; Points to ponder 4, p. 297).
- A sinusoidal travelling wave on a string is described by y(x, t) = a sin(kx − ωt + φ); for a longitudinal wave the same form is used with displacement s(x, t) (NCERT §14.3, p. 281; Eqs. 14.2 and 14.9, p. 283).
- Amplitude a is the maximum displacement of a particle from equilibrium; phase (kx − ωt + φ) determines the displacement at any (x, t); φ is the initial phase angle at x = 0, t = 0 (NCERT §14.3.1, p. 282).
- Wavelength λ is the minimum distance between two points of equal phase; angular wave number k = 2π/λ with SI unit rad m⁻¹ (NCERT §14.3.2, p. 283, Eq. 14.6).
- Period T is the time for one complete oscillation of a particle, angular frequency ω = 2π/T, and frequency ν = 1/T = ω/(2π), measured in hertz (NCERT §14.3.3, p. 283, Eqs. 14.7–14.8).
- Speed of a travelling wave is v = ω/k = λ/T = νλ; in one period the wave pattern advances exactly one wavelength (NCERT §14.4, p. 284, Eqs. 14.11–14.12).
- For a transverse wave on a stretched string with tension T and linear mass density µ = m/L, the speed is v = √(T/µ); it depends only on the medium, not on wavelength or frequency (NCERT §14.4.1, p. 285, Eq. 14.14).
- For a longitudinal wave in a fluid of bulk modulus B and density ρ, v = √(B/ρ); in a linear solid bar (Young's modulus Y), v = √(Y/ρ) (NCERT §14.4.2, p. 286, Eqs. 14.19–14.20).
- Newton's formula for sound in an ideal gas, treating compressions/rarefactions as isothermal, gives v = √(P/ρ) ≈ 280 m s⁻¹ at STP, about 15% below the measured 331 m s⁻¹ (NCERT §14.4.2, pp. 286–287, Eqs. 14.22–14.23).
- Laplace correction notes the variations are adiabatic (PVγ = constant), so the adiabatic bulk modulus is B_ad = γP and v = √(γP/ρ). For air γ = 7/5, giving 331.3 m s⁻¹, matching experiment (NCERT §14.4.2, p. 287, Eq. 14.24).
- Principle of superposition: when waves overlap, the net displacement is the algebraic sum y(x, t) = y₁(x, t) + y₂(x, t) + … = Σ fᵢ(x − vt); this principle underlies interference (NCERT §14.5, pp. 287–288, Eqs. 14.25–14.26).
- Two waves of equal a, k, ω differing in phase by φ add to y = 2a cos(φ/2) sin(kx − ωt + φ/2); φ = 0 gives constructive interference (amplitude 2a), φ = π gives destructive interference (zero displacement everywhere) (NCERT §14.5, p. 288, Eqs. 14.31–14.34).
- A wave reflected at a rigid boundary undergoes a phase change of π (the boundary point must remain at zero displacement); at an open/free boundary there is no phase change (NCERT §14.6, pp. 288–289, Eqs. 14.35–14.36).
- When two identical waves travel in opposite directions, superposition gives a standing wave y(x, t) = 2a sin kx cos ωt — same ω at every point but amplitude 2a sin kx varies with x. Points of zero amplitude are nodes; of maximum amplitude are antinodes; consecutive nodes (or antinodes) are λ/2 apart (NCERT §14.6.1, pp. 289–291, Eqs. 14.37–14.39).
- For a stretched string of length L fixed at both ends (nodes at both ends), L = nλ/2, so allowed wavelengths λ = 2L/n and frequencies νₙ = nv/(2L), n = 1, 2, 3 … — all harmonics are present; n = 1 gives fundamental ν₁ = v/(2L) (NCERT §14.6.1, p. 291, Eqs. 14.40–14.42).
- For a pipe closed at one end (node at closed end, antinode at open end), L = (n + ½)λ/2, so νₙ = (n + ½) v/(2L) for n = 0, 1, 2, … — only odd harmonics ν₁ = v/4L, 3v/4L, 5v/4L, … are present (NCERT §14.6.1, pp. 291–292, Eqs. 14.43–14.44).
