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Class XI ⚛️ Physics Ch 1 of 14

Units and Measurements

CUET unit: Units and Measurements

📌 Snapshot

  • Master SI units, significant figures, error propagation and dimensional analysis with worked CUET examples.
  • Learn why every measurement is a number, a unit and a promise about how far to trust it.
  • Practise the arithmetic rules for significant figures, percentage errors and unit conversion until they are automatic.
  • Use dimensions to check an equation, convert units and derive a formula, and know exactly where the method stops working.

📖 Detailed Notes

Written and reviewed by Akanksha Tiwari, Physics & Chemistry faculty at UniDrill (M.Sc. Physics, Banaras Hindu University · 8 years teaching Class XI–XII science). Based on NCERT Physics Class XI, Chapter 1.

Why is 2 m not the same as 2.000 m?

A tailor tears off "two metres" of cloth by eye. A lab technician reports 2.000 m, certified to a tenth of a millimetre. The number is the same, but the claim is not. Every measurement in physics is a number, a unit and a promise about how far you can trust the number. This chapter teaches all three: the units the world agrees on, the digits you are allowed to write, and the errors you must admit to.

Units: agreeing on the yardstick

To measure is to compare. You compare the quantity with an agreed reference called a unit, and the answer is "so many units". A small set of base quantities is chosen, and every other quantity is built from them. The units of the base quantities are base units. Units of everything else are derived units. Together they make a system of units.

Old systems were CGS (cm, g, s), FPS (foot, pound, second) and MKS (m, kg, s). Today the world uses the SI (Système International d'Unités), which is decimal, so converting between a kilometre and a millimetre is only a matter of powers of ten. SI has seven base quantities.

Quantity SI unit Symbol Dimension symbol Fixed by (the 2019 definitions)
Length metre m L Speed of light $c = 299\,792\,458$ m s⁻¹
Mass kilogram kg M Planck constant $h = 6.626\,070\,15 \times 10^{-34}$ J s
Time second s T Caesium-133 hyperfine frequency, 9 192 631 770 Hz
Electric current ampere A A Elementary charge $e = 1.602\,176\,634 \times 10^{-19}$ C
Temperature kelvin K K Boltzmann constant $k = 1.380\,649 \times 10^{-23}$ J K⁻¹
Amount of substance mole mol mol Avogadro constant $N_A = 6.022\,140\,76 \times 10^{23}$ mol⁻¹
Luminous intensity candela cd cd Luminous efficacy of 683 lm W⁻¹ for light of frequency $540 \times 10^{12}$ Hz

The ampere, kelvin, mole and candela are easy to forget because they are not the everyday ones. A coulomb is not a base unit: it is derived (1 C = 1 A s). When you use the mole, always say what you are counting: atoms, molecules, ions or electrons.

Beyond the textbook. For the exam: each SI base unit is defined by fixing the numerical value of a natural constant, so the metre comes from c, the kilogram from h, the second from the caesium frequency, and so on. In reality: until 20 May 2019 the kilogram was the mass of a single platinum-iridium cylinder kept near Paris, and comparisons with its official copies showed small drifts over the decades. Fixing h removed the dependence on one physical object. Why it matters: a unit tied to a constant of nature is the same on every planet and cannot be damaged.

Two angle units sit outside the seven. The radian measures a plane angle, $d\theta = ds/r$ (arc divided by radius). The steradian measures a solid angle, $d\Omega = dA/r^2$ (area divided by radius squared). Each is a ratio of two like quantities, so both are dimensionless. They are traditionally called supplementary units, and they are never base units.

Derived units get their own names when they are used often: newton (N), joule (J), watt (W), pascal (Pa), hertz (Hz). Very large and very small values use prefixes.

Prefix Factor Prefix Factor
tera (T) $10^{12}$ milli (m) $10^{-3}$
giga (G) $10^{9}$ micro (μ) $10^{-6}$
mega (M) $10^{6}$ nano (n) $10^{-9}$
kilo (k) $10^{3}$ pico (p) $10^{-12}$
centi (c) $10^{-2}$ femto (f) $10^{-15}$

Some non-SI units are still used because the SI ones are inconvenient at those scales.

