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Class XI ⚛️ Physics ~12 MCQs/year Ch 13 of 14

Oscillations

CUET unit: Oscillations

📌 Snapshot

  • Establishes the language of periodic and oscillatory motion — period T, frequency ν, displacement, amplitude, phase — and singles out Simple Harmonic Motion (SHM) as the simplest oscillation, defined by a sinusoidal displacement x(t) = A cos(ωt + φ).
  • Derives the kinematics of SHM (velocity v = −Aω sin(ωt+φ), acceleration a = −ω²x) by treating SHM as the projection of uniform circular motion on a diameter — a powerful geometric trick used throughout CUET problems.
  • Builds the dynamics — restoring force F = −kx with ω = √(k/m) — and the energy picture: KE = ½ mω²(A²−x²), PE = ½ kx², total E = ½ kA² = constant.
  • Applies SHM to two canonical systems: the spring–mass oscillator (T = 2π√(m/k)) and the simple pendulum at small angular displacement (T = 2π√(L/g)).
  • CUET draws heavily here for formula-substitution numericals (T from m, k or L, g; vmax; KE/PE ratios) and for conceptual sieves (periodic vs SHM, phase of v and a, energy at extremes vs mean).

📖 Detailed Notes

2.1 Core concepts

  • Motion that repeats itself at regular intervals of time is called periodic motion; to-and-fro motion about a mean (equilibrium) position is called oscillatory motion. Every oscillatory motion is periodic, but every periodic motion need not be oscillatory — uniform circular motion is periodic but not oscillatory (NCERT §13.1–13.2, p. 259–260).
  • At the equilibrium position no net external force acts on the body; a small displacement brings a restoring force into play, producing oscillations or vibrations. The terms oscillation and vibration are essentially synonymous; oscillation is used at low frequency (tree branch), vibration at high frequency (musical string) (NCERT §13.2, p. 260).
  • The period T is the smallest time interval after which the motion repeats; its SI unit is the second. The frequency ν = 1/T is measured in hertz (1 Hz = 1 oscillation per second = 1 s⁻¹); ν need not be an integer (NCERT §13.2.1, Eqs. 13.1–13.2, p. 260–261).
  • In this chapter displacement is generalised: it refers to the change with time of any physical property (position of a block on a spring, angle of a pendulum from the vertical, voltage across a capacitor, pressure in a sound wave). Displacement can be positive or negative (NCERT §13.2.2, p. 261).
  • A periodic displacement is conveniently written as f(t) = A cos ωt (or A sin ωt). The period is T = 2π/ω; any linear combination A sin ωt + B cos ωt is also periodic with the same T. By Fourier's theorem any periodic function can be written as a superposition of sines and cosines (NCERT §13.2.2, Eqs. 13.3a–13.3d, p. 261–262).
  • Simple Harmonic Motion (SHM) is the oscillation in which the displacement is a sinusoidal function of time: x(t) = A cos(ωt + φ), where A is the amplitude, ω the angular frequency, (ωt+φ) the phase, and φ the phase constant. SHM is not just any periodic motion — it is the sinusoidal one (NCERT §13.3, Eq. 13.4, p. 262).
  • The amplitude A is the magnitude of maximum displacement and is taken positive without loss of generality; the cosine varies between +1 and −1, so x varies between +A and −A. The phase (ωt + φ) determines the instantaneous state of motion; at t = 0 the phase equals the phase constant φ (NCERT §13.3, p. 263).
  • ω is related to T by ω = 2π/T (Eq. 13.7), and to frequency by ω = 2πν. ω is called the angular frequency and has SI units of rad s⁻¹ (NCERT §13.3, Eqs. 13.5–13.7, p. 264).