- A pipe open at both ends has antinodes at both ends; like the string fixed at both ends, all harmonics are present with ν₁ = v/(2L), and νₙ = nv/(2L) (NCERT §14.6.1, p. 292; Example 14.5, p. 292).
- Beats occur when two harmonic sound waves of close (but unequal) frequencies superpose. The resultant has average angular frequency ωₐ = (ω₁ + ω₂)/2 modulated by amplitude that oscillates at 2ωᵦ = ω₁ − ω₂, so the audible beat frequency is ν_beat = |ν₁ − ν₂| (NCERT §14.7, pp. 293–294, Eqs. 14.45–14.48).
- The wave function y(x, t) must be a solution of the linear wave equation ∂²y/∂t² = v² ∂²y/∂x², so any function of the form f(x − vt) describes a wave travelling in the +x direction at speed v, and g(x + vt) describes one travelling in the −x direction (NCERT §14.3, p. 281).
- For sound in an ideal gas, v depends only on temperature (not on pressure) because P/ρ is set by T via the ideal-gas law; in air v ≈ 331 m s⁻¹ at 0 °C and increases by roughly 0.61 m s⁻¹ per °C rise — a standard NCERT remark (NCERT §14.4.2, p. 287).
- A travelling wave on a string transports both kinetic energy (oscillating string elements) and elastic potential energy (string segments alternately stretched); the average power transmitted is proportional to a²ω² so doubling either amplitude or frequency quadruples the power carried — relevant to NCERT examples on string waves (NCERT §14.4, p. 285).
2.2 Definitions to memorise
| Term | Definition | Page |
|---|---|---|
| Transverse wave | Wave in which constituents oscillate perpendicular to the direction of propagation. | 280 |
| Longitudinal wave | Wave in which constituents oscillate along the direction of propagation. | 280 |
| Amplitude (a) | Maximum displacement of a particle of the medium from its equilibrium position. | 282 |
| Wavelength (λ) | Minimum distance between two points having the same phase at a given instant. | 283 |
| Angular wave number (k) | k = 2π/λ; SI unit rad m⁻¹. | 283 |
| Period (T) | Time for one complete oscillation of a particle; T = 2π/ω. | 283 |
| Frequency (ν) | Number of oscillations per second; ν = 1/T = ω/2π, measured in hertz. | 283 |
| Wave speed (v) | Speed of propagation of a fixed phase point; v = ω/k = λ/T = νλ. | 284 |
| Speed on a stretched string | v = √(T/µ), with T the tension and µ the linear mass density. | 285 |
| Speed in a fluid | v = √(B/ρ), with B the bulk modulus and ρ the density. | 286 |
| Speed in a solid bar | v = √(Y/ρ), with Y Young's modulus and ρ density. | 286 |
| Newton-Laplace formula | Speed of sound in a gas v = √(γP/ρ), with γ = Cp/Cv. | 287 |
| Principle of superposition | Net displacement when waves overlap is the algebraic sum of the individual displacements. | 287 |
| Node | Point on a stationary wave where the amplitude is zero. | 290 |
| Antinode | Point on a stationary wave where the amplitude is maximum. | 290 |
| Fundamental frequency / first harmonic | Lowest natural frequency of a vibrating system. | 291 |
| Beat frequency | ν_beat = ν₁ − ν₂; rate of waxing/waning of intensity when two close-frequency waves superpose. | 294 |
| Phase | The argument (kx − ωt + φ) of a sinusoidal wave; determines displacement at any (x, t). | 282 |
| Initial phase angle (φ) | Value of the phase at x = 0, t = 0; SI unit radian. | 282 |
| Mechanical wave | Wave that requires an elastic material medium for propagation. | 279 |
| Electromagnetic wave | Wave that does not require a medium and travels at c = 3 × 10⁸ m s⁻¹ in vacuum. | 279 |
| Standing (stationary) wave | Wave pattern produced by superposition of two oppositely travelling identical waves; nodes and antinodes are fixed. | 290 |
| Normal mode | A natural pattern of oscillation of a bounded system with a definite frequency (νₙ). | 291 |
| Overtone | Any allowed frequency higher than the fundamental; the first overtone is the second harmonic for an open pipe/string. | 292 |
2.3 Diagrams / processes to remember
- Fig. 14.1 (p. 279): chain of coupled springs showing how a disturbance at one end travels along, while each spring only oscillates about its equilibrium — the model for mechanical wave propagation.