Unit Value in SI Used for
ångström (Å) $10^{-10}$ m Atomic sizes and wavelengths of light
fermi (fm) $10^{-15}$ m Nuclear sizes
astronomical unit (AU) $1.496 \times 10^{11}$ m Distances inside the solar system
light year (ly) $9.46 \times 10^{15}$ m Distances to stars
parsec (pc) $3.08 \times 10^{16}$ m Distances to stars and galaxies
atomic mass unit (u) $1.66 \times 10^{-27}$ kg Masses of atoms and nuclei
electron volt (eV) $1.6 \times 10^{-19}$ J Energies of electrons and photons
litre (L) $10^{-3}$ m³ Volumes of liquids

Significant figures: the digits you may write

A measurement has some digits you are sure of and one last digit that is doubtful. Together they are the significant figures. If a stopwatch shows 1.62 s, the 1 and 6 are reliable, the 2 is the guess, and you must not write 1.620 s because that would claim a precision you do not have.

The number of significant figures depends on the instrument, never on the unit you choose. So 2.308 cm, 0.02308 m, 23.08 mm and 23 080 μm all have four significant figures.

Rule Example Significant figures
Every non-zero digit counts 2.718 4
Zeros between non-zero digits count 3007 4
Zeros before the first non-zero digit never count 0.0042 2
Trailing zeros after a decimal point count 0.06900 4
Trailing zeros with no decimal point do not count 12 300 3
Scientific notation $a \times 10^{b}$ ($1 \le a < 10$) removes doubt: count the digits of $a$ $1.2300 \times 10^{4}$ 5
Exact numbers (counts, definitions) have unlimited significant figures the 2 in $2\pi r$ unlimited

Pause and predict: a student records one length as 7.0 cm and another as 7.00 cm. Which instrument is more precise?

Check your answer: the one that gave 7.00 cm. It claims the hundredths place, so its least count is smaller. Precise does not mean accurate, though. Both readings could still be off from the true length if the instrument has a zero error.

Arithmetic with measured numbers. The answer can never be more precise than the weakest input, but the two operations measure "weakest" differently.

Operation Keep Why
Multiply or divide As many significant figures as the input with the fewest Relative uncertainty of the result is set by the least precise factor
Add or subtract As many decimal places as the input with the fewest Absolute uncertainty is set by the least precise term

Worked example: adding masses. Add 436.32 g, 227.2 g and 0.301 g, and report the total correctly.

Step What we do Result
1 Add exactly 663.821 g
2 Count decimal places of each term 2, 1 and 3, so the fewest is 1
3 Round the sum to 1 decimal place 663.8 g

The common wrong step: reporting 664 g because the "least number of significant figures" rule was used. That rule belongs to multiplication and division. For a sum, 227.2 g is uncertain in the tenths place, so nothing beyond the tenths place in the answer is trustworthy.

A related surprise: subtraction can destroy significant figures. 12.9 g − 7.06 g = 5.84 g on a calculator, but the answer is 5.8 g because 12.9 has only one decimal place.

Worked example: volume of a block. A metal block measures 12.5 cm × 3.2 cm × 0.85 cm. Find its volume.

Step What we do Result
1 Multiply 12.5 × 3.2 × 0.85 = 34.0 cm³
2 Significant figures of each factor 3, 2 and 2, so the fewest is 2
3 Round to 2 significant figures 34 cm³

The common wrong step: writing 34.0 cm³ because the calculator showed it. That claims three significant figures when two of your three measurements have only two.

Rounding off. Look at the first digit you are dropping. If it is more than 5, raise the last kept digit by one. If it is less than 5, leave it. If it is exactly 5 (nothing after it), raise the last kept digit only when it is odd. So 2.745 → 2.74, 2.735 → 2.74, and 2.746 → 2.75. In a long calculation, keep one extra digit in the middle and round only at the end.

Beyond the textbook. For the exam: use the odd/even rule above. In reality: this is called round-half-to-even, and it is the default rounding mode in standard computer arithmetic. Always rounding a 5 upward pushes a long column of numbers slightly high, and the odd/even rule cancels that bias. Why it matters: it is not an arbitrary rule, which makes it easier to remember.

Order of magnitude. Write the quantity as $a \times 10^{b}$ with $1 \le a < 10$. If $a \le 5$ the order of magnitude is $10^{b}$, and if $a > 5$ it is $10^{b+1}$. A hydrogen atom of radius $5 \times 10^{-11}$ m is of order $10^{-11}$ m, and Earth's mass of $5.97 \times 10^{24}$ kg is of order $10^{25}$ kg.