  • SHM ↔ uniform circular motion: the projection of a particle moving uniformly on a circle of radius A with angular speed ω on a diameter of that circle executes SHM with amplitude A and angular frequency ω. The circle is called the reference circle and the moving point the reference particle (NCERT §13.4, p. 264–265).
  • Velocity in SHM: v(t) = −Aω sin(ωt + φ), obtained either by projecting the tangential velocity v = ωA of the reference particle or by differentiating x(t). Hence vmax = Aω, occurring at x = 0 (mean position), and v = 0 at x = ±A. Eliminating time gives v = ±ω√(A² − x²) (NCERT §13.5, Eqs. 13.8–13.10, p. 266).
  • Acceleration in SHM: a(t) = −ω²A cos(ωt + φ) = −ω² x(t), obtained from the centripetal acceleration ω²A of the reference particle, or by differentiating v(t). Thus acceleration is proportional to displacement and always directed towards the mean position; |a|max = ω²A at the extremes, a = 0 at x = 0 (NCERT §13.5, Eqs. 13.11–13.12, p. 266–267).
  • Phase relations: with respect to displacement, velocity has a phase lead of π/2 and acceleration has a phase difference of π (i.e., is in anti-phase). All three quantities have the same period T (NCERT §13.5, Fig. 13.13, p. 267).
  • Force law for SHM: by Newton's second law F = ma = −mω² x = −kx, where k = mω² (so ω = √(k/m)). The restoring force is linearly proportional to displacement and directed towards the mean position; the system is a linear harmonic oscillator. Forces with extra x², x³ terms give non-linear oscillators (NCERT §13.6, Eqs. 13.13–13.14, p. 267).
  • Energy in SHM: kinetic energy K = ½ mv² = ½ mω²A² sin²(ωt+φ) = ½ k A² sin²(ωt+φ); potential energy U = ½ k x² = ½ k A² cos²(ωt+φ). Both are periodic with period T/2 (NCERT §13.7, Eqs. 13.15–13.17, p. 268).
  • The total mechanical energy of the harmonic oscillator is E = K + U = ½ k A² = ½ mω²A² — constant in time, independent of where the particle is. At x = 0 the energy is entirely kinetic; at x = ±A it is entirely potential; in between K and U exchange (NCERT §13.7, Eq. 13.18 and Fig. 13.16, p. 269).
  • Spring–mass oscillator: F = −kx gives ω = √(k/m) and T = 2π√(m/k) (NCERT §13.6 and Summary point 8, Eqs. 13.13–13.14, p. 267 and p. 272).
  • Simple pendulum: for a bob of mass m on an inextensible massless string of length L, the tangential restoring torque is τ = −L (mg sinθ). Newton's law of rotation gives α = −(mgL/I) sinθ. For small θ, sinθ ≈ θ (Table 13.1 shows sinθ ≈ θ even up to ~20°), so α = −(mgL/I) θ — SHM in angular displacement (NCERT §13.8, Eqs. 13.19–13.24, p. 270–271).
  • With I = mL², the angular frequency is ω = √(g/L) and the period is T = 2π√(L/g), independent of mass and amplitude (NCERT §13.8, Eqs. 13.25–13.26, p. 271).
  • Two-spring effective stiffness (NCERT Example 13.6, p. 267–268): when a mass is connected to two identical springs of constant k on opposite sides, both contribute restoring force, so the effective k is 2k and T = 2π√(m/2k). The same logic gives k_series = k₁k₂/(k₁ + k₂) and k_parallel = k₁ + k₂ in standard combinations encountered in NCERT exercises.
  • Energy interconversion is continuous in SHM: at any displacement x, K = ½ mω²(A² − x²) and U = ½ mω² x²; sum K + U = ½ mω² A² is conserved. Plots of K and U against time are sin² and cos² curves of period T/2, mirror images of each other around the half-energy line (NCERT §13.7, Fig. 13.16, p. 268–269).
  • SHM as projection of uniform circular motion explains why the kinematic equations of SHM have the same form as the components of uniform circular motion: x = A cos θ, vₓ = −Aω sin θ, aₓ = −Aω² cos θ, with θ = ωt + φ — this geometric mapping is what NCERT exploits to derive every SHM relation without calculus (NCERT §13.4, p. 264–266).