- Fig. 14.2 / 14.3 (p. 280): pulse and sinusoidal transverse wave on a stretched string; string elements oscillate in y while the wave moves in x.
- Fig. 14.4 (p. 280): longitudinal wave generated in a piston-driven air column — compressions and rarefactions parallel to the propagation direction.
- Fig. 14.5 / 14.6 (p. 282): meaning of a, ω, k, φ in y = a sin(kx − ωt + φ), and snapshots of a harmonic wave at successive times showing the crest advancing.
- Fig. 14.7 (p. 283): displacement of one element as a function of time — period T, amplitude a.
- Fig. 14.8 (p. 284): two snapshots of a wave at t and t + Δt to read off the phase speed v = Δx/Δt.
- Fig. 14.9 (p. 287): two equal-and-opposite pulses crossing — instantaneous cancellation illustrating superposition.
- Fig. 14.10 (p. 288): resultant of two harmonic waves of equal amplitude — constructive (φ = 0, amplitude 2a) versus destructive (φ = π, zero).
- Fig. 14.11 (p. 289): reflection of a pulse from a rigid boundary with phase change π.
- Fig. 14.12 (p. 290): two oppositely-travelling waves combining into a stationary wave with fixed nodes.
- Fig. 14.13 (p. 291): first six harmonics of a string fixed at both ends — ν₁ : ν₂ : ν₃ … = 1 : 2 : 3 …
- Fig. 14.14 (p. 292): first six odd harmonics of an air column closed at one end — ν₁, 3ν₁, 5ν₁ … only.
- Fig. 14.15 (p. 293): first four harmonics of a pipe open at both ends — all harmonics present.
- Fig. 14.16 (p. 294): superposition of 11 Hz and 9 Hz waves giving a 2 Hz beat envelope.
2.4 Common confusions / NTA trap points
- Confusing wind with sound: wind carries air bodily; a sound wave only carries the compression/rarefaction pattern — no net flow of air (NCERT §14.2, p. 281; Points to ponder 1, p. 297).
- Forgetting that transverse waves cannot propagate inside fluids — fluids cannot sustain shearing stress, so in air only longitudinal sound waves exist (NCERT §14.2, p. 281).
- Misusing Newton's bare v = √(P/ρ): it gives ~280 m s⁻¹ for air at STP, off by 15%. The Laplace-corrected v = √(γP/ρ) with γ = 7/5 gives 331.3 m s⁻¹, which is what NCERT uses (NCERT §14.4.2, pp. 286–287).
- Mixing up the harmonics of a closed pipe versus an open pipe: closed pipe has only odd harmonics (ν₁, 3ν₁, 5ν₁ …) while an open pipe (or a string fixed at both ends) has all harmonics (ν₁, 2ν₁, 3ν₁ …) (NCERT §14.6.1, pp. 291–292).
- In a standing wave, every particle oscillates with the same frequency and phase between two nodes but with different amplitudes — opposite to a progressive wave where amplitude is the same but phases differ (Points to ponder 5, p. 297).
- Beat frequency is the absolute difference ν₁ − ν₂, not the average; the average sets the pitch, the difference sets the waxing rate (NCERT §14.7, p. 294, Eq. 14.48).
- A common slip is treating "+" or "−" sign inside (kx ± ωt) as cosmetic — the sign sets the direction of travel: (kx − ωt) propagates in +x, (kx + ωt) in −x (NCERT §14.3, p. 281).
- Mistaking k (angular wave number, rad m⁻¹) for the ordinary wave number 1/λ — only k = 2π/λ enters the standard NCERT wave equation y = a sin(kx − ωt).
- Forgetting that on a stretched string ν depends on length and tension/density of the wire — so changing string length (fretting a guitar) raises ν without altering v, whereas tightening the string raises v and hence ν together.