Errors: admitting what you don't know

No measurement is perfect. Accuracy is how close a reading is to the true value. Precision is how closely repeated readings agree with each other. A watch that is always exactly 5 minutes fast is precise but not accurate.

Type of error Cause Can it be removed?
Systematic Faulty instrument, zero error, flawed method, personal habit Yes, once found and corrected
Random Unpredictable changes in conditions or in the observer Reduced by taking many readings and averaging
Least count error The instrument cannot read finer than its least count (the smallest division) Only by using a finer instrument

For repeated readings $a_1, a_2, \ldots a_n$, the best estimate is the mean $\bar{a}$. The absolute error of each reading is its deviation from the mean, and the mean absolute error is the average of those deviations. Relative error is $\Delta\bar{a}/\bar{a}$, and percentage error is that times 100 %.

Worked example: reporting a measurement. Four readings of the length of a wire are 20.0, 20.4, 19.6 and 20.0 cm. Report the length with its error.

Step What we do Result
1 Mean (20.0 + 20.4 + 19.6 + 20.0) / 4 = 20.0 cm
2 Absolute errors of the readings 0.0, 0.4, 0.4, 0.0 cm
3 Mean absolute error 0.8 / 4 = 0.2 cm
4 Report 20.0 ± 0.2 cm, a relative error of 0.01 or 1 %

Combining errors. Add the errors of two measured quantities, but add them in the right form.

Operation Rule Example
Sum or difference, $Z = A \pm B$ Absolute errors add: $\Delta Z = \Delta A + \Delta B$ (100 ± 1) − (20 ± 1) = 80 ± 2
Product or quotient, $Z = AB$ or $A/B$ Relative errors add: $\Delta Z/Z = \Delta A/A + \Delta B/B$ 3 % and 2 % give 5 %
Power, $Z = A^p B^q$ $\Delta Z/Z = p(\Delta A/A) + q(\Delta B/B)$ $r^3$ with 2 % error in $r$ gives 6 %

Notice that in a difference the errors still add. That is why subtracting two nearly equal quantities is dangerous: the answer shrinks but the error does not, so the percentage error explodes. The 80 ± 2 above has a 2.5 % error, while each input had only 1 % and 5 %.

Worked example: percentage error in density. A cylinder has mass m = 50.0 ± 0.5 g, radius r = 2.00 ± 0.02 cm and length l = 10.0 ± 0.1 cm. Find the percentage error in its density $\rho = m/(\pi r^2 l)$.

Step What we do Result
1 Percentage error in each quantity m: 1 %, r: 1 %, l: 1 %
2 Write the dependence $\rho \propto m r^{-2} l^{-1}$
3 Powers multiply the percentage error, and all terms add 1 % + 2 × 1 % + 1 %
4 Total 4 %

The common wrong step: forgetting the factor 2 for $r^2$ (giving 3 %) or subtracting the errors of r and l because they are in the denominator. Errors never cancel, so the sign of the power does not matter, only its size.

Dimensions: what kind of quantity is it?

The dimensions of a quantity are the powers to which the base quantities are raised to build it. A velocity is length over time whether it is in km h⁻¹ or m s⁻¹, so its dimensional formula is $[L\,T^{-1}]$. Magnitude, direction and unit do not matter. That is why initial velocity, final velocity and change in velocity all have the same dimensions.

Quantity Built from Dimensions SI unit
Velocity length / time $[L\,T^{-1}]$ m s⁻¹
Acceleration velocity / time $[L\,T^{-2}]$ m s⁻²
Force m a $[M\,L\,T^{-2}]$ N
Momentum, impulse m v, $F\,\Delta t$ $[M\,L\,T^{-1}]$ kg m s⁻¹
Work, energy, torque F d, F r $[M\,L^2\,T^{-2}]$ J (torque in N m)
Power work / time $[M\,L^2\,T^{-3}]$ W
Pressure, stress, elastic modulus $F/A$ $[M\,L^{-1}\,T^{-2}]$ Pa
Density $m/V$ $[M\,L^{-3}]$ kg m⁻³
Frequency, angular velocity $1/\text{time}$ $[T^{-1}]$ Hz, rad s⁻¹
Surface tension, spring constant $F/\text{length}$ $[M\,T^{-2}]$ N m⁻¹
Coefficient of viscosity $F/(A \times \text{velocity gradient})$ $[M\,L^{-1}\,T^{-1}]$ Pa s
Gravitational constant G $Fr^2/m^2$ $[M^{-1}\,L^3\,T^{-2}]$ N m² kg⁻²
Angular momentum, Planck constant h $r\,p$, $E/\nu$ $[M\,L^2\,T^{-1}]$ J s

Pause and predict: torque and work both have dimensions $[M\,L^2\,T^{-2}]$. Does that mean torque can be measured in joules?