2.2 Definitions to memorise

Term Definition Page
Periodic motion Motion that repeats itself at regular intervals of time 260
Oscillatory motion To-and-fro motion about a mean (equilibrium) position 259–260
Period (T) The smallest interval of time after which the motion is repeated; SI unit second 260
Frequency (ν) Number of repetitions per unit time, ν = 1/T; SI unit hertz (Hz) = 1 s⁻¹ 261
Displacement Change with time of any physical property under consideration (position, angle, voltage, pressure, etc.) 261
Amplitude (A) Magnitude of the maximum displacement of the particle; taken positive 263
Phase The time-dependent quantity (ωt + φ) in x(t) = A cos(ωt+φ), determining the state of motion at time t 263
Phase constant (φ) Value of phase at t = 0; the phase angle 263
Angular frequency (ω) ω = 2π/T = 2πν; SI unit rad s⁻¹ 264
Simple harmonic motion (SHM) Oscillation in which displacement is a sinusoidal function of time: x(t) = A cos(ωt+φ) 262
Restoring force (in SHM) Force F = −kx, linearly proportional to displacement and directed towards the mean position 267
Linear harmonic oscillator System obeying F = −kx exactly; if extra x², x³ terms appear it becomes non-linear 267
Reference circle / reference particle The circle (and uniformly revolving point on it) whose projection on a diameter gives the SHM 265
Equilibrium (mean) position Point of zero net force where the displacement x is measured from; in SHM, x = 0 here 260
Extreme position Points x = ±A where v = 0 and a
Maximum speed v_max = Aω (at the mean position) 266
Maximum acceleration a
Effective spring constant (series) k_s = k₁k₂/(k₁+k₂) 267 (implied)
Effective spring constant (parallel) k_p = k₁ + k₂ 267 (implied)
Period of spring–mass system T = 2π√(m/k) 267
Period of simple pendulum T = 2π√(L/g), small θ 271
Small-angle approximation sin θ ≈ θ (rad), valid up to ~20° 271

2.3 Diagrams / processes to remember

  • Fig. 13.1 (p. 260) — three examples of periodic motion: insect climbing a ramp; child climbing a step; a ball bouncing (parabolic arcs).
  • Fig. 13.2 (p. 261) — (a) block on a spring, the prototype linear SHM system; (b) simple pendulum with angular displacement θ.
  • Fig. 13.3 / 13.4 / 13.5 (p. 262–263) — particle vibrating between +A and −A; snapshots at t = 0, T/4, T/2, 3T/4, T; continuous x-vs-t cosine curve.
  • Fig. 13.6 (p. 263) — table mapping the symbols A, ω, ωt+φ, φ to their meanings in x(t) = A cos(ωt+φ).
  • Fig. 13.7 (p. 263) — two SHMs with same ω, φ but different A (a); same A, ω but different φ (b).
  • Fig. 13.8 (p. 264) — two SHMs with same A, φ but different periods T (and hence different ω).
  • Fig. 13.9 / 13.10 (p. 265) — ball on a string in horizontal circular motion; its projection on a wall is SHM. Reference-circle construction.
  • Fig. 13.11 / 13.12 (p. 266) — projecting the tangential velocity v = ωA of reference particle gives v(t) = −ωA sin(ωt+φ); projecting the centripetal acceleration ω²A gives a(t) = −ω²A cos(ωt+φ) = −ω² x(t).
  • Fig. 13.13 (p. 267) — stacked plots of x(t), v(t), a(t): same period T but velocity leads displacement by π/2, acceleration is anti-phase to displacement.
  • Fig. 13.14 / 13.15 (p. 268) — Example 13.6: a mass between two identical springs k each gives effective force −2kx and T = 2π√(m/2k).
  • Fig. 13.16 (p. 269) — K, U, and total E plotted vs time and vs displacement: K and U both repeat with period T/2; total E = ½kA² is a horizontal line.
  • Fig. 13.17 (p. 270) — simple pendulum free-body diagram: T along string; mg cosθ (radial) and mg sinθ (tangential, restoring).
  • Table 13.1 (p. 271) — values of θ (degrees, radians) vs sinθ, showing sinθ ≈ θ to good accuracy up to ~20°.

