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Mensuration & Basic Geometry

Mensuration & Basic Geometry is a frequently tested area in CUET General Test. Work through these free NTA-style sample questions with full answers and explanations, then attempt all 35 in a timed practice test to build exam-day speed.

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Snapshot

Part 1 — Two-dimensional figures

Key 2-D figureslbArea = l × bPerim. = 2(l + b)bhArea = ½ × b × hHeron: √(s(s−a)(s−b)(s−c))rArea = π r²Circumf. = 2 π r
Figure Area Perimeter
Square (side a) 4a
Rectangle (l, b) l × b 2(l + b)
Triangle (base b, height h) ½ × b × h a + b + c
Triangle (sides a,b,c) √(s(s−a)(s−b)(s−c)), s = ½(a+b+c) a + b + c
Equilateral (side a) (√3 ÷ 4) a² 3a
Parallelogram (b, h) b × h 2(a + b)
Trapezium (parallel a, b; height h) ½ (a + b) × h sum of sides
Rhombus (diagonals d₁, d₂) ½ × d₁ × d₂ 4 × side
Circle (radius r) π r² 2 π r (circumference)

The diagonal of a square is a√2; of a rectangle, √(l² + b²).

Part 2 — Three-dimensional solids

Key 3-D solidsCuboidV = lbhSA = 2(lb+bh+hl)CylinderV = π r² hCSA = 2 π r hSphereV = 4/3 π r³SA = 4 π r²
Solid Volume Surface area
Cube (side a) 6a²
Cuboid (l, b, h) l × b × h 2(lb + bh + hl)
Cylinder (r, h) π r² h CSA 2πrh · TSA 2πr(r+h)
Cone (r, h, slant l) ⅓ π r² h CSA πrl · TSA πr(r+l)
Sphere (r) (4/3) π r³ 4 π r²
Hemisphere (r) (2/3) π r³ CSA 2πr² · TSA 3πr²

For a cone, the slant height l = √(r² + h²). CSA = curved surface area; TSA = total (includes the flat faces).

Part 3 — Basic geometry essentials

Part 4 — Key constants & speed techniques

  1. π = 22/7 is exact enough; it cancels cleanly when the radius is a multiple of 7.
  2. Spot the Pythagorean triple to skip the square-root step.
  3. Units: area is square, volume is cubic — a "double the side" change multiplies area by 4 and volume by 8.
  4. Half the diameter before using any circle/sphere formula — radius, not diameter.
  5. Match units first (convert cm to m, etc.) before computing.

Part 5 — Worked examples

1. Rectangle. l = 12, b = 5. Area = 60 sq units; diagonal = √(144+25) = √169 = 13.

2. Triangle (Heron). Sides 13, 14, 15. s = 21; area = √(21·8·7·6) = √7056 = 84.

3. Circle. r = 7. Area = 22/7 × 49 = 154; circumference = 2 × 22/7 × 7 = 44.

4. Equilateral. Side 6. Area = (√3/4) × 36 = 9√3.

5. Cube. Side 5. Volume = 125; surface area = 6 × 25 = 150.

6. Cylinder. r = 7, h = 10. Volume = 22/7 × 49 × 10 = 1540; CSA = 2 × 22/7 × 7 × 10 = 440.

7. Cone. r = 3, h = 4 → slant = 5. Volume = ⅓ × 22/7 × 9 × 4 = 37.7; CSA = 22/7 × 3 × 5 = 47.1.

8. Sphere. r = 21. Volume = 4/3 × 22/7 × 21³ = 38,808.

Part 6 — Common traps

Part 7 — How to use this page

Memorise the two formula tables and the Pythagorean triples, re-solve the eight examples closed-book, then attempt the practice set and the timed test.

One-line revision: area is square units and volume cubic, use radius not diameter, π = 22/7, slant height of a cone is √(r²+h²), and doubling a side multiplies area by 4 and volume by 8.

Practice questions

Now test yourself. 8 free sample questions with explanations. 27 more in the timed practice test.

Q1. A solid metal cube of side $6$ cm is melted and recast into small cubes of side $2$ cm. How many small cubes are formed?

▸ Show answer & explanation

Answer: A

Big cube volume $=6^3=216 \text{ cm}^3$. Small cube volume $=2^3=8 \text{ cm}^3$. Number $=\frac{216}{8}=27$.

Q2. The length of a rectangle is twice its breadth and its area is $72 \text{ cm}^2$. What is its perimeter?

▸ Show answer & explanation

Answer: A

Let breadth $=b$, length $=2b$. Area $=2b^2=72$, so $b^2=36$, $b=6$, $l=12$. Perimeter $=2(12+6)=36 \text{ cm}$.

Q3. A wire is bent into a circle of radius $14$ cm. If the same wire is re-bent into a square, what is the side of the square? (Use $\pi=\frac{22}{7}$.)

▸ Show answer & explanation

Answer: A

Length of wire $=$ circumference $=2\pi r=2\times\frac{22}{7}\times14=88$ cm. Side of square $=\frac{88}{4}=22 \text{ cm}$.

Q4. In a triangle, two angles measure $55^\circ$ and $65^\circ$. What is the exterior angle at the third vertex?

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Answer: A

An exterior angle equals the sum of the two remote interior angles: $55^\circ+65^\circ=120^\circ$.

Q5. A circle is inscribed in a square of side $14$ cm. What is the area of the circle? (Use $\pi=\frac{22}{7}$.)

▸ Show answer & explanation

Answer: A

An inscribed circle has diameter equal to the side, so radius $=7$ cm. Area $=\pi r^2=\frac{22}{7}\times49=154 \text{ cm}^2$.

Q6. The total surface area of a cube is $216 \text{ cm}^2$. What is its volume?

▸ Show answer & explanation

Answer: A

Total surface area $=6s^2=216$, so $s^2=36$, $s=6$ cm. Volume $=s^3=6^3=216 \text{ cm}^3$.

Q7. Two parallel lines are cut by a transversal. If one of the co-interior (allied) angles is $70^\circ$, what is the measure of the other co-interior angle on the same side?

▸ Show answer & explanation

Answer: A

Co-interior angles between parallel lines are supplementary, summing to $180^\circ$. So the other angle $=180^\circ-70^\circ=110^\circ$.

Q8. A rectangular sheet of paper $44$ cm by $20$ cm is rolled along its longer side to form a cylinder. What is the radius of the cylinder? (Use $\pi=\frac{22}{7}$.)

▸ Show answer & explanation

Answer: A

Rolling along the $44$ cm side makes the circumference $44$ cm: $2\pi r=44$, so $r=\frac{44\times7}{2\times22}=7 \text{ cm}$.

🔒 27 more questions

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