Check your answer: no. Dimensions tell you the kind of building blocks, not the physical meaning. Work is a scalar and torque is a vector ($\vec{r} \times \vec{F}$), so we write torque in N m and keep the joule for energy. Equal dimensions are a necessary condition for two quantities to be the same thing, never a sufficient one.

Dimensional analysis rests on the principle of homogeneity: you can add or subtract only quantities of the same dimensions, so both sides of a true equation, and every term in it, must have the same dimensions. That gives three uses.

Use How it works Its limit
Check an equation Reduce every term to base dimensions and compare A correct check does not prove the equation is true
Convert units Treat the dimensional formula as a recipe: replace each base unit by its value in the new system Needs the dimensional formula first
Derive a relation Assume a power-law product, match the powers of M, L and T Cannot find pure numbers such as $2\pi$ or $1/2$

Here is how the check works in practice. The equation $v^2 = u^2 + 2ax$ has every term in $[L^2\,T^{-2}]$, so it passes. The equation $v = u + at^2$ fails, because $at^2$ is $[L]$, not $[L\,T^{-1}]$. But $x = ut + at^2$ also passes, even though the true equation has a $1/2$ in front of $at^2$. Dimensions cannot see a pure number. Two more limits: the argument of sin, cos, log and exponential functions must be dimensionless, and an equation with many terms may hold only if each term is homogeneous.

Worked example: converting a unit. Express g = 9.8 m s⁻² in km h⁻².

Step What we do Result
1 Convert the length unit: 1 m = $10^{-3}$ km $9.8 \times 10^{-3}$ km
2 Convert the time unit: 1 s = $1/3600$ h, so 1 s⁻² = $3600^2$ h⁻² $\times 1.296 \times 10^{7}$
3 Multiply $9.8 \times 10^{-3} \times 1.296 \times 10^{7} = 1.27 \times 10^{5}$ km h⁻²

The common wrong step: multiplying by 3600 once instead of squaring it. The time unit appears with power −2, so its conversion factor must appear with power 2 as well.

Worked example: deriving a formula. The time period T of a mass m on a spring of spring constant k depends on m and k. Find the form of T.

Step What we do Result
1 Assume $T = c\,m^a k^b$, where $c$ is a pure number
2 Dimensions: $[T] = [M]^a [M\,T^{-2}]^b$ $[T^1] = [M^{a+b}\,T^{-2b}]$
3 Match powers of M: $a + b = 0$. Match powers of T: $-2b = 1$ $b = -1/2$, $a = 1/2$
4 Assemble $T = c\sqrt{m/k}$

What the method cannot do: tell you that $c = 2\pi$. That number comes from solving the equation of motion (you will do it in Oscillations) or from experiment. The same logic gives the pendulum result $T = c\sqrt{l/g}$, with the mass dropping out because its power comes out as zero.

Beyond the textbook. For the exam: dimensional analysis cannot determine dimensionless constants. In reality: it can still be astonishingly useful. In 1941 the physicist G. I. Taylor reasoned that the radius R of a huge explosion's fireball can depend only on the energy E released, the time t and the air density ρ. Dimensions then force $R \propto (E t^2/\rho)^{1/5}$. A published photograph of the first atomic test, with its time stamp, was enough to estimate its energy, and the result was close to the classified figure. Why it matters: dimensions are a physicist's first sanity check on any new problem.