2.4 Common confusions / NTA trap points

  • Periodic vs SHM. Every SHM is periodic, but the reverse is false. Earth's rotation is periodic, not SHM. NTA distractors will offer a periodic non-sinusoidal motion (e.g., a bouncing ball, planetary orbit) as "SHM" (NCERT §13.2 and Points to Ponder #2, p. 273).
  • Phase of v and a. Students often write "velocity is in phase with displacement". It isn't — v leads x by π/2 and a is in anti-phase (phase difference π), not π/2 (NCERT §13.5, Fig. 13.13, p. 267).
  • vmax and amax locations. vmax = Aω occurs at the mean position (x = 0), not at the extremes; amax = ω²A occurs at the extremes (x = ±A), not at the mean. NTA loves swapping these (NCERT §13.5, p. 266–267).
  • KE/PE at mean and extreme. At x = 0 energy is entirely kinetic; at x = ±A entirely potential. KE and PE individually have period T/2, but total E is constant — not periodic in any non-trivial sense (NCERT §13.7, Fig. 13.16, p. 268–269).
  • Pendulum period independent of mass and amplitude. T = 2π√(L/g) — students sometimes write it as depending on mass m or on initial amplitude θ₀. Both are wrong for small oscillations (NCERT §13.8 and Points to Ponder #7, Eq. 13.26, p. 271 and p. 273).
  • Two-spring trap (Example 13.6). With identical springs k on either side of a mass, both pull it back: F = −2kx, so ω = √(2k/m), T = 2π√(m/2k) — not T = 2π√(m/k). Students forget to add the spring constants (NCERT §13.6, Example 13.6, p. 267–268).
  • Small-angle approximation for pendulum. SHM holds only for small θ where sinθ ≈ θ. For large amplitudes the pendulum is still periodic, but not simple harmonic (NCERT §13.8 and Points to Ponder #8, p. 271, 273).
  • Confusing T (period) with t (time). T is the smallest interval for one full repetition; t is the running time. The phase ωt + φ uses the running t, not T.
  • Energy quadratic in amplitude. Doubling A multiplies E by 4 (not 2), because E ∝ A². Many students miss the square.
  • Pendulum on the Moon. Since T ∝ 1/√g and g_Moon ≈ g_Earth/6, the same pendulum has period √6 ≈ 2.45 times longer on the Moon — NTA loves this swap.
  • k for a vertically hanging spring. The natural length shifts to a new equilibrium under gravity; the SHM about this new equilibrium still has T = 2π√(m/k) — gravity does not enter the period.

2.5 Key formulas table

Quantity Symbol / Formula NCERT reference
Period and frequency T = 1/ν; ν = 1/T §13.2.1, Eqs. 13.1–13.2, p. 261
Angular frequency ω = 2π/T = 2πν §13.3, Eqs. 13.5–13.6, p. 264
SHM displacement x(t) = A cos(ωt + φ) §13.3, Eq. 13.4, p. 262
SHM velocity v(t) = −Aω sin(ωt + φ) §13.5, Eq. 13.9, p. 266
SHM acceleration a(t) = −ω² x(t) §13.5, Eq. 13.11, p. 266
Maximum speed v_max = Aω at x = 0 §13.5, p. 266
Maximum acceleration a
Velocity–displacement v = ±ω √(A² − x²) §13.5, Eq. 13.10, p. 266
Restoring force F = −k x; k = m ω² §13.6, Eq. 13.13, p. 267
Period (spring–mass) T = 2π √(m/k) §13.6, Eq. 13.14, p. 267
Period (two equal springs both sides) T = 2π √(m/2k) Ex. 13.6, p. 268
Kinetic energy in SHM K = ½ mω²(A² − x²) = ½ k(A² − x²) §13.7, Eq. 13.15, p. 268
Potential energy in SHM U = ½ k x² §13.7, Eq. 13.16, p. 268
Total energy E = ½ k A² = ½ m ω² A² §13.7, Eq. 13.18, p. 269
Period of K and U T/2 §13.7, p. 268
Period (simple pendulum) T = 2π √(L/g) §13.8, Eq. 13.26, p. 271
ω (simple pendulum) ω = √(g/L) §13.8, p. 271
Phase lead of v over x π/2 §13.5, p. 267
Phase of a relative to x π (anti-phase) §13.5, p. 267
Small-angle validity sin θ ≈ θ for θ < ~0.35 rad (~20°) Table 13.1, p. 271

🎯 Practice MCQs

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Q1. Which one of the following statements is correct?

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Answer: B

Circular motion is a periodic but non-oscillatory example. (A) is false (only sinusoidal periodic motion is SHM), (C) reverses the truth, (D) is meaningless — SHM is independent of amplitude.

Q2. The displacement of a particle executing SHM is given by x(t) = A cos(ωt + φ). The quantity (ωt + φ) is called the

▸ Show answer & explanation

Answer: C

The textbook explicitly names (ωt + φ) the phase; its value at t = 0, namely φ alone, is the phase constant. A and B are unrelated to that argument.

Q3. A particle in SHM has amplitude A and angular frequency ω. Its maximum speed is

▸ Show answer & explanation

Answer: B

Since v(t) = −Aω sin(ωt+φ), the maximum value of |v| is Aω, occurring when sin(…)= ±1, i.e., at the mean position. Aω² is the maximum acceleration, not speed.

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