- Assuming the speed of sound in water or steel can be computed with Newton-Laplace v = √(γP/ρ): that formula is for gases only; in liquids and solids use v = √(B/ρ) and v = √(Y/ρ) (NCERT §14.4.2, p. 286).
2.5 Key formulas table
| Quantity | Symbol / Formula | NCERT reference |
|---|---|---|
| Travelling wave (transverse) | y(x, t) = a sin(kx − ωt + φ) | §14.3, Eq. 14.2, p. 282 |
| Angular wave number | k = 2π/λ | §14.3.2, Eq. 14.6, p. 283 |
| Angular frequency | ω = 2π/T = 2πν | §14.3.3, Eq. 14.7, p. 283 |
| Frequency | ν = 1/T = ω/(2π) | §14.3.3, Eq. 14.8, p. 283 |
| Wave speed | v = ω/k = λ/T = νλ | §14.4, Eqs. 14.11–14.12, p. 284 |
| Speed on stretched string | v = √(T/µ) | §14.4.1, Eq. 14.14, p. 285 |
| Linear mass density | µ = m/L | §14.4.1, p. 285 |
| Speed in solid bar | v = √(Y/ρ) | §14.4.2, Eq. 14.19, p. 286 |
| Speed in fluid | v = √(B/ρ) | §14.4.2, Eq. 14.20, p. 286 |
| Newton's formula (isothermal) | v = √(P/ρ) | §14.4.2, Eq. 14.23, p. 287 |
| Newton-Laplace (adiabatic) | v = √(γP/ρ) | §14.4.2, Eq. 14.24, p. 287 |
| Superposition principle | y = Σ yᵢ = Σ fᵢ(x − vt) | §14.5, Eq. 14.26, p. 288 |
| Resultant of two waves (same a, ω, k) | y = 2a cos(φ/2) sin(kx − ωt + φ/2) | §14.5, Eq. 14.32, p. 288 |
| Standing wave on string | y = 2a sin(kx) cos(ωt) | §14.6.1, Eq. 14.37, p. 290 |
| Frequencies of string (both ends fixed) | νₙ = nv/(2L), n = 1, 2, 3 … | §14.6.1, Eq. 14.41, p. 291 |
| Frequencies of pipe (closed one end) | νₙ = (2n + 1)v/(4L), n = 0, 1, 2 … | §14.6.1, Eq. 14.44, p. 292 |
| Frequencies of pipe (open both ends) | νₙ = nv/(2L), n = 1, 2, 3 … | §14.6.1, p. 292 |
| Beat frequency | ν_beat = | ν₁ − ν₂ |
| Distance between adjacent nodes | λ/2 | §14.6.1, p. 290 |
| Distance node-to-nearest-antinode | λ/4 | §14.6.1, p. 290 |
🎯 Practice MCQs
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Q1. In which of the following media can a transverse mechanical wave NOT propagate?
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Answer: C
Transverse waves need a medium that can sustain shearing stress. Fluids like air cannot, so inside the bulk of air only longitudinal waves can propagate; solids and the water surface can support transverse waves.
Q2. A travelling wave on a string is given by y(x, t) = 0.005 sin(80.0 x − 3.0 t), with quantities in SI units. The wavelength of the wave is closest to:
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Answer: B
With k = 80.0 rad m⁻¹, λ = 2π/k ≈ 7.85 × 10⁻² m = 7.85 cm. Option A is half-wavelength; the others arise from doubling or dropping factors of 2π.
Q3. The speed v of a transverse wave on a stretched string of tension T and linear mass density µ is given by:
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Answer: C
Dimensional analysis, confirmed by exact derivation, gives v = √(T/µ). Speed grows with tension and falls with linear mass density.
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Q4. A steel wire 0.72 m long has a mass of 5.0 × 10⁻³ kg and is under a tension of 60 N. The speed of a transverse wave on the wire is approximately:
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Answer: C
Linear mass density µ = m/L = 6.9 × 10⁻³ kg m⁻¹, so v = √(T/µ) = √(60/6.9 × 10⁻³) ≈ 93 m s⁻¹.