Exam traps

The trap Why it is tempting The truth
12 300 has 5 significant figures The zeros look like measured digits With no decimal point, trailing zeros do not count: 3 (write $1.2300 \times 10^4$ for 5)
0.0042 has 4 significant figures A zero in front of the decimal looks like a digit Leading zeros never count: 2
A sum follows the "fewest significant figures" rule One rule feels simpler than two Sums and differences follow the fewest decimal places
Errors subtract in a difference or quotient Values subtract, so errors seem to Errors always add (absolute for ±, relative for × and ÷)
Forgetting the power in error propagation The error in r looks like a single number $r^3$ carries three times the percentage error of $r$
Same dimensions means same quantity Work and torque, or momentum and impulse, look alike Equal dimensions are necessary, not sufficient
A dimensionally correct equation is correct The check feels like a proof Pure numbers such as $1/2$ and $2\pi$ are invisible to dimensions
Radian is a base unit It is the SI unit of angle It is a ratio of lengths, so it is dimensionless

Formula sheet

Quantity Formula Unit or form When to use
Plane angle $d\theta = ds/r$ rad Arc length and radius
Solid angle $d\Omega = dA/r^2$ sr Area on a sphere
Mean value $\bar{a} = (a_1 + a_2 + \cdots + a_n)/n$ Same as a Best estimate of repeated readings
Mean absolute error $\Delta\bar{a} = (\sum \lvert a_i - \bar{a} \rvert)/n$ Same as a Spread of repeated readings
Percentage error $(\Delta\bar{a}/\bar{a}) \times 100\ \%$ % Comparing precision
Error in $A \pm B$ $\Delta Z = \Delta A + \Delta B$ Same as a Sums and differences
Error in $A \times B$ or $A/B$ $\Delta Z/Z = \Delta A/A + \Delta B/B$ Fraction Products and quotients
Error in $A^p B^q$ $\Delta Z/Z = p\,\Delta A/A + q\,\Delta B/B$ Fraction Powers
Order of magnitude $N = a \times 10^{b}$, round $a$ at 5 Power of ten Rough comparisons
Dimensional equation $[Q] = [M^a L^b T^c]$ Dimensions Checking and deriving

60-second revision

Topic Lock this in
SI base units m, kg, s, A, K, mol, cd (seven). Radian and steradian are dimensionless
2019 redefinition Units fixed by constants: c, h, caesium frequency, e, k, $N_A$, luminous efficacy
Significant figures Leading zeros no; trailing zeros yes only after a decimal point; unit change does not matter
Sum or difference Fewest decimal places
Product or quotient Fewest significant figures
Rounding a lone 5 Raise the previous digit only if it is odd
Error rules Sum or difference: absolute errors add. Product or quotient: relative errors add. Power: multiply by the power
Same dimensions Work, energy, torque · momentum, impulse · pressure, stress, modulus · frequency, angular velocity · surface tension, spring constant · h, angular momentum
Dimensional analysis Checks, converts, derives. Cannot find $1/2$, $2\pi$ or other pure numbers

Where this chapter connects

  • Next: Motion in a Straight Line uses these units for every kinematics problem, so the unit conversions here (km h⁻¹ to m s⁻¹) come back immediately.
  • Later in Class XI: Oscillations proves the spring and pendulum periods that you derived here up to the constant $2\pi$, and Gravitation gives G, whose dimensions you tabulated above.
  • Class XII link: Dual Nature of Radiation and Matter uses Planck's constant h, whose dimensions equal those of angular momentum.

🎯 Practice MCQs

First 3 questions free · create a free account to unlock the rest — answers & explanations included, no payment needed

Q1. Which of the following is NOT an SI base unit?

▸ Show answer & explanation

Answer: C

The seven SI base units are metre, kilogram, second, ampere, kelvin, mole and candela. The coulomb is derived, since 1 C = 1 A s. The other three options are all base units.

Q2. The numbers 0.0620, $6.20 \times 10^3$ and 6200 have how many significant figures respectively?

▸ Show answer & explanation

Answer: A

In 0.0620 the leading zeros do not count but the trailing zero after the decimal point does, so the digits 6, 2, 0 give 3. In $6.20 \times 10^3$ the digits 6, 2, 0 give 3. In 6200 there is no decimal point, so the trailing zeros do not count and the answer is 2. Options B and C count zeros that the rules exclude, and D drops a trailing zero that is significant.

Q3. The lengths 12.11 m, 18.0 m and 1.013 m are added. The sum, with the correct number of significant figures, is

▸ Show answer & explanation

Answer: C

The exact sum is 31.123 m. The term 18.0 m has the fewest decimal places (one), so the result is rounded to one decimal place: 31.1 m. Options A and B keep too many decimals, and D applies the multiplication rule wrongly.

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