Q5. Newton's formula for the speed of sound in a gas, v = √(P/ρ), under-predicts the measured value at STP by about 15%. The Laplace correction modifies this to:
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Answer: B
Pressure variations in sound are adiabatic, not isothermal. Adiabatic bulk modulus is γP, so v = √(B_ad/ρ) = √(γP/ρ). For air γ = 7/5 gives 331.3 m s⁻¹.
Q6. Two harmonic waves of equal amplitude a and same (ω, k) travel along a string in the same direction with phase difference φ. The resultant amplitude is:
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Answer: B
Using sin A + sin B with the two phases gives a resultant amplitude 2a cos(φ/2). Hence φ = 0 gives 2a (constructive), φ = π gives 0 (destructive).
Q7. A travelling pulse on a string is reflected from a rigid boundary. The phase change suffered by the reflected pulse is:
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Answer: C
The displacement at a rigid boundary must remain zero at all times; this requires that the reflected wave differ from the incident by a phase of π (i.e. an inversion). At an open boundary there is no phase change.
Q8. A stretched string of length L is fixed at both ends. The wavelength of the nth normal mode is:
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Answer: B
Both ends are nodes, requiring an integer number of half-wavelengths in L. The corresponding frequencies are νₙ = nv/(2L), and all harmonics are present.
Q9. An air column closed at one end and open at the other emits which set of harmonics of its fundamental ν₁?
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Answer: C
A node at the closed end and antinode at the open end allow only odd-integer × (v/4L). Even harmonics violate the boundary conditions and are absent.
Q10. A pipe 30 cm long is open at both ends. With v_sound = 330 m s⁻¹, which harmonic of the pipe is resonantly excited by a 1.1 kHz source?
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Answer: B
For an open pipe ν₁ = v/(2L) = 330/0.6 = 550 Hz. 1100 Hz = 2 × 550 Hz, i.e. the second harmonic. If one end is closed the only modes are 275, 825, 1375 Hz, so 1100 Hz is NOT a mode of the closed pipe.
Q11. Two sitar strings A and B playing the note 'Dha' produce beats of frequency 5 Hz. When the tension of string B is slightly increased, the beat frequency decreases to 3 Hz. If A has frequency 427 Hz, the original frequency of B is:
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Answer: D
Raising the tension of B raises ν_B. The beat frequency falls (5 → 3), so ν_B must be moving toward ν_A from below — i.e. originally ν_B < ν_A. With |ν_A − ν_B| = 5 and ν_A = 427 Hz, ν_B = 422 Hz.
Q12. Assertion (A): For a sinusoidal wave y = a sin(kx − ωt), the wave speed is v = ω/k. Reason (R): For a fixed phase point, the condition kx − ωt = constant gives dx/dt = ω/k, which equals νλ.
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Answer: A
Tracking a constant-phase point on the wave gives the phase-speed v = ω/k. Using ω = 2πν and k = 2π/λ converts this directly to νλ, exactly the reasoning of NCERT Eq. 14.12. Hence both assertion and reason are true and R explains A.
Q13. The speed of sound in air at 0 °C is 331 m s⁻¹. At 27 °C the speed is closest to (assuming ideal-gas behaviour, v ∝ √T)
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Answer: B
v(T) = 331 × √(300/273) ≈ 331 × 1.048 ≈ 347 m s⁻¹. The NCERT rule of thumb of ~0.6 m s⁻¹ per °C also gives 331 + 0.61 × 27 ≈ 347 m s⁻¹.
Q14. A standing wave on a string fixed at both ends has nodes separated by 0.25 m. The wavelength of the constituent travelling waves is
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Answer: B
In a standing wave consecutive nodes are λ/2 apart, so λ = 2 × 0.25 = 0.50 m. Option (A) is the trap — students may forget the factor of 2.
Q15. Assertion (A): An open organ pipe of given length sounds an octave higher than a closed pipe of the same length when both are sounded at their fundamental. Reason (R): The fundamental of an open pipe is ν₁ = v/(2L) while that of a closed pipe is ν₁ = v/(4L).
▸ Show answer & explanation
Answer: A
Open pipe: ν₁ = v/(2L). Closed pipe: ν₁ = v/(4L). Their ratio is 2 — exactly one octave. R correctly explains A.
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